来自 api 的信息不显示 - Flutter
Posted
技术标签:
【中文标题】来自 api 的信息不显示 - Flutter【英文标题】:Information from api doesn't show - Flutter 【发布时间】:2021-04-06 22:35:52 【问题描述】:我对 Flutter 中的 Future builder 有疑问。它成功地从 api 获取信息但不显示它。当我从 api 打印和打印信息时,没问题,它显示电影名称没有任何问题。这是我的代码:
class Search extends StatefulWidget
final String value;
Search(Key key, String this.value) : super(key: key);
@override
_SearchState createState() => _SearchState();
class _SearchState extends State<Search>
var title;
Future getSearch(index) async
http.Response response = await http.get(
'https://api.themoviedb.org/3/search/company?api_key=6d6f3a650f56fd6b3347428018a20a73&query=' +
widget.value);
var results = json.decode(response.body);
setState(()
this.title = results['results'];
);
return title[index]['name'];
getName(index)
return title[index]['name'];
@override
Widget build(BuildContext context)
return SafeArea(
child: Scaffold(
backgroundColor: Color(0xff1d1d27),
body: Column(
children: [
Expanded(
child: FutureBuilder(
initialData: [],
future: getSearch(),
builder: (context, snapshot)
return ListView.builder(itemBuilder: (context, index)
Padding(
padding:
EdgeInsets.symmetric(horizontal: 30, vertical: 20),
child: Container(
color: Colors.white,
child: Text(getName(index).toString()),
),
);
);
,
))
],
)),
);
【问题讨论】:
【参考方案1】:请使用这个code
,它可以很好地获取名称并将它们显示在列表中,
import 'dart:convert';
import 'package:flutter/material.dart';
import 'package:http/http.dart' as http;
class Search extends StatefulWidget
final String value;
Search(Key key, String this.value) : super(key: key);
@override
_SearchState createState() => _SearchState();
class _SearchState extends State<Search>
var title;
var results;
getSearch() async
http.Response response = await http.get(
'https://api.themoviedb.org/3/search/company?api_key=6d6f3a650f56fd6b3347428018a20a73&query=' +
widget.value);
results = json.decode(
response.body); //make it global variable to fetch it everywhere we need
return results['results'][0]['name'];
getName(index)
return results['results'][index]['name'];
@override
Widget build(BuildContext context)
return SafeArea(
child: Scaffold(
backgroundColor: Color(0xff1d1d27),
body: Column(
children: [
Expanded(
child: FutureBuilder(
// initialData: [],
future: getSearch(),
builder: (context, snapshot)
String name =
snapshot.data; // to get the data from the getSearch
print(name);
if (snapshot.hasData)
// if there is data then show the list
return ListView.builder(
itemCount: results['results']
?.length, // to get the list length of results
itemBuilder: (context, index)
return Padding(
padding: EdgeInsets.symmetric(
horizontal: 30, vertical: 20),
child: Container(
color: Colors.white,
child: Text(getName(index)
.toString()), // pass the index in the getName to get the name
),
);
);
else
// if there is no data or data is not loaded then show the text loading...
return new Text("Loading...",
style: TextStyle(fontSize: 42, color: Colors.white));
,
))
],
)),
);
P.S了解 Futurebuilder 的基础知识可以查看this 文章了解更多信息
我已经对代码进行了注释,以便向您解释更多。
【讨论】:
谢谢兄弟。你帮了很多忙。当然我会知道你发送的链接。 别担心兄弟@MahdiAghajani,我们都是学习者,学习永远不会停止。以上是关于来自 api 的信息不显示 - Flutter的主要内容,如果未能解决你的问题,请参考以下文章
Dart/flutter:如何在模拟器的本地主机上显示来自 API 的图像
在 ReactJS 中使用搜索框时如何显示来自 API 的信息?
Flutter:未处理的异常:错误状态:调用关闭后无法添加新事件(不一样的情况)