将整数转换为书面数字
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【中文标题】将整数转换为书面数字【英文标题】：Convert integers to written numbers 【发布时间】：2010-09-05 09:59:54 【问题描述】：有没有一种有效的方法可以将整数转换成书面数字，例如：
string Written = IntegerToWritten(21);
将返回“二十一”。
有没有不涉及大量查找表的方法？
【问题讨论】：
我希望21 返回 twenty-one，而不是 twenty one。连字符很重要：three thousand four hundred and seventy-six.
这是我采用的方法：blackbeltcoder.com/Articles/strings/converting-numbers-to-words
任何做这种事情的人都应该意识到它的本地化很差。
【参考方案1】：
为什么要使用海量查找表？
string GetWrittenInteger(int n)
string[] a = new string[] "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"
string[] b = new string[] "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"
string[] c = new string[] "Twenty", "Thirty", "Forty", "Sixty", "Seventy", "Eighty", "Ninety";
string[] d = new string[] "Hundred", "Thousand", "Million"
string s = n.ToString();
for (int i = 0; i < s.Length; i++)
// logic (too lazy but you get the idea)
【讨论】：
【参考方案2】：我使用此代码。它是 VB 代码，但您可以轻松地将其转换为 C#。有效
Function NumberToText(ByVal n As Integer) As String
Select Case n
Case 0
Return ""
Case 1 To 19
Dim arr() As String = "One","Two","Three","Four","Five","Six","Seven", _
"Eight","Nine","Ten","Eleven","Twelve","Thirteen","Fourteen", _
"Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"
Return arr(n-1) & " "
Case 20 to 99
Dim arr() as String = "Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"
Return arr(n\10 -2) & " " & NumberToText(n Mod 10)
Case 100 to 199
Return "One Hundred " & NumberToText(n Mod 100)
Case 200 to 999
Return NumberToText(n\100) & "Hundreds " & NumberToText(n mod 100)
Case 1000 to 1999
Return "One Thousand " & NumberToText(n Mod 1000)
Case 2000 to 999999
Return NumberToText(n\1000) & "Thousands " & NumberToText(n Mod 1000)
Case 1000000 to 1999999
Return "One Million " & NumberToText(n Mod 1000000)
Case 1000000 to 999999999
Return NumberToText(n\1000000) & "Millions " & NumberToText(n Mod 1000000)
Case 1000000000 to 1999999999
Return "One Billion " & NumberTotext(n Mod 1000000000)
Case Else
Return NumberToText(n\1000000000) & "Billion " _
& NumberToText(n mod 1000000000)
End Select
End Function
这是c#中的代码
public static string AmountInWords(double amount)
var n = (int)amount;
if (n == 0)
return "";
else if (n > 0 && n <= 19)
var arr = new string[] "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" ;
return arr[n - 1] + " ";
else if (n >= 20 && n <= 99)
var arr = new string[] "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" ;
return arr[n / 10 - 2] + " " + AmountInWords(n % 10);
else if (n >= 100 && n <= 199)
return "One Hundred " + AmountInWords(n % 100);
else if (n >= 200 && n <= 999)
return AmountInWords(n / 100) + "Hundred " + AmountInWords(n % 100);
else if (n >= 1000 && n <= 1999)
return "One Thousand " + AmountInWords(n % 1000);
else if (n >= 2000 && n <= 999999)
return AmountInWords(n / 1000) + "Thousand " + AmountInWords(n % 1000);
else if (n >= 1000000 && n <= 1999999)
return "One Million " + AmountInWords(n % 1000000);
else if (n >= 1000000 && n <= 999999999)
return AmountInWords(n / 1000000) + "Million " + AmountInWords(n % 1000000);
else if (n >= 1000000000 && n <= 1999999999)
return "One Billion " + AmountInWords(n % 1000000000);
else
return AmountInWords(n / 1000000000) + "Billion " + AmountInWords(n % 1000000000);
【讨论】：
【参考方案3】：这应该可以很好地工作：
public static class HumanFriendlyInteger
static string[] ones = new string[] "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" ;
static string[] teens = new string[] "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" ;
static string[] tens = new string[] "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" ;
static string[] thousandsGroups = "", " Thousand", " Million", " Billion" ;
