使用 Alamofire 将图像上传到 API 服务器

Posted 2023-02-24

【中文标题】使用 Alamofire 将图像上传到 API 服务器

【英文标题】：Uploading Image to API Server using Alamofire

【发布时间】：2017-02-12 14:29:31

【问题描述】：

我有一个关于的问题。

基本网址：http://vietnamtravelguide-app.com/quangnam/api_inquangnam/tips/create?user_id=""&token="" 3个参数：location_id、content、imageName

邮递员发帖没问题

我的代码：

Alamofire.upload(multipartFormData:  multipartFormData in
            multipartFormData.append(image, withName: "imageName", fileName: "swift_file.jpeg", mimeType: "image/jpeg")

        , with: path, encodingCompletion: encodingResult in
            switch encodingResult 
            case .success(let upload, _, _):
            upload.responseJSON  response in
                print(response.result)
            switch response.result 
            case .success:
                let json = JSON(response.result.value!)
                if(delegate != nil) 
                    delegate!.didReceiveResult(json,basePath: basePath)
                
            case .failure(let error):
                print(error)
                                    
            case .failure(let encodingError):
                print(encodingError)
            

            )

带有图像（来自参数转换的图像作为数据）。当我调试它时，我得到了 response.result 返回失败

【参考方案1】：

您没有上传剩余的两个参数content 和location_id。

试试这个，看看结果。我也在这里使用了SwiftyJSON。 这是我用于所有 API 处理的 APIManager 类。

import Alamofire
import SwiftyJSON

class APIManager: NSObject 

    class func apiMultipart(serviceName:String,parameters: [String:Any]?, completionHandler: @escaping (JSON?, NSError?) -> ()) 

        Alamofire.upload(multipartFormData:  (multipartFormData:MultipartFormData) in
            for (key, value) in parameters! 
                if key == "imageName" 
                    multipartFormData.append(
                        value as! Data,
                        withName: key,
                        fileName: "swift_file.jpg",
                        mimeType: "image/jpg"
                    )
                 else 
                    //Data other than image
                    multipartFormData.append((value as! String).data(using: .utf8)!, withName: key)
                
            
        , usingThreshold: 1, to: serviceName, method: .post, headers: ["yourHeaderKey":"yourHeaderValue"])  (encodingResult:SessionManager.MultipartFormDataEncodingResult) in

            switch encodingResult 
            case .success(let upload, _, _):
                upload.responseJSON  response in
                    if response.result.error != nil 
                        completionHandler(nil,response.result.error as NSError?)
                        return
                    
                    print(response.result.value!)
                    if let data = response.result.value 
                        let json = JSON(data)
                        completionHandler(json,nil)
                    
                
                break

            case .failure(let encodingError):
                print(encodingError)
                completionHandler(nil,encodingError as NSError?)
                break
            
        
    

如果您没有任何标题，则可以将字段保留为 ["":""] 代替您的 ["yourHeaderKey":"yourHeaderValue"]

现在为了调用，我刚刚在控制器中形成了参数。

var params = [String:AnyObject]()
params["content"] = "something" as AnyObject?
params["location_id"] = "201" as AnyObject?

// Grab your image from some variable or imageView. Here self.profileImage is a UIImage object
if let profileImageData = self.profileImage 
    if let imageData = UIImageJPEGRepresentation(profileImageData, 0.5) 
        params["imageName"] = imageData as AnyObject?
        APIManager.apiMultipart(serviceName: "http://yourAPIURL", parameters: params, completionHandler:  (response:JSON?, error:NSError?) in
        //Handle response       
        )
     else 
       print("Image problem")
    

【讨论】：

是的，已解决，我错过了 2 个参数并对其进行了编码。非常感谢。