如何将xml传递给C#中的View？

Posted 2023-03-05

【中文标题】如何将xml传递给C#中的View？

【英文标题】：How to pass xml to View in C#?

【发布时间】：2020-11-02 13:02:50

【问题描述】：

它从请求中以字符串形式提供 xml。反序列化后，我无法使用 get 方法从 xml 中获取任何值。同样在Vehicle.cshtml 中，我试图获得DeviceId 的值。它仅将字符串名称 DeviceId 获取到 html 标签。得不到价值。我的方式有什么问题吗？如何从视图中获取这些 xml 值？

DataSet.cs

using System;
using System.Xml.Serialization;

namespace ShippingProject.Models

  //  [System.Xml.Serialization.XmlRootAttribute("DataSet", Namespace = "http://www.arvento.com/", IsNullable = false)]

    [XmlRoot("DataSet")]
    public class DataSet
    
        [XmlElement("Device_x0020_No")]
        public string DeviceId  get; set; 
        [XmlElement("Latitude")]
        public double Latitude  get; set; 
        [XmlElement("Longitude")]
        public double Longitude  get; set; 
        [XmlElement("Address")]
        public string Address  get; set; 
    
 

HomeController.cs

 public IActionResult Vehicle()
        
            // Create web client.
            WebClient client = new WebClient();

            // Download string.
            string value = client.DownloadString("http://ws.arvento.com//v1/report.asmx/GetVehicleStatus?Username=username&PIN1=password&PIN2=password&Language=string");

            // Write values.
            Console.WriteLine("--- WebClient result ---");
            Console.WriteLine(value.Length);
            Console.WriteLine(value);
            XmlSerializer serializer = new XmlSerializer(typeof(List<DataSet>), new XmlRootAttribute("DataSet"));
            //  DataSet result;
            var ms = new MemoryStream(Encoding.UTF8.GetBytes(value));
            var rdr = new XmlTextReader(ms)  Namespaces = false ;
          //  StringReader rdr = new StringReader(value);
          /*  using (TextReader rdr = new StringReader(value))
                  
                      result = (DataSet)serializer.Deserialize(reader);
                   
               StreamReader rdr = new StreamReader(value);*/
            List<DataSet> datasetList = (List<DataSet>)serializer.Deserialize(rdr);
            Console.WriteLine("--- Deserialize result ---");
            Console.WriteLine(datasetList);
            datasetList.ForEach(dl => 
                Console.WriteLine(dl.DeviceId);
                Console.WriteLine(dl.Latitude);
                Console.WriteLine(dl.Longitude);
                Console.WriteLine(dl.Address);
                Console.WriteLine();
            );
            return View();
        

Vehicle.cshtml
@model DataSet
@Html.LabelFor(model => model.DeviceId)

