Django如何将外键传递给ModelForm字段
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【中文标题】Django如何将外键传递给ModelForm字段【英文标题】：Django how to pass foreign key into ModelForm field 【发布时间】：2014-09-02 07:54:35 【问题描述】：我是 Django 新手，作为一个学习项目，我正在构建一个待办事项列表应用程序。 主页 (lists.html) 显示 List 对象和 Item 对象（通过外键关联）。
Lists.html 显示所有列表和这些列表中的任何项目。列表标题旁边是一个“新建”链接。单击此链接将转到 create.html，您可以在其中创建新项目并将它们添加到列表中。我想要发生的是，当您单击“新建”时，它会带您创建.html 但它已经预先填充了 todo_list 外键字段，具体取决于您单击旁边的“新建”哪个列表。
我最初的策略是尝试将列表 ID 传递到 URL，但后来我很难将其输入 todo_list 外键字段。这是正确的方法吗？还有什么其他方法可以实现？
代码如下，在此先感谢。
models.py：
from django.db import models
from django.forms import ModelForm
import datetime
PRIORITY_CHOICES = (
(1,'Low'),
(2,'Normal'),
(3,'High'),
)
# Create your models here.
class List(models.Model):
title = models.CharField(max_length=250,unique=True)
def __str__(self):
return self.title
class Meta:
ordering = ['title']
class Admin:
pass
class Item(models.Model):
title = models.CharField(max_length=250)
created_date = models.DateTimeField(default=datetime.datetime.now)
priority = models.IntegerField(choices=PRIORITY_CHOICES,default=2)
completed = models.BooleanField(default=False)
todo_list = models.ForeignKey(List)
def __str__(self):
return self.title
class Meta:
ordering = ['-priority','title']
class Admin:
pass
class NewItem(ModelForm):
class Meta:
model = Item
fields = ['title','priority','completed','todo_list']
views.py：
from django.shortcuts import render_to_response
from django.shortcuts import render
from todo.models import List
from todo.models import Item
from todo.models import NewItem
from django.http import HttpResponseRedirect
# Create your views here.
def status_report(request):
todo_listing = []
for todo_list in List.objects.all():
todo_dict =
todo_dict['id'] = id
todo_dict['list_object'] = todo_list
todo_dict['item_count'] = todo_list.item_set.count()
todo_dict['items_complete'] = todo_list.item_set.filter(completed=True).count()
todo_dict['percent_complete'] =int(float(todo_dict['items_complete'])/todo_dict['item_count']*100)
todo_listing.append(todo_dict)
return render_to_response('status_report.html', 'todo_listing': todo_listing)
def lists(request):
todo_listing = []
for todo_list in List.objects.all():
todo_dict =
todo_dict['list_object'] = todo_list
todo_dict['items'] = todo_list.item_set.all()
todo_listing.append(todo_dict)
return render_to_response('lists.html','todo_listing': todo_listing)
def create(request):
if request.method == 'POST':
form = NewItem(request.POST or None)
if form.is_valid():
form.save()
return HttpResponseRedirect('/lists/')
else:
form = NewItem()
return render(request, 'create.html', 'form': form)
lists.html
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>To-do List Status Report</title>
</head>
<body>
<h1>To-do lists</h1>
% for list_dict in todo_listing %
<h2> list_dict.list_object.title <a href='/create/'>New</a></h2>
<table>
% for item in list_dict.items %
<tr><td> item </td><td><a href='/delete/item.id/'>Del</a></td></tr>
% endfor %
</table>
</ul>
% endfor %
</body>
</html>
创建.html
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Create Task</title>
</head>
<body>
<form action="/create/" method="post">
% csrf_token %
% for field in form %<p>field</p>% endfor %
<input type="submit" value="Submit" />
</form>
</body>
</html>
【问题讨论】：
【参考方案1】：也许这会有所帮助：https://***.com/a/5470037/2002580
您希望通过请求传递一些数据。我认为 URL 方案之类的东西可能很有用，因为它不会太复杂。
# urls.py
urlpatterns += patterns('myview.views',
url(r'^(?P<user>\w+)/', 'myview', name='myurl'), # I can't think of a better name
)
# template.html
<form name="form" method="post" action="% url myurl username %">
# above code is from the linked answer
【讨论】：
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