如何从 Android 移动应用程序调用本地 Web 服务
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【中文标题】如何从 Android 移动应用程序调用本地 Web 服务【英文标题】：How to call a local web service from an Android mobile application 【发布时间】：2011-12-13 05:42:12 【问题描述】：从过去几天开始，我一直在编写一个调用本地 Web 服务的 android 代码。我正在使用 Android 的 ksoap 库来调用我在 .NET 中创建的 SOAP Web 服务。但是，我觉得我的代码有问题，因为当我从我的应用程序调用 Web 服务时得到的响应遇到了 catch 块。我尝试调试我的 Android 代码，但我仍然无法解决我的问题。 请有人告诉我有什么问题或其他更简单的方法吗？
这是我迄今为止实现的 Android 代码：
package com.demo;
import java.net.SocketException;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.AndroidHttpTransport;
import android.app.Activity;
import android.app.ProgressDialog;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
public class Login extends Activity
private static final String SOAP_ACTION = "http://tempuri.org/GetLoginDetails";
private static final String METHOD_NAME = "GetLoginDetails";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://10.0.2.2/testlogin/Service1.asmx";
@Override
public void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button signin = (Button) findViewById(R.id.regsubmitbtn);
signin.setOnClickListener(new OnClickListener()
public void onClick(View v)
EditText etxt_user = (EditText) findViewById(R.id.usereditlog);
user_id = etxt_user.getText().toString();
EditText etxt_password = (EditText) findViewById(R.id.pwdeditlog);
password = etxt_password.getText().toString();
new LoginTask().execute();
);
String user_id;
String password;
String auth=null;
private class LoginTask extends AsyncTask<Void, Void, Void>
private final ProgressDialog dialog = new ProgressDialog(
Login.this);
protected void onPreExecute()
this.dialog.setMessage("Logging in...");
this.dialog.show();
protected Void doInBackground(final Void... unused)
auth = doLogin("lalit", "lalit");
return null; // don't interact with the ui!
protected void onPostExecute(Void result)
if (this.dialog.isShowing())
this.dialog.dismiss();
private String doLogin(String user_id, String password)
SoapPrimitive resultstring = null;
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("user", user_id);
request.addProperty("password", password);
SoapSerializationEnvelope soapenvelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
soapenvelope.dotNet = true;
soapenvelope.setOutputSoapObject(request);
AndroidHttpTransport httptransport = new AndroidHttpTransport(URL);
httptransport.debug = true;
try
httptransport.call(SOAP_ACTION, soapenvelope);
resultstring = (SoapPrimitive) soapenvelope.getResponse();
//Log.d("Authenticaion", resultstring+"");
System.out.println(resultstring);
catch (SocketException ex)
Log.e("Error : " , "Error on soapPrimitiveData() " + ex.getMessage());
ex.printStackTrace();
catch (Exception e)
Log.e("Error : " , "Error on soapPrimitiveData() " + e.getMessage());
e.printStackTrace();
return resultstring+"";
我的网络服务代码：
using System;
using System.Collections;
using System.ComponentModel;
using System.Data;
using System.Linq;
using System.Web;
using System.Web.Services;
using System.Web.Services.Protocols;
using System.Xml.Linq;
using System.Data.SqlClient;
namespace LoginDetails
[WebService(Namespace = "http://tempuri.org/")]
[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
[ToolboxItem(false)]
// [System.Web.Script.Services.ScriptService]
public class Service1 : System.Web.Services.WebService
[WebMethod]
public String GetLoginDetails(string UserName, string Password)
try
using (SqlConnection myConnection = new SqlConnection(@"Data Source= .\SQLEXPRESS;Initial Catalog=student;User ID=sa;Password=demo"))
myConnection.Open();
using (SqlCommand myCommand = new SqlCommand())
myCommand.Connection = myConnection;
myCommand.CommandText = "SELECT COUNT(*) FROM Login WHERE UserName = @UserName AND Password = @Password";
myCommand.Parameters.Add("@UserName", SqlDbType.VarChar).Value = UserName;
myCommand.Parameters.Add("@Password", SqlDbType.VarChar).Value = Password;
return (int)myCommand.ExecuteScalar() == 1 ? "success" : "bad username or password";
catch (Exception ex)
Console.WriteLine(ex.Message);
return "an error occurred.";
我的日志：
10-22 21:49:17.635: DEBUG/dalvikvm(117): GC_EXTERNAL_ALLOC freed 901 objects /
10-22 21:49:18.015: WARN/KeyCharacterMap(117): No keyboard for id 0
10-22 21:49:18.015: WARN/KeyCharacterMap(117): Using default keymap: /system/usr/keychars/qwerty.kcm.bin
10-22 21:49:22.275: INFO/ARMAssembler(58): generated s scanline__00000077:03515104_00000000_00000000 [ 33 ipp] (47 ins) at [0x23df98:0x23e054] in 675711 ns
10-22 21:49:42.025: INFO/System.out(274): an error occurred.