这是我的 xml 文件：

<DataSet xmlns="http://www.arvento.com/">
<xs:schema xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" id="tblVehicleStatus">
<xs:element name="tblVehicleStatus" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
<xs:complexType>
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element name="dtVehicleStatus">
<xs:complexType>
<xs:sequence>
<xs:element name="Device_x0020_No" type="xs:string" minOccurs="0"/>
<xs:element name="GMT_x0020_Date_x002F_Time" type="xs:dateTime" minOccurs="0"/>
<xs:element name="Latitude" type="xs:double" minOccurs="0"/>
<xs:element name="Longitude" type="xs:double" minOccurs="0"/>
<xs:element name="Speed" type="xs:double" minOccurs="0"/>
<xs:element name="Address" type="xs:string" minOccurs="0"/>
<xs:element name="Building_x0020__x002F__x0020_Region" type="xs:string" minOccurs="0"/>
<xs:element name="Height" type="xs:string" minOccurs="0"/>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
<diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
<tblVehicleStatus xmlns="">
<dtVehicleStatus diffgr:id="dtVehicleStatus1" msdata:rowOrder="0" diffgr:hasChanges="inserted">
<Device_x0020_No>805251</Device_x0020_No>
<GMT_x0020_Date_x002F_Time>2020-07-10T06:00:55+03:00</GMT_x0020_Date_x002F_Time>
<Latitude>41.070751</Latitude>
<Longitude>29.000586</Longitude>
<Speed>0</Speed>
<Address>Cemal Sururi Sk., Gülbahar Mh., Şişli, İstanbul, Türkiye</Address>
<Building_x0020__x002F__x0020_Region/>
<Height>205</Height>
</dtVehicleStatus>
<dtVehicleStatus diffgr:id="dtVehicleStatus2" msdata:rowOrder="1" diffgr:hasChanges="inserted">
<Device_x0020_No>805252</Device_x0020_No>
<GMT_x0020_Date_x002F_Time>2020-07-08T13:33:24+03:00</GMT_x0020_Date_x002F_Time>
<Latitude>41.071037</Latitude>
<Longitude>29.00054</Longitude>
<Speed>7.86</Speed>
<Address>Şat Otopark, Çamlı Sk., Gülbahar Mh., Şişli, İstanbul, Türkiye</Address>
<Building_x0020__x002F__x0020_Region/>
<Height>151</Height>
</dtVehicleStatus>
<dtVehicleStatus diffgr:id="dtVehicleStatus3" msdata:rowOrder="2" diffgr:hasChanges="inserted">
<Device_x0020_No>805253</Device_x0020_No>
<GMT_x0020_Date_x002F_Time>2020-07-10T05:31:43+03:00</GMT_x0020_Date_x002F_Time>
<Latitude>41.071087</Latitude>
<Longitude>29.000429</Longitude>
<Speed>6.31</Speed>
<Address>Şat Otopark, Çamlı Sk., Gülbahar Mh., Şişli, İstanbul, Türkiye</Address>
<Building_x0020__x002F__x0020_Region/>
<Height>103</Height>
</dtVehicleStatus>
</tblVehicleStatus>
</diffgr:diffgram>
</DataSet>

【问题讨论】：

您不能序列化必须在根目录 (List) 列出的 xml。除非根是单例，否则 Net 序列化程序将失败。

我应该只用DataSet 替换所有List<DataSet> 吗？

我需要查看 xml 样本才能给出准确的答案。我现在只能说 List 不起作用。

【参考方案1】：

尝试以下：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

namespace ConsoleApplication8

    class Program
    
        const string FILENAME = @"C:\temp\test.xml";
        static void Main(string[] args)
        
            string xml = File.ReadAllText(FILENAME);
            StringReader sReader = new StringReader(xml);
            XmlReader reader = XmlReader.Create(sReader);
            XmlSerializer serializer = new XmlSerializer(typeof(DataSet));
            ConsoleApplication8.DataSet dataset = (ConsoleApplication8.DataSet)serializer.Deserialize(reader);
 
        
    
    public class Diffgram
    
        [XmlArray(ElementName = "tblVehicleStatus", Namespace = "")]
        [XmlArrayItem(ElementName = "dtVehicleStatus", Namespace = "")]
        public List<DtVehicleStatus> DtVehicleStatus  get; set;  
    
    public class DtVehicleStatus
    
            [XmlElement("Device No")]
            public string DeviceId  get; set; 
            [XmlElement("Latitude")]
            public double Latitude  get; set; 
            [XmlElement("Longitude")]
            public double Longitude  get; set; 
            [XmlElement("Address")]
            public string Address  get; set; 
    
    [XmlRoot(ElementName = "DataSet", Namespace = "http://www.arvento.com/")]
    public class DataSet
    
        [XmlElement(ElementName = "diffgram", Namespace = "urn:schemas-microsoft-com:xml-diffgram-v1")]
        public Diffgram Diffgram  get; set; 
    
 

【讨论】：

感谢您的帮助。我将在我的项目中添加此代码。你能写这个吗。当我在 HomeController 中添加它时。命名空间产生问题。

用我的课代替你的课。然后你只需要修改两行来匹配我的代码 1) XmlSerializer serializer = new XmlSerializer(typeof(List), new XmlRootAttribute("DataSet")); 2) List datasetList = (List)serializer.Deserialize(rdr);

我有一些语法错误。我在这里上传了我的代码。你能检查一下吗？ link

我只会使用您的旧代码并删除我的类来代替您的代码。命名空间可能会出现问题。