private static string FriendlyInteger(int n, string leftDigits, int thousands)
if (n == 0)
return leftDigits;
string friendlyInt = leftDigits;
if (friendlyInt.Length > 0)
friendlyInt += " ";
if (n < 10)
friendlyInt += ones[n];
else if (n < 20)
friendlyInt += teens[n - 10];
else if (n < 100)
friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
else if (n < 1000)
friendlyInt += FriendlyInteger(n % 100, (ones[n / 100] + " Hundred"), 0);
else
friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands+1), 0);
if (n % 1000 == 0)
return friendlyInt;
return friendlyInt + thousandsGroups[thousands];
public static string IntegerToWritten(int n)
if (n == 0)
return "Zero";
else if (n < 0)
return "Negative " + IntegerToWritten(-n);
return FriendlyInteger(n, "", 0);
（已编辑以修复百万、十亿等的错误）
【讨论】：
我想看国际化版本。 有趣的是要注意上述（美国英语）和英国英语等效项之间有多少细微差别，更不用说其他语言了...... :-) 我必须在每次递归调用后插入一个 return 才能使 1000000 一百万起作用。此代码产生一百万。【参考方案4】：using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace tryingstartfror4digits
class Program
static void Main(string[] args)
Program pg = new Program();
Console.WriteLine("Enter ur number");
int num = Convert.ToInt32(Console.ReadLine());
if (num <= 19)
string g = pg.first(num);
Console.WriteLine("The number is " + g);
else if ((num >= 20) && (num <= 99))
if (num % 10 == 0)
string g = pg.second(num / 10);
Console.WriteLine("The number is " + g);
else
string g = pg.second(num / 10) + pg.first(num % 10);
Console.WriteLine("The number is " + g);
else if ((num >= 100) && (num <= 999))
int k = num % 100;
string g = pg.first(num / 100) +pg.third(0) + pg.second(k / 10)+pg.first(k%10);
Console.WriteLine("The number is " + g);
else if ((num >= 1000) && (num <= 19999))
int h = num % 1000;
int k = h % 100;
string g = pg.first(num / 1000) + "Thousand " + pg.first(h/ 100) + pg.third(k) + pg.second(k / 10) + pg.first(k % 10);
Console.WriteLine("The number is " + g);
Console.ReadLine();
public string first(int num)
string name;
if (num == 0)
name = " ";
else
string[] arr1 = new string[] "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" , "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen";
name = arr1[num - 1];
return name;
public string second(int num)
string name;
if ((num == 0)||(num==1))
name = " ";
else
string[] arr1 = new string[] "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" ;
name = arr1[num - 2];
return name;
public string third(int num)
string name ;
if (num == 0)
name = "";
else
string[] arr1 = new string[] "Hundred" ;
name = arr1[0];
return name;
从 1 到 19999 工作正常，我完成后会很快更新
【讨论】：
【参考方案5】：这是一个C# Console Application，它将返回整数和小数。
【讨论】：
【参考方案6】：仅用于类 HumanFriendlyInteger (↑) 的土耳其语代表（土耳其语，sayı yazı karşılığı）：
public static class HumanFriendlyInteger
static string[] ones = new string[] "", "Bir", "İki", "Üç", "Dört", "Beş", "Altı", "Yedi", "Sekiz", "Dokuz" ;
static string[] teens = new string[] "On", "On Bir", "On İki", "On Üç", "On Dört", "On Beş", "On Altı", "On Yedi", "On Sekiz", "On Dokuz" ;
static string[] tens = new string[] "Yirmi", "Otuz", "Kırk", "Elli", "Altmış", "Yetmiş", "Seksen", "Doksan" ;
static string[] thousandsGroups = "", " Bin", " Milyon", " Milyar" ;
private static string FriendlyInteger(int n, string leftDigits, int thousands)
if (n == 0)
return leftDigits;
string friendlyInt = leftDigits;
if (friendlyInt.Length > 0)
friendlyInt += " ";
if (n < 10)
friendlyInt += ones[n];
else if (n < 20)
friendlyInt += teens[n - 10];
else if (n < 100)
friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
else if (n < 1000)
friendlyInt += FriendlyInteger(n % 100, ((n / 100 == 1 ? "" : ones[n / 100] + " ") + "Yüz"), 0); // Yüz 1 ile başlangıçta "Bir" kelimesini Türkçe'de almaz.
