自定义 Spring Security 应用程序中的无限循环
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【中文标题】自定义 Spring Security 应用程序中的无限循环【英文标题】:Infinite loop in custom Spring Security application 【发布时间】:2015-04-06 17:48:23 【问题描述】:我们尝试用现有的 Spring Security Basic Login 替换开源应用程序中的 REST-API,以实现使用令牌的自定义登录。我阅读了有关该主题的博文:http://javattitude.com/2014/06/07/spring-security-custom-token-based-rest-authentication/
当请求没有名为“Cookie”的标头时,我会得到正确的 401 - 未经授权的响应(预期行为)。当请求具有有效令牌时,我得到一个无限循环,导致java.lang.***Error
:
Exception in thread "http-bio-8080-exec-45" java.lang.***Error
at org.apache.tomcat.util.http.NamesEnumerator.<init>(MimeHeaders.java:402)
at org.apache.tomcat.util.http.MimeHeaders.names(MimeHeaders.java:228)
at org.apache.catalina.connector.Request.getHeaderNames(Request.java:2108)
at org.apache.catalina.connector.RequestFacade.getHeaderNames(RequestFacade.java:726)
at javax.servlet.http.HttpServletRequestWrapper.getHeaderNames(HttpServletRequestWrapper.java:103)
at javax.servlet.http.HttpServletRequestWrapper.getHeaderNames(HttpServletRequestWrapper.java:103)
at javax.servlet.http.HttpServletRequestWrapper.getHeaderNames(HttpServletRequestWrapper.java:103)
at javax.servlet.http.HttpServletRequestWrapper.getHeaderNames(HttpServletRequestWrapper.java:103)
at javax.servlet.http.HttpServletRequestWrapper.getHeaderNames(HttpServletRequestWrapper.java:103)
at javax.servlet.http.HttpServletRequestWrapper.getHeaderNames(HttpServletRequestWrapper.java:103)
at org.activiti.rest.security.CustomTokenAuthenticationFilter.attemptAuthentication(CustomTokenAuthenticationFilter.java:43)
at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.doFilter(AbstractAuthenticationProcessingFilter.java:211)
at org.activiti.rest.security.CustomTokenAuthenticationFilter.doFilter(CustomTokenAuthenticationFilter.java:86)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.security.web.authentication.logout.LogoutFilter.doFilter(LogoutFilter.java:110)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:101)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.security.web.context.SecurityContextPersistenceFilter.doFilter(SecurityContextPersistenceFilter.java:65)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:101)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.security.web.FilterChainProxy.doFilterInternal(FilterChainProxy.java:192)
at org.springframework.security.web.FilterChainProxy.doFilter(FilterChainProxy.java:166)
at org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:344)
at org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:261)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:243)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.ApplicationDispatcher.invoke(ApplicationDispatcher.java:749)
at org.apache.catalina.core.ApplicationDispatcher.processRequest(ApplicationDispatcher.java:487)
at org.apache.catalina.core.ApplicationDispatcher.doForward(ApplicationDispatcher.java:412)
at org.apache.catalina.core.ApplicationDispatcher.forward(ApplicationDispatcher.java:339)
at org.springframework.security.web.firewall.RequestWrapper$FirewalledRequestAwareRequestDispatcher.forward(RequestWrapper.java:132)
at org.activiti.rest.security.TokenSimpleUrlAuthenticationSuccessHandler.onAuthenticationSuccess(TokenSimpleUrlAuthenticationSuccessHandler.java:30)
at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.successfulAuthentication(AbstractAuthenticationProcessingFilter.java:331)
at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.successfulAuthentication(AbstractAuthenticationProcessingFilter.java:298)
at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.doFilter(AbstractAuthenticationProcessingFilter.java:235)
at org.activiti.rest.security.CustomTokenAuthenticationFilter.doFilter(CustomTokenAuthenticationFilter.java:86)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.security.web.authentication.logout.LogoutFilter.doFilter(LogoutFilter.java:110)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:101)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.security.web.context.SecurityContextPersistenceFilter.doFilter(SecurityContextPersistenceFilter.java:65)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:101)
