使用 Alamofire 将图像数组上传到服务器

Posted 2023-02-24

【中文标题】使用 Alamofire 将图像数组上传到服务器

【英文标题】：Upload array of images to server using Alamofire

【发布时间】：2018-04-17 12:29:47

【问题描述】：

我正在使用 Swift4，我已使用此代码将图像上传到服务器

class func uploadMultipleAdvertisementImage(photos: UIImage, completion: @escaping (_ error: Error?, _ sucess: Bool, _ image_id: Int)-> Void) 

    let url = URLs.uploadImages

    var images = [Data]()
    Alamofire.upload(multipartFormData:  (form: MultipartFormData) in



       if let data = UIImageJPEGRepresentation(photos , 0.5) 
            form.append(data, withName: "images", fileName: "photo.jpeg", mimeType: "image/jpeg")
        

    , usingThreshold: SessionManager.multipartFormDataEncodingMemoryThreshold, to: url, method: .post, headers: nil)  (result: SessionManager.MultipartFormDataEncodingResult) in

        switch result 
        case .failure(let error):
            print(error)
            completion(error, false, 0)

        case .success(request: let upload, streamingFromDisk: _, streamFileURL: _):

            upload.uploadProgress(closure:  (progress: Progress) in
                print(progress)
            )
                .responseJSON(completionHandler:  (response: DataResponse<Any>) in

                    switch response.result
                    
                    case .failure(let error):
                        print(error)
                        completion(error, false, 0)

                    case .success(let value):
                        let json = JSON(value)
                        print(json)
                        if(json["msg"] == "image uploaded successfully") 
                            let image_id = json["image_id"].int ?? 0
                            print("hiiiiiiiiii", image_id)
                            completion(nil, true, image_id)
                        
                    

                )
        

    

成功了， 但我想将图像数组上传到名为“图像”的服务器。 有什么方法可以将图像数组上传到服务器而不是上传一个？

【问题讨论】：

***.com/questions/42427541/…的可能重复

Upload multiple images in swift using Alamofire的可能重复

你可以查看这个答案。 ***.com/questions/45685210/…

您的 api 必须以数组的形式获取图像数据。如果图像的设置参数为一个并且用新图像覆盖每个图像来自数组。联系您的后端开发人员以管理图像数组

@NitinGohel 没有 api 管理将图像数据作为数组获取。

【参考方案1】：

只是没有什么需要做的。 添加你的

if let data = UIImageJPEGRepresentation(photos , 0.5) 
            form.append(data, withName: "images", fileName: "photo.jpeg", mimeType: "image/jpeg")
        

编码到 For 循环中，其余的事情 AlamoFire 会处理。

【讨论】：

for i in 0..

【参考方案2】：

假设您在函数中获得images: [UIImage] 作为参数。然后你只需要将所有图像的数据追加到多部分形式中，只需更新每个图像的文件名。

将您的代码行更新为：

for i in 0..<images.count 
    if let data = UIImageJPEGRepresentation(photos[i], 0.5)         
        form.append(data, withName: "images", fileName: "photo\(i).jpeg", mimeType: "image/jpeg")
    

【讨论】：

它对我不起作用可能是因为它不是数组，后端只接收数组

【参考方案3】：

要告诉服务器端您正在发送一组图像或视频，您必须在参数名称后附加 一个开闭方括号 '[]' .祝你好运，编码愉快。

public func multipartUpload(_ images: [String: UIImage], videos: [String: Data], params: [String: String], api: API, headers: HTTPHeaders, success: @escaping(Response?) -> Void, fail: @escaping(Error) -> Void) 

    DispatchQueue.main.async 
        UIApplication.shared.isNetworkActivityIndicatorVisible = true
    

    Alamofire.upload(multipartFormData:  (multipartFormData) in
        for (key, value) in params 
            multipartFormData.append(value.data(using: .utf8)!, withName: key)
        

        for (name, value) in images 
            multipartFormData.append(UIImageJPEGRepresentation(value, 1)!, withName: "images[]", fileName: name, mimeType: "image/jpeg")
        

        for (name, value) in videos 
            multipartFormData.append(value, withName: "videos[]", fileName: name, mimeType: "video/mp4")
        

    , usingThreshold: UInt64.init(), to: api.path, method: .post, headers: headers, encodingCompletion: encodingResult in
        switch encodingResult 
        case .success(let upload, _, _):
            upload.validate(contentType: ["application/json"]).responseJSON  response in
                DispatchQueue.main.async 
                    UIApplication.shared.isNetworkActivityIndicatorVisible = false
                

                if let httpStatusCode = response.response?.statusCode, let data = response.data 
                    switch(httpStatusCode) 
                    case 200...300:
                        let mResponse = Response(json: JSON(data), resultCode: httpStatusCode)
                        return success(mResponse)
                    default:
                        let mResponse = Response(json: JSON(data), resultCode: httpStatusCode)
                        return success(mResponse)
                    
                 else 
                    fail(CustomError(forClientErrorCode: .noDataToReturn))
                

            
            upload.uploadProgress(closure:  progress in
                if let aProgressRing = Utility.shared.progressCircle 
                    aProgressRing.startProgress(to: CGFloat(progress.fractionCompleted * 100), duration: 0.1)
                
                print(progress)
            )
        case .failure(let encodingError):
            print(encodingError)
        
    )