在查询的输出上应用 DENSE_RANK()
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【中文标题】在查询的输出上应用 DENSE_RANK()【英文标题】:To apply DENSE_RANK() on the output of an query 【发布时间】:2016-11-23 07:23:21 【问题描述】:我有三个表,分别命名为 Groups、GroupMembers 和 DailyTable。以下是我的每个模型:
models.py
class Group(models.Model):
name = models.CharField(max_length=255, blank=False, null=False)
group_type = models.ForeignKey('GroupType',blank=True,default=False)
class Meta:
db_table = 'groups'
class GroupMembers(models.Model):
group = models.ForeignKey('Group')
user = models.ForeignKey('User')
status = models.CharField(max_length=20)
class Meta:
db_table = 'group_members'
unique_together = ['group', 'user']
class DailyTable(models.Model):
class Meta:
managed = True
db_table = 'dailytable'
user_id = models.IntegerField(db_index=True)
calories = models.FloatField()
date = models.DateField()
我想单独计算每组燃烧的总卡路里。所以我启动了以下查询:
select groups.id,groups.name as group_display_name,
(select count(*) from group_members where group_id = groups.id and status = 'accepted' and groups.group_type_id = 1) as total_members,
(select sum(calories) from dailytable where user_id in (select user_id from group_members where group_id = groups.id and groups.group_type_id = 1) and dailytable.date='2016-02-02') as total_calories,
(select case when exists(select * from group_members where group_id = groups.id and user_id = 3 and status = 'accepted' and groups.group_type_id = 1) then cast(1 as bit) else cast(0 as bit) end) as is_member_of_group
from groups
where groups.group_type_id = 1
order by total_calories desc
nulls last;
下面是我得到的输出 现在我想根据我燃烧的总卡路里对组进行排名,所以我在查询中进行了以下更改:
....
dense_rank() over(order by total_calories)
from groups
....
错误:列“total_calories”不存在
我想将 RANK 应用于查询的输出。有什么办法可以做到这一点。
【问题讨论】:
【参考方案1】:包围查询并计算外部选择中的排名。
在下面的示例中,查询使用联接和 group by 而不是子查询来计算总数。
select
q.*,
DENSE_RANK() over (order by total_calories) as total_calories_rank
from
(
select
g.id as group_id,
g.name as group_name,
count(distinct m.user_id) as total_members,
sum(d.calories) as total_calories,
cast(max(case when m.user_id = 3 then 1 else 0 end) as bit) as user_3_is_member_of_group
from groups g
inner join group_members m on (g.id = m.group_id and m.status = 'accepted')
left join (
select user_id, sum(calories) as calories
from dailytable
where date = '2016-02-02'
group by user_id
) d on (m.user_id = d.user_id)
where g.group_type_id = 1
group by g.id, g.name
) q
order by total_calories desc
nulls last;
【讨论】:
【参考方案2】:这是因为您正在尝试在 dense_rank() 中使用派生列别名,这在此处不可用。在 CTE 中包装查询并对其应用 dense_rank():
WITH baseQuery AS (
SELECT
groups.id,
groups.name AS group_display_name,
(
SELECT
count(*)
FROM group_members
WHERE
group_id = groups.id AND status = 'accepted' AND groups.group_type_id = 1) AS total_members,
(
SELECT
sum(calories)
FROM dailytable
WHERE
user_id IN (
SELECT
user_id
FROM group_members
WHERE
group_id = groups.id
AND groups.group_type_id = 1
) AND dailytable.date = '2016-02-02'
) AS total_calories,
(
SELECT
CASE WHEN exists(SELECT
*
FROM group_members
WHERE
group_id = groups.id
AND user_id = 3
AND status = 'accepted'
AND groups.group_type_id = 1)
THEN cast(1 AS BIT)
ELSE cast(0 AS BIT) END) AS is_member_of_group
FROM groups
WHERE
groups.group_type_id = 1
)
select * ,
dense_rank() over(order by total_calories)
from baseQuery
ORDER BY total_calories DESC
NULLS LAST
【讨论】:
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