连接元素节点由相同的状态名称组成一个元素节点
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【中文标题】连接元素节点由相同的状态名称组成一个元素节点【英文标题】：Concatenate Elements nodes consist of same state name into one element node 【发布时间】：2021-08-26 05:55:10 【问题描述】：输入 XML 文件
<ContactD>
<addr>
<name>jack</name>
<street>south street</street>
<state>Tamilnadu</state>
<country>India</country>
<pin>621716</pin>
</addr>
<addr>
<name>Benjamin</name>
<street>north street</street>
<state>Tamilnadu</state>
<country>India</country>
<pin>621706</pin>
</addr>
<addr>
<name>Ryan</name>
<street>East street</street>
<state>Kerala</state>
<country>India</country>
<pin>67322</pin>
</addr>
</ContactD>
输出应该是这样的：
<ContactD>
<addr>
<name>jack,Benjamin</name>
<street>south street,north street</street>
<state>Tamilnadu</state>
<country>India</country>
<pin>621716,621706</pin>
</addr>
<addr>
<name>Ryan</name>
<street>East street</street>
<state>Kerala</state>
<country>India</country>
<pin>67322</pin>
</addr>
</ContactD>
我尝试使用 Java 代码我尝试匹配 state 元素之后我不知道如何将这两者连接成一个
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
//import com.sun.org.apache.xml.internal.security.utils.XPathFactory;
import javax.xml.XMLConstants;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import java.io.File;
import java.io.IOException;
import java.io.InputStream;
public class Jparser
private static final String FILENAME = "books.xml";
public static void main(String[] args)
// Instantiate the Factory
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try
// optional, but recommended
// process XML securely, avoid attacks like XML External Entities (XXE)
dbf.setFeature(XMLConstants.FEATURE_SECURE_PROCESSING, true);
// parse XML file
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new File(FILENAME));
// optional, but recommended
// http://***.com/questions/13786607/normalization-in-dom-parsing-with-java-how-does-it-work
doc.getDocumentElement().normalize();
System.out.println("Root Element :" + doc.getDocumentElement().getNodeName());
System.out.println("------");
// get <staff>
NodeList list = doc.getElementsByTagName("addr");
String[] hell= new String[3];
for (int temp = 0; temp < list.getLength(); temp++)
Node node = list.item(temp);
if (node.getNodeType() == Node.ELEMENT_NODE)
Element element = (Element) node;
String name = element.getElementsByTagName("name").item(0).getTextContent();
String street = element.getElementsByTagName("street").item(0).getTextContent();
hell[temp]= element.getElementsByTagName("state").item(0).getTextContent();
String country = element.getElementsByTagName("country").item(0).getTextContent();
String pin = element.getElementsByTagName("pin").item(0).getTextContent();
System.out.println("Current Element :" + node.getNodeName());
System.out.println("name : " + name);
System.out.println("street : " + street);
System.out.println("state : " + hell[temp]);
System.out.println("country : " + country);
System.out.printf("pin :"+ pin);
for (int t = 0; t < list.getLength()-1; t++)
if(hell[t].equals(hell[t+1]))
/////here i need to concatenate the two element nodes which has same state in one xml data what to do here!!
System.out.println("same");
catch (ParserConfigurationException | SAXException | IOException e)
e.printStackTrace();
当我尝试将我识别为相同的两个元素节点联系为一个时，我卡住了...我完成了匹配这些状态节点...需要连接帮助！
【问题讨论】：
JQuery 和 html 是从哪里来的？另请注意，您在此处包含的任何内容都不是可运行的 javascript sn-p - 我现在会相应地编辑问题，但以后请多加注意。 tnx 我以后会更小心的 【参考方案1】：输入
<ContactD>
<addr>
<name>jack</name>
<street>south street</street>
<state>Tamilnadu</state>
<country>India</country>
<pin>621716</pin>
</addr>
<addr>
<name>Benjamin</name>
<street>north street</street>
<state>Tamilnadu</state>
<country>India</country>
<pin>621706</pin>
</addr>
<addr>
<name>Ryan</name>
<street>East street</street>
<state>Kerala</state>
<country>India</country>
<pin>67322</pin>
</addr>
<addr>
<name>yan</name>
<street>East street</street>
<state>Kerala</state>
<country>India</country>
<pin>67322</pin>
</addr>
</ContactD>
预期输出：
<?xml version="1.0" encoding="UTF-8" standalone="no"?><ContactD>
<addr>
<name>jack,Benjamin</name>
<street>south street,north street</street>
<state>Tamilnadu</state>
<country>India</country>
<pin>621716,621706</pin>
</addr>
<addr>
<name>Ryan,yan</name>
<street>East street</street>
<state>Kerala</state>
<country>India</country>
<pin>67322</pin>
</addr>
</ContactD>
这个连接的Javacode如下：（抱歉太多冗余的cmets和不均匀的代码）
import java.io.File;