at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
at org.springframework.security.web.FilterChainProxy.doFilterInternal(FilterChainProxy.java:192)
at org.springframework.security.web.FilterChainProxy.doFilter(FilterChainProxy.java:166)
at org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:344)
at org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:261)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:243)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.ApplicationDispatcher.invoke(ApplicationDispatcher.java:749)
at org.apache.catalina.core.ApplicationDispatcher.processRequest(ApplicationDispatcher.java:487)
at org.apache.catalina.core.ApplicationDispatcher.doForward(ApplicationDispatcher.java:412)
at org.apache.catalina.core.ApplicationDispatcher.forward(ApplicationDispatcher.java:339)
at org.springframework.security.web.firewall.RequestWrapper$FirewalledRequestAwareRequestDispatcher.forward(RequestWrapper.java:132)
at org.activiti.rest.security.TokenSimpleUrlAuthenticationSuccessHandler.onAuthenticationSuccess(TokenSimpleUrlAuthenticationSuccessHandler.java:30)
at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.successfulAuthentication(AbstractAuthenticationProcessingFilter.java:331)
at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.successfulAuthentication(AbstractAuthenticationProcessingFilter.java:298)
at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.doFilter(AbstractAuthenticationProcessingFilter.java:235)
at org.activiti.rest.security.CustomTokenAuthenticationFilter.doFilter(CustomTokenAuthenticationFilter.java:86)
我的 Spring 安全配置如下所示:
@Configuration
@EnableWebSecurity
@EnableWebMvcSecurity
public class SecurityConfiguration extends WebSecurityConfigurerAdapter
@Bean
public AuthenticationProvider authenticationProvider()
return new BasicAuthenticationProvider();
@Autowired
AuthenticationProvider basicAuthenticationProvider;
@Bean
public CustomTokenAuthenticationFilter customTokenAuthenticationFilter()
System.out.println("+++ create new CustomTokenAuthenticationFilter for path=/**");
return new CustomTokenAuthenticationFilter("/**");
;
@Autowired
CustomTokenAuthenticationFilter customTokenAuthenticationFilter;
@Override
protected void configure(HttpSecurity http) throws Exception
System.out.println("init of http security START");
http
.authenticationProvider(authenticationProvider())
.sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS).and()
.csrf().disable()
.authorizeRequests()
.anyRequest().authenticated()
.and()//.authenticationProvider(basicAuthenticationProvider);
.addFilterBefore(customTokenAuthenticationFilter, BasicAuthenticationFilter.class)
.httpBasic();
//.and().addFilter(filter);
System.out.println("init of http security DONE");
我已经尝试将 URL 映射从 /**
更改为 /activiti-rest/**
,但随后,基本身份验证再次启动。
这是我的自定义令牌身份验证过滤器:
public class CustomTokenAuthenticationFilter extends AbstractAuthenticationProcessingFilter
private static final Logger logger = LoggerFactory.getLogger(CustomTokenAuthenticationFilter.class);
public CustomTokenAuthenticationFilter(String defaultFilterProcessesUrl)
super(defaultFilterProcessesUrl);
super.setRequiresAuthenticationRequestMatcher(new AntPathRequestMatcher(defaultFilterProcessesUrl));
setAuthenticationManager(new NoOpAuthenticationManager());
setAuthenticationSuccessHandler(new TokenSimpleUrlAuthenticationSuccessHandler());
public final String HEADER_SECURITY_TOKEN = "Cookie";//"LdapToken";
/**
* Attempt to authenticate request - basically just pass over to another method to authenticate request headers
*/
@Override public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response) throws AuthenticationException, IOException, ServletException
Enumeration<String> headerNames = request.getHeaderNames();
int i = 0;
