快捷方式代码（根据数量隐藏视图）

Posted 2023-02-26

【中文标题】快捷方式代码（根据数量隐藏视图）

【英文标题】：Shortcut the code (hide views based on count of number)

【发布时间】：2017-02-21 06:35:14

【问题描述】：

下面最好的代码是什么，代码运行良好，没有问题，只是找到了更好的代码编写方式，有 11 个视图和用户数，所以我需要隐藏视图基于 11 个可用的用户假设我们有 11 个用户并且只有 2 个可用，所以它将是 11 个中的 2 个。应用程序将隐藏第一个视图和第二个视图，但不会隐藏从 3 到 11 的视图，依此类推

    NSInteger countOfViews = 2;
    if (countOfViews == 1) 
        UIView *viewtag1 = (UIView *)[self.leftScrollView viewWithTag:1000];
        UIView *viewtag2 = (UIView *)[self.leftScrollView viewWithTag:2000];
        UIView *viewtag3 = (UIView *)[self.leftScrollView viewWithTag:3000];
        UIView *viewtag4 = (UIView *)[self.leftScrollView viewWithTag:4000];
        UIView *viewtag5 = (UIView *)[self.leftScrollView viewWithTag:5000];
        UIView *viewtag6 = (UIView *)[self.leftScrollView viewWithTag:6000];
        UIView *viewtag7 = (UIView *)[self.leftScrollView viewWithTag:7000];
        UIView *viewtag8 = (UIView *)[self.leftScrollView viewWithTag:8000];
        UIView *viewtag9 = (UIView *)[self.leftScrollView viewWithTag:9000];
        UIView *viewtag10 = (UIView *)[self.leftScrollView viewWithTag:10000];
        UIView *viewtag11 = (UIView *)[self.leftScrollView viewWithTag:11000];

        viewtag1.hidden = YES;
        viewtag2.hidden = NO;
        viewtag3.hidden = NO;
        viewtag4.hidden = NO;
        viewtag5.hidden = NO;
        viewtag6.hidden = NO;
        viewtag7.hidden = NO;
        viewtag8.hidden = NO;
        viewtag9.hidden = NO;
        viewtag10.hidden = NO;
        viewtag11.hidden = NO;
    


 if (countOfViews == 2) 
        UIView *viewtag1 = (UIView *)[self.leftScrollView viewWithTag:1000];
        UIView *viewtag2 = (UIView *)[self.leftScrollView viewWithTag:2000];
        UIView *viewtag3 = (UIView *)[self.leftScrollView viewWithTag:3000];
        UIView *viewtag4 = (UIView *)[self.leftScrollView viewWithTag:4000];
        UIView *viewtag5 = (UIView *)[self.leftScrollView viewWithTag:5000];
        UIView *viewtag6 = (UIView *)[self.leftScrollView viewWithTag:6000];
        UIView *viewtag7 = (UIView *)[self.leftScrollView viewWithTag:7000];
        UIView *viewtag8 = (UIView *)[self.leftScrollView viewWithTag:8000];
        UIView *viewtag9 = (UIView *)[self.leftScrollView viewWithTag:9000];
        UIView *viewtag10 = (UIView *)[self.leftScrollView viewWithTag:10000];
        UIView *viewtag11 = (UIView *)[self.leftScrollView viewWithTag:11000];

        viewtag1.hidden = YES;
        viewtag2.hidden = YES;
        viewtag3.hidden = NO;
        viewtag4.hidden = NO;
        viewtag5.hidden = NO;
        viewtag6.hidden = NO;
        viewtag7.hidden = NO;
        viewtag8.hidden = NO;
        viewtag9.hidden = NO;
        viewtag10.hidden = NO;
        viewtag11.hidden = NO;
    

/*
till if (countOfViews == 11)
*/

【问题讨论】：

您可以使用Outlet collection 来创建网点阵列，这样会更干净

【参考方案1】：

    NSInteger countOfViews = 2;
    for (int i = 1; i <= 11; i++) 
            UIView *view = (UIView *)[self.leftScrollView viewWithTag:i * 1000];
            view.hidden = (i <= countOfViews);
    

【讨论】：

干净整洁 +1

聪明。非常感谢 +1