按下注册按钮时应用程序崩溃

Posted 2023-02-23

【中文标题】按下注册按钮时应用程序崩溃

【英文标题】：App crashes when registration button is pressed

【发布时间】：2018-07-06 16:21:59

【问题描述】：

我对 android studio 和 java 有点陌生，但对编程不熟悉。我正在开发一个类似于 Uber 的应用程序。

当我第一次编写登录和注册活动代码时，一切都很顺利。现在，在完成应用程序的大部分功能后，辞职方法会使应用程序崩溃。我已经尝试了一切，包括获取一个新的 JSON 文件。

任何帮助将不胜感激。

import android.content.Intent;
import android.support.annotation.NonNull;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;

import com.google.android.gms.tasks.OnCompleteListener;
import com.google.android.gms.tasks.Task;
import com.google.firebase.auth.AuthResult;
import com.google.firebase.auth.FirebaseAuth;
import com.google.firebase.auth.FirebaseUser;
import com.google.firebase.database.DatabaseReference;
import com.google.firebase.database.FirebaseDatabase;


public class CustomerLoginActivity extends AppCompatActivity 
private EditText mEmail, mPassword;
private Button mLogin, mRegistration;

private FirebaseAuth mAuth;
private FirebaseAuth.AuthStateListener mAuthListener;

@Override
protected void onCreate(Bundle savedInstanceState) 
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_customer_login);

    mAuth = FirebaseAuth.getInstance();

    mAuthListener =[enter image description here][1] new FirebaseAuth.AuthStateListener() 
        @Override
        public void onAuthStateChanged(@NonNull FirebaseAuth firebaseAuth) 
            //store info of current user
            FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
            if(user!=null)
                Intent intent = new Intent(CustomerLoginActivity.this, CustomerMapActivity.class);
                startActivity(intent);
                finish();
            

        
    ;

    mEmail = (EditText) findViewById(R.id.email);
    mPassword = (EditText) findViewById(R.id.password);

    mLogin = (Button) findViewById(R.id.login);
    mRegistration = (Button) findViewById(R.id.registration);

    mRegistration.setOnClickListener(new View.OnClickListener() 
        @Override
        public void onClick(View v) 
            String email = mEmail.getText().toString();
            String password = mPassword.getText().toString();
            mAuth.createUserWithEmailAndPassword(email, password).addOnCompleteListener(CustomerLoginActivity.this, new OnCompleteListener<AuthResult>() 
                @Override
                public void onComplete(@NonNull Task<AuthResult> task) 
                    if(!task.isSuccessful())
                        Toast.makeText(CustomerLoginActivity.this, "sign up error", Toast.LENGTH_SHORT).show();
                    else
                        String user_id = mAuth.getCurrentUser().getUid();
                        DatabaseReference current_user_db = FirebaseDatabase.getInstance().getReference().child("Users").child("Customers").child(user_id);
                        current_user_db.setValue(true);

                    

                
            );
        
    );

    mLogin.setOnClickListener(new View.OnClickListener() 
        @Override
        public void onClick(View v) 
            String email = mEmail.getText().toString();
            String password = mPassword.getText().toString();
            mAuth.signInWithEmailAndPassword(email, password).addOnCompleteListener(CustomerLoginActivity.this, new OnCompleteListener<AuthResult>() 
                @Override
                public void onComplete(@NonNull Task<AuthResult> task) 
                    if(!task.isSuccessful())
                        Toast.makeText(CustomerLoginActivity.this, "sign in error", Toast.LENGTH_SHORT).show();
                    

                
            );

        
    );


@Override
protected void onStart() 
    super.onStart();
    mAuth.addAuthStateListener(mAuthListener);


@Override
protected void onStop() 
    super.onStop();
    mAuth.removeAuthStateListener(mAuthListener);

【问题讨论】：

什么是崩溃日志。显示崩溃日志！？

查看这个答案***.com/questions/39842599/…

i.stack.imgur.com/a6ouh.png@Xenolion

检查@jignesh下面的答案，问题是您的编辑文本没有任何值，所以它们是空的，您可以在点击注册按钮之前填写它们来确认！！

【参考方案1】：

需要验证邮箱，密码不能为空

  String email = mEmail.getText().toString();
                    String password = mPassword.getText().toString();
                    if(password.length()==0 || email.length()==0)
                    
                    // enter the email and password 
                    return;
                    

                   mAuth.createUserWithEmailAndPassword(email, password).addOnCompleteListener(CustomerLoginActivity.this, new OnCompleteListener<AuthResult>() 
                @Override
                public void onComplete(@NonNull Task<AuthResult> task) 
                    if(!task.isSuccessful())
                        Toast.makeText(CustomerLoginActivity.this, "sign up error", Toast.LENGTH_SHORT).show();
                    else
                        String user_id = mAuth.getCurrentUser().getUid();
                        DatabaseReference current_user_db = FirebaseDatabase.getInstance().getReference().child("Users").child("Customers").child(user_id);
                        current_user_db.setValue(true);

                    

                
            );

【讨论】：

登录方法完美运行....它的注册方法使应用程序崩溃...您仍然建议我更改登录方法吗？ @jignesh

非常感谢伙计！...非常感谢

【参考方案2】：

电子邮件和密码不应为空或为空

String email = mEmail.getText().toString();
String password = mPassword.getText().toString();

if(email.isEmpty() || password.isEmpty())
    return;    //you need to display message to the user

mAuth.createUserWithEmailAndPassword(email, password)
.addOnCompleteListener(CustomerLoginActivity.this, new OnCompleteListener<AuthResult>() 
 
    ...
)

【参考方案3】：

字符串电子邮件 = mEmail.getText().toString();

字符串密码 = mPassword.getText().toString();

/*请检查null，因为我们不能拥有它*/

if(email.isEmpty() || 密码.isEmpty()) 返回;

/*

你的代码

*/