while (headerNames.hasMoreElements())
String key = (String) headerNames.nextElement();
String value = request.getHeader(key);
System.out.println("+++ key["+i+"]" +key);
System.out.println("+++ val["+i+"]" +value);
i++;
String token = request.getHeader(HEADER_SECURITY_TOKEN);
logger.info("token found:"+token);
System.out.println("+++ token found:"+token);
AbstractAuthenticationToken userAuthenticationToken = authUserByToken(token);
if(userAuthenticationToken == null) throw new AuthenticationServiceException(MessageFormat.format("Error | 0", "Bad Token"));
System.out.println("+++ userAuthenticationToken:"+userAuthenticationToken.toString());
return userAuthenticationToken;
/**
* authenticate the user based on token
* @return
*/
private AbstractAuthenticationToken authUserByToken(String token)
if(token==null)
System.out.println("+++ i shouldn't be null +++");
return null;
AbstractAuthenticationToken authToken = new JWTAuthenticationToken(token);
try
return authToken;
catch (Exception e)
System.out.println(e);
logger.error("Authenticate user by token error: ", e);
return authToken;
@Override
public void doFilter(ServletRequest req, ServletResponse res,
FilterChain chain) throws IOException, ServletException
System.out.println("++++++++++++++++++++++++++++++ doFilter ");
super.doFilter(req, res, chain);
还有我的自定义成功处理程序。我认为这会导致无限循环,但我不知道为什么:
public class TokenSimpleUrlAuthenticationSuccessHandler extends SimpleUrlAuthenticationSuccessHandler
@Override
protected String determineTargetUrl(HttpServletRequest request,
HttpServletResponse response)
System.out.println("+++ yuhuuu determineTargetUrl+++");
String context = request.getContextPath();
String fullURL = request.getRequestURI();
String url = fullURL.substring(fullURL.indexOf(context)+context.length());
return url;
@Override
public void onAuthenticationSuccess(HttpServletRequest request,
HttpServletResponse response, Authentication authentication)
throws IOException, ServletException
System.out.println("+++ yuhuuu onAuthenticationSuccess+++");
String url = determineTargetUrl(request,response);
request.getRequestDispatcher(url).forward(request, response);
所有其他类(NoOpAuthenticationManager 和 RestAuthenticationEntryPoint)与这篇博文中的完全一样。
如果有人可以给我一个提示,可能会导致这个无限循环,那就太好了。正如我所说,它仅在请求具有有效令牌时发生。
感谢和最好的问候 本
【问题讨论】:
如果删除打印标题的代码会发生什么? 我认为问题在于 URL 匹配。我使用 /** 作为 URL 模式。例如,我调用 REST-URL localhost:8080/activiti-rest/service。我的 CustomFilter 被调用,因为它匹配 /**。 request.getRequestDispatcher(url).forward(request, response);在这种情况下 /service 具有作为 url 参数,它也与 URL 模式匹配。所以我的 CustomAuthenticationFilter 再次被调用。循环发生。但我不知道如何解决这个问题,因为所有 REST-URL 都应该受到保护。 如果您愿意探索另一种方法,您可以查看this app,它取消了自定义过滤器并利用核心 Spring Security 基础设施来保护 REST API 端点。 【参考方案1】:您的编码方法是有效的。但是,我可以为您提供一种略有不同但可行的方法。在我开始解释解决方案之前,这里是代码:
WebSecurityConfig.java
@Configuration
@EnableWebMvcSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter
@Override
protected void configure(HttpSecurity http) throws Exception
http.authorizeRequests().
antMatchers("/restapi").hasRole("USER")
.and().addFilterBefore(new SsoTokenAuthenticationFilter(authenticationManager()), BasicAuthenticationFilter.class).httpBasic()
.and().authorizeRequests().antMatchers("/**").permitAll().anyRequest().authenticated();
@Override
protected void configure(AuthenticationManagerBuilder auth)
throws Exception
// The order is important! During runtime Spring Security tries to find Provider-Implementations that
// match the UsernamePasswordAuthenticationToken (which will be created later..). We must make sure
// that daoAuthenticationProvider matches first. Why? Hard to explain, I figured it out with the debugger.
auth.authenticationProvider(daoAuthenticationProvider());
auth.authenticationProvider(tokenAuthenticationProvider());
@Bean
public AuthenticationProvider tokenAuthenticationProvider()
return new SsoTokenAuthenticationProvider();
@Bean
public AuthenticationProvider daoAuthenticationProvider()
// DaoAuthenticationProvider requires a userDetailsService object to be attached.