else
friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands + 1), 0);
return friendlyInt + thousandsGroups[thousands];
public static string IntegerToWritten(int n)
if (n == 0)
return "Sıfır";
else if (n < 0)
return "Eksi " + IntegerToWritten(-n);
return FriendlyInteger(n, "", 0);
【讨论】：
Türkçede onluklar için özel bir durum olmadığındanteens kullanımına gerek kalmıyor。 else if (n < 20) kontrolü tamamen kaldırılır, tens içine "On" eklenir ve 100 kontrolündeki tens[n / 10 - 2] , teens[n / 10 - 1] şeklinde güncellenirse daha sade bir şekilde sonuç üretec
【参考方案7】：
接受的答案似乎并不完美。它不处理像二十一这样的数字中的破折号，它不把“和”这个词放在像“一百零一”这样的数字中，而且，它是递归的。
这是我的答案。它智能地添加“和”字，并适当地连字符数字。如果需要任何修改，请告诉我。
这是如何调用它（显然你会想把它放在某个类中）：
for (int i = int.MinValue+1; i < int.MaxValue; i++)
Console.WriteLine(ToWords(i));
代码如下：
private static readonly string[] Ones = "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine";
private static readonly string[] Teens =
"Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
"Seventeen", "Eighteen", "Nineteen"
;
private static readonly string[] Tens =
"", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty",
"Ninety"
;
public static string ToWords(int number)
if (number == 0)
return "Zero";
var wordsList = new List<string>();
if (number < 0)
wordsList.Add("Negative");
number = Math.Abs(number);
if (number >= 1000000000 && number <= int.MaxValue) //billions
int billionsValue = number / 1000000000;
GetValuesUnder1000(billionsValue, wordsList);
wordsList.Add("Billion");
number -= billionsValue * 1000000000;
if (number > 0 && number < 10)
wordsList.Add("and");
if (number >= 1000000 && number < 1000000000) //millions
int millionsValue = number / 1000000;
GetValuesUnder1000(millionsValue, wordsList);
wordsList.Add("Million");
number -= millionsValue * 1000000;
if (number > 0 && number < 10)
wordsList.Add("and");
if (number >= 1000 && number < 1000000) //thousands
int thousandsValue = number/1000;
GetValuesUnder1000(thousandsValue, wordsList);
wordsList.Add("Thousand");
number -= thousandsValue * 1000;
if (number > 0 && number < 10)
wordsList.Add("and");
GetValuesUnder1000(number, wordsList);
return string.Join(" ", wordsList);
private static void GetValuesUnder1000(int number, List<string> wordsList)
while (number != 0)
if (number < 10)
wordsList.Add(Ones[number]);
number -= number;
else if (number < 20)
wordsList.Add(Teens[number - 10]);
number -= number;
else if (number < 100)
int tensValue = ((int) (number/10))*10;
int onesValue = number - tensValue;
if (onesValue == 0)
wordsList.Add(Tens[tensValue/10]);
else
wordsList.Add(Tens[tensValue/10] + "-" + Ones[onesValue]);
number -= tensValue;
number -= onesValue;
else if (number < 1000)
int hundredsValue = ((int) (number/100))*100;
wordsList.Add(Ones[hundredsValue/100]);
wordsList.Add("Hundred");
number -= hundredsValue;
if (number > 0)
wordsList.Add("and");
【讨论】：
【参考方案8】：只需获取该字符串并使用 就像 字符串 s=txtNumber.Text.Tostring(); int i=Convert.ToInt32(s.Tostring()); 它只会写入完整的整数值
【讨论】：
【参考方案9】：Nick Masao 对孟加拉数字相同问题的回答的扩展。数字的初始输入是 Unicode 字符串。干杯！！
string number = "২২৮৯";
number = number.Replace("০", "0").Replace("১", "1").Replace("২", "2").Replace("৩", "3").Replace("৪", "4").Replace("৫", "5").Replace("৬", "6").Replace("৭", "7").Replace("৮", "8").Replace("৯", "9");
