QuickBlox - 对话框必须在 Objective-C 的内存缓存中

Posted 2023-02-23

【中文标题】QuickBlox - 对话框必须在 Objective-C 的内存缓存中

【英文标题】：QuickBlox - Dialog have to be in memory cache in Objective-C

【发布时间】：2017-05-05 10:45:49

【问题描述】：

我创建了一个聊天应用程序。我已经使用 QuickBlox 互相聊天。

我已经注册了两个用户并互相聊天，它会很完美。 但是当用户注销并再次登录时，它会崩溃。

错误 - 对话框必须在内存缓存中！

EX：A 和 B 用户使用他们的设备登录，然后在他们注销并再次登录以及发送消息应用程序崩溃时相互聊天。 p>

登录

- (void)loginWithQuickBlox:(NSString *)idandPassword 
    [QBRequest logInWithUserLogin:idandPassword password:idandPassword successBlock:^(QBResponse *response, QBUUser *user)
     
        // NSLog(@"User Id : %ld",(unsigned long)user.ID);

         NSString *usrID=[NSString stringWithFormat:@"%ld",(unsigned long)user.ID];
         [[NSUserDefaults standardUserDefaults]setObject:usrID forKey:@"LoginQuickbloxID"];

         [self loginWithQuickBloxChat:idandPassword];
      errorBlock:^(QBResponse *response)
     
         // error handling
         NSLog(@"error: %@", response.error);
     ];


- (void)loginWithQuickBloxChat:(NSString *)idandPassword 

    QBUUser *selectedUser = [QBUUser user];
    selectedUser.password = idandPassword;
    selectedUser.login = idandPassword;

    [ServicesManager.instance logInWithUser:selectedUser completion:^(BOOL success, NSString *errorMessage)
     
         if (success)
         
             [self getRecenetChatUsingInBadgeCount];
             NSLog(@"Login in Quickblox");
             [[NSUserDefaults standardUserDefaults]setObject:idandPassword forKey:@"QuickbloxIDPass"];
         
         else
         
             NSLog(@"Error in QuickBlox");
         
     ];

聊天

与 ChatViewController 聊天。

注销

1)取消订阅设备令牌

NSString *deviceUdid = [[[UIDevice currentDevice] identifierForVendor] UUIDString];
                [QBRequest unregisterSubscriptionForUniqueDeviceIdentifier:deviceUdid successBlock:^(QBResponse *response) 
                    // Unsubscribed successfully
                       NSLog(@"Unsubscribed successfully");

                 errorBlock:^(QBError *error) 
                    // Handle error
                    NSLog(@"Unsubscribed ERROR");
                ];

2)ServicesManager 注销

[ServicesManager.instance logoutWithCompletion:^

           NSLog(@"logoutWithCompletion");

    ];

3)退出成功阻止

[QBRequest logOutWithSuccessBlock:^(QBResponse *response) 
           // Successful logout
              NSLog(@"Successful logout");

      errorBlock:^(QBResponse *response) 
              // Handle error
               NSLog(@"Logout ERROR %@",response);
   ];

退出登录后发送消息时再次崩溃

QMChatService.m

- (void)sendMessage:(QBChatMessage *)message
         toDialogID:(NSString *)dialogID
      saveToHistory:(BOOL)saveToHistory
      saveToStorage:(BOOL)saveToStorage
         completion:(QBChatCompletionBlock)completion

    NSCParameterAssert(dialogID);
    QBChatDialog *dialog = [self.dialogsMemoryStorage chatDialogWithID:dialogID];
    NSAssert(dialog != nil, @"Dialog have to be in memory cache!");

    [self sendMessage:message toDialog:dialog saveToHistory:saveToHistory saveToStorage:saveToStorage completion:completion];

【问题讨论】：

我有同样的问题，发送消息应用程序会在这里崩溃：NSAssert(dialog != nil, @"Dialog must be in memory cache!");

@sohil，请在Quickblox repo 中创建问题并附上完整的日志。

@sohil，你找到解决这个问题的方法了吗？

【参考方案1】：

答案很晚，但也许有人会觉得这很有帮助。 为了使对话在内存中，必须使用正确的方法加载它（某些方法不执行此操作）。 这是我的做法（但很快，我很抱歉）

private func sendMessage(message: QBChatMessage) 
    if ServicesManager.instance().chatService.dialogsMemoryStorage.chatDialog(withID: self.dialog.id!) != nil 
        self.send(message: message)
     else 
        loadAndSaveToMemoryDialog(message)
    


private func send(message: QBChatMessage) 
    ServicesManager.instance().chatService.send(message, toDialogID: self.dialog.id!, saveToHistory: true, saveToStorage: true)  (error in
        if error != nil 
            QMMessageNotificationManager.showNotification(withTitle: "SA_STR_ERROR", subtitle: error?.localizedDescription, type: .error, handler: nil)
        
    


private func loadAndSaveToMemoryDialog(_ message: QBChatMessage) 
    ServicesManager.instance().chatService.loadDialog(withID: self.dialog.id!) 
        [weak self] _ in
        guard let self = self else  return 
        self.sendMessage(message: message)