// So we build one. This replaces the AuthenticationConfiguration, which is commented out below
// Build the userDetailsService
User userThatMustMatch = new User("michael", "password", AuthorityUtils.commaSeparatedStringToAuthorityList("ROLE_USER,ROLE_RESTUSER"));
Collection<UserDetails> users = new ArrayList<>();
users.add(userThatMustMatch);
InMemoryUserDetailsManager userDetailsService = new InMemoryUserDetailsManager(users);
// Create the DaoAuthenticationProvider that will handle all HTTP BASIC AUTH requests
DaoAuthenticationProvider daoAuthProvider = new DaoAuthenticationProvider();
daoAuthProvider.setUserDetailsService(userDetailsService);
return daoAuthProvider;
SsoTokenAuthenticationFilter.java
public class SsoTokenAuthenticationFilter extends GenericFilterBean
public final String HEADER_SECURITY_COOKIE = "LdapToken";
private AuthenticationManager authenticationManager;
private AuthenticationDetailsSource<HttpServletRequest,?> ssoTokenAuthenticationDetailsSource = new SsoTokenWebAuthenticationDetailsSource();
public SsoTokenAuthenticationFilter(AuthenticationManager authenticationManager)
this.authenticationManager = authenticationManager;
@Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException
HttpServletRequest httpRequest = (HttpServletRequest) request;
HttpServletResponse httpResponse = (HttpServletResponse) response;
// check if SSO token is available. If not, pass down to next filter in chain
try
Cookie[] cookies = httpRequest.getCookies();
if (cookies == null)
chain.doFilter(request, response);
return;
Cookie ssoCookie = null;
for (int i = 0; i < cookies.length; i++)
if (cookies[i].getName().equals("ssoToken"))
ssoCookie = cookies[i];
if (ssoCookie == null)
chain.doFilter(request, response);
return;
// SSO token found, now authenticate and afterwards pass down to next filter in chain
authenticateWithSsoToken(httpRequest);
logger.debug("now the AuthenticationFilter passes down to next filter in chain");
chain.doFilter(request, response);
catch (InternalAuthenticationServiceException internalAuthenticationServiceException)
SecurityContextHolder.clearContext();
logger.error("Internal authentication service exception", internalAuthenticationServiceException);
httpResponse.sendError(HttpServletResponse.SC_INTERNAL_SERVER_ERROR);
catch (AuthenticationException authenticationException)
SecurityContextHolder.clearContext();
logger.debug("No or invalid SSO token");
httpResponse.sendError(HttpServletResponse.SC_UNAUTHORIZED, authenticationException.getMessage());
private void authenticateWithSsoToken(HttpServletRequest request) throws IOException
System.out.println("+++ authenticateWithSSOToken +++");
UsernamePasswordAuthenticationToken authRequest = new UsernamePasswordAuthenticationToken(null, null, AuthorityUtils.commaSeparatedStringToAuthorityList("ROLE_USER,ROLE_RESTUSER"));
authRequest.setDetails(ssoTokenAuthenticationDetailsSource.buildDetails(request));
// Delegate authentication to SsoTokenAuthenticationProvider, he will call the SsoTokenAuthenticationProvider <-- because of the configuration in WebSecurityConfig.java
Authentication authResult = authenticationManager.authenticate(authRequest);
SsoTokenAuthenticationProvider.java
public class SsoTokenAuthenticationProvider implements AuthenticationProvider
public SsoTokenAuthenticationProvider()
@Override
public Authentication authenticate(Authentication authentication) throws AuthenticationException
SsoTokenWebAuthenticationDetails ssoTokenWebAuthenticationDetails = null;
WebAuthenticationDetails webWebAuthenticationDetails = (WebAuthenticationDetails)authentication.getDetails();
if (! (webWebAuthenticationDetails instanceof SsoTokenWebAuthenticationDetails))
// ++++++++++++++++++++++++
// BASIC authentication....
// ++++++++++++++++++++++++
UsernamePasswordAuthenticationToken emptyToken = new UsernamePasswordAuthenticationToken(null, null);
emptyToken.setDetails(null);
return emptyToken; //return null works, too.
// ++++++++++++++++++++++++
// LDAP authentication....