double vtempdbl = Convert.ToDouble(number);
string amount = AmountInWords(vtempdbl);
private static string AmountInWords(double amount)
var n = (int)amount;
if (n == 0)
return " ";
else if (n > 0 && n <= 99)
var arr = new string[] "এক", "দুই", "তিন", "চার", "পাঁচ", "ছয়", "সাত", "আট", "নয়", "দশ", "এগার", "বারো", "তের", "চৌদ্দ", "পনের", "ষোল", "সতের", "আঠার", "ঊনিশ", "বিশ", "একুশ", "বাইস", "তেইশ", "চব্বিশ", "পঁচিশ", "ছাব্বিশ", "সাতাশ", "আঠাশ", "ঊনত্রিশ", "ত্রিশ", "একত্রিস", "বত্রিশ", "তেত্রিশ", "চৌত্রিশ", "পঁয়ত্রিশ", "ছত্রিশ", "সাঁইত্রিশ", "আটত্রিশ", "ঊনচল্লিশ", "চল্লিশ", "একচল্লিশ", "বিয়াল্লিশ", "তেতাল্লিশ", "চুয়াল্লিশ", "পয়তাল্লিশ", "ছিচল্লিশ", "সাতচল্লিশ", "আতচল্লিশ", "উনপঞ্চাশ", "পঞ্চাশ", "একান্ন", "বায়ান্ন", "তিপ্পান্ন", "চুয়ান্ন", "পঞ্চান্ন", "ছাপ্পান্ন", "সাতান্ন", "আটান্ন", "উনষাট", "ষাট", "একষট্টি", "বাষট্টি", "তেষট্টি", "চৌষট্টি", "পয়ষট্টি", "ছিষট্টি", " সাতষট্টি", "আটষট্টি", "ঊনসত্তর ", "সত্তর", "একাত্তর ", "বাহাত্তর", "তেহাত্তর", "চুয়াত্তর", "পঁচাত্তর", "ছিয়াত্তর", "সাতাত্তর", "আটাত্তর", "ঊনাশি", "আশি", "একাশি", "বিরাশি", "তিরাশি", "চুরাশি", "পঁচাশি", "ছিয়াশি", "সাতাশি", "আটাশি", "উননব্বই", "নব্বই", "একানব্বই", "বিরানব্বই", "তিরানব্বই", "চুরানব্বই", "পঁচানব্বই ", "ছিয়ানব্বই ", "সাতানব্বই", "আটানব্বই", "নিরানব্বই" ;
return arr[n - 1] + " ";
else if (n >= 100 && n <= 199)
return AmountInWords(n / 100) + "এক শত " + AmountInWords(n % 100);
else if (n >= 100 && n <= 999)
return AmountInWords(n / 100) + "শত " + AmountInWords(n % 100);
else if (n >= 1000 && n <= 1999)
return "এক হাজার " + AmountInWords(n % 1000);
else if (n >= 1000 && n <= 99999)
return AmountInWords(n / 1000) + "হাজার " + AmountInWords(n % 1000);
else if (n >= 100000 && n <= 199999)
return "এক লাখ " + AmountInWords(n % 100000);
else if (n >= 100000 && n <= 9999999)
return AmountInWords(n / 100000) + "লাখ " + AmountInWords(n % 100000);
else if (n >= 10000000 && n <= 19999999)
return "এক কোটি " + AmountInWords(n % 10000000);
else
return AmountInWords(n / 10000000) + "কোটি " + AmountInWords(n % 10000000);
【讨论】：
【参考方案10】：我使用这个名为 Humanizer 的便捷库。
https://github.com/Humanizr/Humanizer
它支持多种文化，不仅可以将数字转换为单词，还可以转换日期，使用起来非常简单。
我是这样使用它的：
int someNumber = 543;
var culture = System.Globalization.CultureInfo("en-US");
var result = someNumber.ToWords(culture); // 543 -> five hundred forty-three
瞧！
【讨论】：
Humanizer 很棒。不久前，我在 Scott Hanselman 的 NuGet 包中看到了它，从那以后我就一直在用它做很多事情。 很棒的图书馆！我曾经创建自己的转换器来将枚举值更改为其描述以使其更具可读性，但 Humanizer 也涵盖了这一点！谢谢。【参考方案11】：以下 C# 控制台应用程序代码将接受最多 2 位小数的货币值，并以英文打印。这不仅将整数转换为其英语等价物，而且将其转换为美元和美分的货币价值。
namespace ConsoleApplication2
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
class Program
static void Main(string[] args)
bool repeat = true;
while (repeat)
string inputMonetaryValueInNumberic = string.Empty;
string centPart = string.Empty;
string dollarPart = string.Empty;
Console.Write("\nEnter the monetary value : ");
inputMonetaryValueInNumberic = Console.ReadLine();
inputMonetaryValueInNumberic = inputMonetaryValueInNumberic.TrimStart('0');
if (ValidateInput(inputMonetaryValueInNumberic))
if (inputMonetaryValueInNumberic.Contains('.'))
