如何从 microsoft web 表达式 4 连接到 phpmyadmin localhost 数据库
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【中文标题】如何从 microsoft web 表达式 4 连接到 phpmyadmin localhost 数据库【英文标题】：How to connect to phpmyadmin localhost database from microsoft web expression 4 【发布时间】：2022-01-14 01:31:35 【问题描述】：如何连接到它一直说的数据库
致命错误：未捕获的错误：在 C:\xampp\htdocs\5Dec2021\Order.php:90 中找不到类“msqli”堆栈跟踪：在 C:\xampp\htdocs\5Dec2021\Order 中抛出 #0 main .php 在第 90 行 当我转到 http://localhost/5Dec2021/Menu.html 时它工作正常我可以点击按钮并回答文本框Here但在我提交后它变成This
这是我的 HTML
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<title>Untitled 1</title>
</head>
<body>
<form method="post" action="Order.php">
<table border="1" style="width: 100%">
<tr>
<th colspan="2" style="height: 25px">Pizza Shop 2.0</th>
</tr>
<tr>
<td style="width: 310px">Name:</td>
<td>
<input name="Text1" id="Name" type="text" style="width: 299px" /></td>
</tr>
<tr>
<td style="width: 310px">Pizza Topping:</td>
<td><input name="Checkbox1[]" type="checkbox" id="supreme"value="Supreme" />Supreme<br>
<input name="Checkbox1[]" type="checkbox" id="vegetarian" value="Vegetarian" />Vegetarian<br>
<input name="Checkbox1[]" type="checkbox" id="haiwaian" value="Haiwaian" />Haiwaian
</td>
</tr>
<tr>
<td style="width: 310px">Pizza Sauce:</td>
<td><select name="Select1" id="dropdown" style="width: 296px">
<option selected="selected" value="0">-</option>
<option value="Ketchup">Ketchup</option>
<option value="Bolognese">Bolognese</option>
<option value="CheeseSpread">Cheese Spread</option>
</select></td>
</tr>
<tr>
<td style="height: 23px; width: 310px;">Optional Extra:</td>
<td style="height: 23px">
<input name="Checkbox2[]" type="checkbox" id="extra" value="Extra cheese" />Extra Cheese <br>
<input name="Checkbox2[]" type="checkbox" id="gluten" value="Gluten free base" />Gluten Free Base
</td>
</tr>
<tr>
<td style="width: 310px" colspan="2">Delivery Instruction:<br>
<textarea name="TextArea1" style="width: 608px; height: 127px"></textarea></td>
</tr>
<tr>
<td style="width: 310px" colspan="2"><input name="submit" type="submit" value="submit" /></td>
</tr>
</table>
</form>
</body>
</html>
这是我的 PHP
<?php
//variable declaration
$name=$_POST['Text1'];
$p=0;
$p2=0;
if (isset($_POST['Checkbox1']))
$top=$_POST['Checkbox1'];
$c=count($top);
for ($i=0; $i<$c;$i++)
If($top[$i]=="Supreme")
$p=$p+15;
If($top[$i]=="Vegetarian")
$p=$p+11;
If($top[$i]=="Haiwaian")
$p=$p+12;
if (isset($_POST['Select1']))
$sauce=$_POST['Select1'];
If($sauce=="0")
$p2=$p2+0;
If($sauce=="Ketchup")
$p2=$p2+4;
If($sauce=="Bolognese")
$p2=$p2+3;
If($sauce=="CheeseSpread")
$p2=$p2+5;
$p3=0;
if (isset($_POST['Checkbox2']))
$extra=$_POST['Checkbox2'];
$c=count($extra);
for ($i=0; $i<$c; $i++)
If($extra[$i]=="Extra cheese")
$p3=$p3+10;
If($extra[$i]=="Gluten free base")
$p3=$p3+5;
$delivery =$_POST['TextArea1'];
$total=0;
$total=$p+$p2+$p3;
$top=implode(" ",$_POST['Checkbox1']); // HAVE TO IMPLODE IF CAN BE MULTIPLE VALUES.
$extra=implode(" ",$_POST['Checkbox2']);
date_default_timezone_set("Asia/Kuala_Lumpur");
$date=date("d-m-Y H:i:sa");
echo "<h1>Billing statement</h1>";
echo "<br>";
echo "Hi ".$name;
echo "<br>";
echo "Total bill RM: ".$total;
//database configuration (pizzatime is the folder of the table name)
$con= new msqli("localhost","root","","pizzatime");
//is the connection working? connection error
if($con->connect_error)
die("Warning!Connection Failed!".$con->connect_error);
//if connection is ok (orderpizza is the table name, and INSERT INTO IS THE COLUMN NAMES WHILE THE VALUES ARE THE CONTAINERS OF THE BUTTONS/CHECKBOX/...
$database="INSERT INTO orderpizza(Time,Name,Top,Sauce,Extra,Delivery,Total) VALUES
('$date','$name','$top','$sauce','$extra','$delivery','$total')";
if($con->query($database)===TRUE)
echo "<br>";
echo "<alert>'Successfully save into the database'</alert>;";
else
echo "Error".$con->connect_error;
$con->close();
?>
This is database I created in localhost phpmyadmin
【问题讨论】：
您是否已经尝试过调用类 mysqli 而不是 msqli ？ 是的，我已经用谷歌搜索并尝试了一些东西，其中 1 个正在更改为 mysqli，但它没有工作同样的错误 你的意思是说“找不到类“mysqli”？ 对不起，我以为你写了我尝试过的 my_mysqli，但它应该是同样的错误，但我刚刚尝试了 mysqli，它显示imgur.com/Gp3aHwX 现在有更多错误 【参考方案1】：我不得不将我的 Xampp 端口更改为 4306，因为它不起作用，所以我必须在 localhost 旁边添加：4306
//database configuration (pizzatime is the folder of the table name)
$con = new msqli("localhost**:4306**","root","","pizzatime");
【讨论】：
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