// ++++++++++++++++++++++++
ssoTokenWebAuthenticationDetails = (SsoTokenWebAuthenticationDetails)webWebAuthenticationDetails;
Cookie ssoTokenCookie = ssoTokenWebAuthenticationDetails.getSsoTokenCookie();
// check if SSO cookie is available
if (ssoTokenCookie == null)
return new UsernamePasswordAuthenticationToken(null, null); //do basic auth.
String username = ssoTokenCookie.getValue();
// Do your SSO token authentication here
if (! username.equals("michael"))
return new UsernamePasswordAuthenticationToken(null, null); //do basic auth.
// Create new Authentication object. Name and password can be null (but you can set the values of course).
// Be careful with your role names!
// In WebSecurityConfig the role "USER" is automatically prefixed with String "ROLE_", so it is "ROLE_USER" in the end.
UsernamePasswordAuthenticationToken authRequest = new UsernamePasswordAuthenticationToken(null, null, AuthorityUtils.commaSeparatedStringToAuthorityList("ROLE_USER,ROLE_RESTUSER"));
authRequest.setDetails(ssoTokenWebAuthenticationDetails);
// Don't let spring decide.. you already have made the right decisions. Tell spring you have an authenticated user.
// vielleicht ist dieses obere Kommentar auch bullshit... ich lese das morgen noch mal nach...
SecurityContextHolder.getContext().setAuthentication(authentication);
return authentication;
@Override
public boolean supports(Class<?> authentication)
return authentication.equals(UsernamePasswordAuthenticationToken.class);
SsoTokenWebAuthenticationDetailsSource.java
public class SsoTokenWebAuthenticationDetailsSource extends
WebAuthenticationDetailsSource
@Override
public WebAuthenticationDetails buildDetails(HttpServletRequest context)
return new SsoTokenWebAuthenticationDetails(context);
SsoTokenWebAuthenticationDetails.java
public class SsoTokenWebAuthenticationDetails extends WebAuthenticationDetails
private static final long serialVersionUID = 1234567890L;
private Cookie ssoTokenCookie;
public SsoTokenWebAuthenticationDetails(HttpServletRequest request)
super(request);
// Fetch cookie from request
Cookie[] cookies = request.getCookies();
Cookie ssoTokenCookie = null;
for (int i = 0; i < cookies.length; i++)
if (cookies[i].getName().equals("SSOToken"))
ssoTokenCookie= cookies[i];
this.setSsoTokenCookie(ssoTokenCookie);
public Cookie getSsoTokenCookie()
return ssoTokenCookie;
public void setSsoTokenCookie(Cookie ssoTokenCookie)
this.ssoTokenCookie = ssoTokenCookie;
我用一句话描述解决方案:
-
Config 类保护任何具有
ROLE_USER
角色的/restapi
控制器。可以使用 httpBasic 身份验证来完成身份验证,但在此之前您可以尝试基本身份验证。您必须尝试通过 ssoTokenCookie(如果可用)对用户进行身份验证。因此,您在基本身份验证之前将SsoTokenAuthenticationFilter
设置为过滤器。已应用。
在过滤器中,您检查请求中是否有可用的 ssoTokenCookie。
如果是,则将身份验证委托给标准 spring AuthenticationManager
。 AuthenticationManager
知道您自己的 SsoTokenAuthenticationProvider
实现并将身份验证委托给它。在这里,提供 cookie 信息很重要。这可以通过使用自定义的WebAuthenticationDetails
来完成。
如果不是,则将工作传递给链中的下一个过滤器。毫不奇怪,标准的BasicAuthenticationFilter
将被调用。因为您告诉 Spring 在WebSecurityConfig.java
中使用标准daoAuthenticationProvider
,所以当在基本身份验证中输入正确的凭据时,Spring 可以对用户进行身份验证。对话框
【讨论】:
非常感谢。工作得很好。此外,我用以下部分修复了我的代码: static final String FILTER_APPLIED = "__spring_security_scpf_applied"; if (req.getAttribute(FILTER_APPLIED) != null) chain.doFilter(req, res);返回; req.setAttribute(FILTER_APPLIED, Boolean.TRUE);这样,我的递归就消失了。以上是关于自定义 Spring Security 应用程序中的无限循环的主要内容,如果未能解决你的问题,请参考以下文章
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