将连接查询更改为 laravel

Posted 2023-02-24

【中文标题】将连接查询更改为 laravel

【英文标题】：Change join query to laravel

【发布时间】：2018-06-20 09:50:18

【问题描述】：

我有一个mysql查询

SELECT a.`head_id` AS "Headid",a.`name` AS "HeadName", b.`id` AS "Emp_ID",b.`name` AS "Emp_name" FROM users a join users b ON a.id=b.head_id where a.`head_id`=63 or b.`id`=63

如何将此查询转换为 laravel？

$users = DB::table('users a')
            ->join('users b', 'a.id', '=', 'b.head_id')

            ->select('a.head_id as Headid','a.name AS HeadName','b.name AS Emp_name','b.name AS Emp_name')
            ->get();

但运气不好，这不起作用。请帮助我。

【参考方案1】：

您的查询构建器看起来不错，只需根据您的普通查询添加 where 过滤器

$users = DB::table('users as a')
            ->join('users as b', 'a.id', '=', 'b.head_id')
            ->select('a.head_id as Headid','a.name AS HeadName','b.name AS Emp_name','b.name AS Emp_name')
            ->where('a.head_id', '=', 63)
            ->orWhere('b.id','=', 63)
            ->get();

【讨论】：

@M khalid junaid 感谢您的回复，但我收到了一个错误，例如 'admin.users a' not exist..query like select a.head_id as Headid, a .name as HeadName, b.name as Emp_name, b.name as Emp_name from users a inner join users b on @98765433@.=@9867654335@ b.head_id 其中a.head_id = 63 或b.id = 63 如果我从users a 中删除单引号，它将起作用

@Ezra 尝试使用关键字users as a