如何从存储过程中获取结果，过程运行良好但 php 返回 null

Posted 2023-02-25

【中文标题】如何从存储过程中获取结果，过程运行良好但 php 返回 null

【英文标题】：How to get result from stored procedure, the procedure runs fine but php returns null

【发布时间】：2019-09-15 05:36:30

【问题描述】：

我有一个存储过程在我的 mysql 服务器上运行，代码如下：

DELIMITER $$
CREATE DEFINER=`present`@`%` PROCEDURE `InsertNewEventOrderItems`(IN `UserIDParam` INT, IN `Time` VARCHAR(255), IN `EventIDParam` INT, OUT `Result` VARCHAR(255))
    MODIFIES SQL DATA
BEGIN

    DECLARE OrderIDVar INT DEFAULT 0;

    IF (EXISTS(SELECT * FROM _newapp_shop_orders where UserID=UserIDParam AND Status='Open')) THEN

        SELECT OrderID INTO OrderIDVar FROM _newapp_shop_orders WHERE UserID=UserIDParam AND Status='Open';

        IF (NOT EXISTS(SELECT * FROM _newapp_shop_order_items WHERE OrderID=OrderIDVar AND EventID=EventIDParam)) THEN  

            -- User has open order so create a new order item!

            SELECT OrderID INTO OrderIDVar FROM _newapp_shop_orders WHERE UserID=UserIDParam AND Status='Open';

            INSERT INTO _newapp_shop_order_items (OrderID, EventID, ActivityID, Price, Amount) VALUES (OrderIDVar, EventIDParam, NULL, (SELECT Price FROM _newapp_shop_products_events WHERE EventID=EventIDParam), 1);

            -- SELECT 'InsertOrderItem' INTO Result;  

            SELECT ROW_COUNT() INTO Result;

        ELSE 

            UPDATE _newapp_shop_order_items SET Amount=Amount + 1 WHERE OrderID=OrderIDVar AND EventID=EventIDParam;

            -- SELECT 'UpdateOrderItem' INTO Result;

            SELECT ROW_COUNT() INTO Result;

        END IF;


    ELSE 

        -- User has no open order so create a new order!

        INSERT INTO _newapp_shop_orders (UserID, Created, Modified) VALUES (UserIDParam, Time, Time);

        SELECT OrderID INTO OrderIDVar from _newapp_shop_orders where UserID=UserIDParam AND Status='Open';

        IF (NOT EXISTS(SELECT * FROM _newapp_shop_order_items WHERE OrderID=OrderIDVar AND EventID=EventIDParam)) THEN  

            -- User has made a new order item so create a new order item!

            INSERT INTO _newapp_shop_order_items (OrderID, EventID, ActivityID, Price, Amount) VALUES (OrderIDVar, EventIDParam, NULL, (SELECT Price FROM _newapp_shop_products_events WHERE EventID=EventIDParam), 1);

            -- SELECT 'InsertOrderItem' INTO Result;  

            SELECT ROW_COUNT() INTO Result;  

        ELSE 
            -- User has made an existing order item so update the order item!

            UPDATE _newapp_shop_order_items SET Amount=Amount + 1 WHERE OrderID=OrderIDVar AND EventID = EventIDParam;

            -- SELECT 'UpdateOrderItem' INTO Result;

            SELECT ROW_COUNT() INTO Result;

        END IF;

    END IF;
END$$
DELIMITER ;

它插入一个新订单、订单项目或更新一个现有项目，它返回修改后的行以检查插入是否成功。当我在 phpmyadmin 中执行该过程时，它会导致插入的行很好，并且它会在所属表中插入正确的行。但是当我从 php 运行这个程序时，它只返回 NULL，这是我的 php 代码：

public function pushItemToCart($userID, $item)
    
        $itemList = json_decode($item);
        if ($itemList->Type == 'events') 
            $sql = 'CALL `InsertNewEventOrderItems`(?, ?, ?, @Result)';
         elseif ($itemList->Type == 'activities') 
            $sql = 'CALL `InsertNewActivityOrderItems`(?, ?, ?, @Result)';
        

        if ($query = $this->DB->prepare($sql)) 
            $nowFormat = mktime(
                date('H'),
                date('i'),
                date('s'),
                date('m'),
                date('d'),
                date('Y')
            );

            $query->bind_param('isi', $userID, $nowFormat, $itemList->Id);

            $query->execute();

            $query->next_result();

            $select = $this->DB->query('SELECT @Result;');

            //$query->execute();

            $result = $select->fetch_assoc();

            $query->close();

            echo json_encode($result['@Result']);

            exit();
         else 
            $error = $this->DB->errno . ' ' . $this->DB->error;

            echo json_encode('405'); // 1054 Unknown column 'foo' in 'field list'

            exit();
        
    

所以我希望结果是 1 或 2 或 0

【问题讨论】：

你需要更多 >next_result();来电

您可能应该包含该 sql 的实际 CREATE PROCEDURE 部分。

@Uueerdo 更新了我的问题。

@YourCommonSense 在代码中的什么位置？

【参考方案1】：

我已经通过删除第二次执行并全面检查错误过程来解决它。主帖中的正确代码。