// j a v a 2 s .co m
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.Result;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
//import com.sun.org.apache.xml.internal.security.utils.XPathFactory;
import javax.xml.XMLConstants;
import javax.xml.parsers.ParserConfigurationException;
import java.util.ArrayList;
import java.io.IOException;
public class Jparser
private static final String FILENAME = "books.xml";
private static void toString(Document newDoc) throws Exception
TransformerFactory tranFactory = TransformerFactory.newInstance();
Transformer aTransformer = tranFactory.newTransformer();
Source src = new DOMSource(newDoc);
Result dest = new StreamResult(new File("books.xml"));
aTransformer.transform(src, dest);
public static void main(String[] args) throws Exception
// Instantiate the Factory
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try
// optional, but recommended
// process XML securely, avoid attacks like XML External Entities (XXE)
dbf.setFeature(XMLConstants.FEATURE_SECURE_PROCESSING, true);
// parse XML file
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new File(FILENAME));
// optional, but recommended
// http://***.com/questions/13786607/normalization-in-dom-parsing-with-java-how-does-it-work
doc.getDocumentElement().normalize();
System.out.println("Root Element :" + doc.getDocumentElement().getNodeName());
System.out.println("------");
// get <staff>
NodeList list = doc.getElementsByTagName("addr");
//String[] hell= new String[10];
ArrayList<String> hell = new ArrayList<String>();
ArrayList<Element> Ements = new ArrayList<Element>();
for (int temp = 0; temp < list.getLength(); temp++)
Node node = list.item(temp);
if (node.getNodeType() == Node.ELEMENT_NODE)
Element element = (Element) node;
Ements.add(element);
String name = element.getElementsByTagName("name").item(0).getTextContent();
String street = element.getElementsByTagName("street").item(0).getTextContent();
hell.add(element.getElementsByTagName("state").item(0).getTextContent());
String country = element.getElementsByTagName("country").item(0).getTextContent();
String pin = element.getElementsByTagName("pin").item(0).getTextContent();
System.out.println("Current Element :" + node.getNodeName());
System.out.println("name : " + name);
System.out.println("street : " + street);
System.out.println("state : " + hell.get(temp));
System.out.println("country : " + country);
System.out.printf("pin :"+ pin);
System.out.println("The size of the ArrayList is: " + Ements.size());
// System.out.println(Ements.get(0).name);
for (int t = 0; t < Ements.size()-1; t++)
// for(int s=1;s<Ements.size()-1;s++)
//for(int d=1; d<list.getLength()-1;d++)
if(hell.get(t).equals(hell.get(t+1)))
/////here i need to concatenate the two element nodes which has same state in one xml data what to do here!!
// int z=t;
String[] he= "name","street","state","country","pin";
for(int a=0; a<he.length; a++)
//System.out.printf(Ements.get[a]);
String zz0=Ements.get(t).getElementsByTagName(he[a]).item(0).getTextContent();
String zz1=Ements.get(t+1).getElementsByTagName(he[a]).item(0).getTextContent();
if(!zz0.equals(zz1))
Ements.get(t).getElementsByTagName(he[a]).item(0).setTextContent(zz0+","+zz1);
//String zz=Ements.get(t).getElementsByTagName(he[a]).item(0).getTextContent()+","+Ements.get(t+1).getElementsByTagName(he[a]).item(0).getTextContent();
// Ements.get(t).getElementsByTagName(he[a]).item(0).setTextContent(zz);
// System.out.println(Ements.get(t).getElementsByTagName(he[a]).item(0).getTextContent());
doc.getDocumentElement().removeChild(Ements.get(t+1));
Ements.remove(t+1);
hell.remove(t+1);
System.out.println(Ements.size());
System.out.println(Ements.size());
// DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
// DocumentBuilder domBuilder = domFactory.newDocumentBuilder();
//Document newDoc = domBuilder.newDocument();
//Element rootElement = newDoc.createElement("parent");
// NodeList toremove=doc.getDocumentElement().getChildNodes();
//for(int i=0;i<toremove.getLength();i++)
// doc.getDocumentElement().removeChild(toremove.item(i));
//
//doc.getDocumentElement().appendChild(Ements.get(0));
//doc.getDocumentElement().appendChild(Ements.get(1));
toString(doc);
catch (ParserConfigurationException | SAXException | IOException e)
e.printStackTrace();
【讨论】：
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