centPart = ProcessCents(inputMonetaryValueInNumberic.Substring(inputMonetaryValueInNumberic.IndexOf(".") + 1));
dollarPart = ProcessDollar(inputMonetaryValueInNumberic.Substring(0, inputMonetaryValueInNumberic.IndexOf(".")));
else
dollarPart = ProcessDollar(inputMonetaryValueInNumberic);
centPart = string.IsNullOrWhiteSpace(centPart) ? string.Empty : " and " + centPart;
Console.WriteLine(string.Format("\n\n01", dollarPart, centPart));
else
Console.WriteLine("Invalid Input..");
Console.WriteLine("\n\nPress any key to continue or Escape of close : ");
var loop = Console.ReadKey();
repeat = !loop.Key.ToString().Contains("Escape");
Console.Clear();
private static string ProcessCents(string cents)
string english = string.Empty;
string dig3 = Process3Digit(cents);
if (!string.IsNullOrWhiteSpace(dig3))
dig3 = string.Format("0 1", dig3, GetSections(0));
english = dig3 + english;
return english;
private static string ProcessDollar(string dollar)
string english = string.Empty;
foreach (var item in Get3DigitList(dollar))
string dig3 = Process3Digit(item.Value);
if (!string.IsNullOrWhiteSpace(dig3))
dig3 = string.Format("0 1", dig3, GetSections(item.Key));
english = dig3 + english;
return english;
private static string Process3Digit(string digit3)
string result = string.Empty;
if (Convert.ToInt32(digit3) != 0)
int place = 0;
Stack<string> monetaryValue = new Stack<string>();
for (int i = digit3.Length - 1; i >= 0; i--)
place += 1;
string stringValue = string.Empty;
switch (place)
case 1:
stringValue = GetOnes(digit3[i].ToString());
break;
case 2:
int tens = Convert.ToInt32(digit3[i]);
if (tens == 1)
if (monetaryValue.Count > 0)
monetaryValue.Pop();
stringValue = GetTens((digit3[i].ToString() + digit3[i + 1].ToString()));
else
stringValue = GetTens(digit3[i].ToString());
break;
case 3:
stringValue = GetOnes(digit3[i].ToString());
if (!string.IsNullOrWhiteSpace(stringValue))
string postFixWith = " Hundred";
if (monetaryValue.Count > 0)
postFixWith = postFixWith + " And";
stringValue += postFixWith;
break;
if (!string.IsNullOrWhiteSpace(stringValue))
monetaryValue.Push(stringValue);
while (monetaryValue.Count > 0)
result += " " + monetaryValue.Pop().ToString().Trim();
return result;
private static Dictionary<int, string> Get3DigitList(string monetaryValueInNumberic)
Dictionary<int, string> hundredsStack = new Dictionary<int, string>();
int counter = 0;
while (monetaryValueInNumberic.Length >= 3)
string digit3 = monetaryValueInNumberic.Substring(monetaryValueInNumberic.Length - 3, 3);
monetaryValueInNumberic = monetaryValueInNumberic.Substring(0, monetaryValueInNumberic.Length - 3);
hundredsStack.Add(++counter, digit3);
if (monetaryValueInNumberic.Length != 0)
hundredsStack.Add(++counter, monetaryValueInNumberic);
return hundredsStack;
private static string GetTens(string tensPlaceValue)
string englishEquvalent = string.Empty;
int value = Convert.ToInt32(tensPlaceValue);
Dictionary<int, string> tens = new Dictionary<int, string>();
tens.Add(2, "Twenty");
tens.Add(3, "Thirty");
tens.Add(4, "Forty");
tens.Add(5, "Fifty");
tens.Add(6, "Sixty");
tens.Add(7, "Seventy");
tens.Add(8, "Eighty");
tens.Add(9, "Ninty");
tens.Add(10, "Ten");
tens.Add(11, "Eleven");
tens.Add(12, "Twelve");
tens.Add(13, "Thrteen");
tens.Add(14, "Fourteen");
tens.Add(15, "Fifteen");
tens.Add(16, "Sixteen");
tens.Add(17, "Seventeen");
tens.Add(18, "Eighteen");
tens.Add(19, "Ninteen");
if (tens.ContainsKey(value))
englishEquvalent = tens[value];
return englishEquvalent;
private static string GetOnes(string onesPlaceValue)
int value = Convert.ToInt32(onesPlaceValue);
string englishEquvalent = string.Empty;
Dictionary<int, string> ones = new Dictionary<int, string>();
ones.Add(1, " One");
ones.Add(2, " Two");
ones.Add(3, " Three");
ones.Add(4, " Four");
ones.Add(5, " Five");
ones.Add(6, " Six");
ones.Add(7, " Seven");
ones.Add(8, " Eight");
ones.Add(9, " Nine");
if (ones.ContainsKey(value))
englishEquvalent = ones[value];
return englishEquvalent;
private static string GetSections(int section)
string sectionName = string.Empty;
switch (section)
case 0:
sectionName = "Cents";
break;
case 1:
sectionName = "Dollars";
break;
case 2:
sectionName = "Thousand";
break;
case 3:
sectionName = "Million";
break;
case 4:
sectionName = "Billion";
break;
case 5:
sectionName = "Trillion";
break;
case 6:
sectionName = "Zillion";
break;
return sectionName;
private static bool ValidateInput(string input)
return Regex.IsMatch(input, "[0-9]1,18(\\.[0-9]1,2)?"))
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