10-22 21:49:42.045: WARN/InputManagerService(58): Window already focused, ignoring focus gain of: com.android.internal.view.IInputMethodClient$Stub$Proxy@44eda178
【问题讨论】：
【参考方案1】：使用 kSOAP2 可能具有挑战性……我知道。但它是一个很好的图书馆，我已经能够让它工作。我写过一些关于在 Android 上使用 kSOAP2 的文章。我讨论了通过网络传递简单和复杂的参数、接收数组以及使用 JDBC WebRowSet 对象。
http://roderickbarnes.com/blog/droid-chronicles-web-services-handling-complex-parameters
网站上还有其他关于使用 kSOAP2 的博客文章。我希望这会有所帮助。
【讨论】：
非常感谢您的回复！是的，我会尝试你的链接，让你知道它是否适合我！ :-) 链接已过期！【参考方案2】：不知何故，我设法解决了我的问题，我正在回答这个问题，以便它对将来看到这篇文章的人有用。
所以这里是修改后的代码：
package com.demo;
import java.net.SocketException;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.Activity;
import android.app.ProgressDialog;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
public class Login extends Activity
private final String NAMESPACE = "http://tempuri.org/";
private final String URL = "http://10.0.2.2/testlogin/Service1.asmx";
String user_id;
String password;
@Override
public void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button signin = (Button) findViewById(R.id.regsubmitbtn);
signin.setOnClickListener(new OnClickListener()
public void onClick(View v)
EditText etxt_user = (EditText) findViewById(R.id.usereditlog);
user_id = etxt_user.getText().toString();
EditText etxt_password = (EditText) findViewById(R.id.pwdeditlog);
password = etxt_password.getText().toString();
new LoginTask().execute();
);
private boolean doLogin(String user_id, String password)
boolean result=false;
final String SOAP_ACTION = "http://tempuri.org/GetLogin";
final String METHOD_NAME = "GetLogin";
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("userid", user_id);
request.addProperty("password",password);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true; // Set this variable to true for
// compatibility with what seems to be the
// default encoding for .Net-Services.
envelope.setOutputSoapObject(request);
System.out.println(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
Log.i("myApp", response.toString());
System.out.println("response" +response);
if(response.toString().equalsIgnoreCase("success"))
result = true;
catch(SocketException ex)
Log.e("Error : " , "Error on soapPrimitiveData() " + ex.getMessage());
ex.printStackTrace();
catch (Exception e)
Log.e("Error : " , "Error on soapPrimitiveData() " + e.getMessage());
e.printStackTrace();
return result;
private class LoginTask extends AsyncTask<Void, Void, Void>
private final ProgressDialog dialog = new ProgressDialog(
Login.this);
protected void onPreExecute()
this.dialog.setMessage("Logging in...");
this.dialog.show();
protected Void doInBackground(final Void... unused)
boolean auth=doLogin(user_id,password);
System.out.println(auth);
return null;// don't interact with the ui!
protected void onPostExecute(Void result)
if (this.dialog.isShowing())
this.dialog.dismiss();
【讨论】：
嘿，你上面的代码在 this.dialog.show() 中出现错误；和新的 LoginTask().execute();这两条线...我该如何解决以上是关于如何从 Android 移动应用程序调用本地 Web 服务的主要内容，如果未能解决你的问题，请参考以下文章
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