如何过滤数组以获取laravel中两个不同对象中的特定列

Posted 2023-02-16

【中文标题】如何过滤数组以获取laravel中两个不同对象中的特定列

【英文标题】：how to filter an array to get specific columns in two different objects in laravel

【发布时间】：2021-10-29 23:37:28

【问题描述】：

我需要这样的回应。

"result": [ 
  
  "properties":  
    "device_id": 15196,
    "device_name": Street Light 1,
    "state" : 1,
    "status": 1,
  , 
  "geometry": 
    "lat":33.7017, 
    "lng": 73.0228 
   
,
  
  "properties":  
    "device_id": 15196,
    "device_name": Street Light 1,
    "state" : 1,
    "status": 1,
  , 
  "geometry": 
    "lat":33.7017, 
    "lng": 73.0228 
   
,
]

我的代码在下面。我只想从我的整个回复中分出两个字段“lat”和“lng”。我的 sql 查询是正确的，但我想创建上面提到的自定义响应

$get1 = DB::table('device_user')
            ->join('devices', 'devices.id', '=', 'device_user.device_id')
            ->join('components', 'devices.id', '=', 'components.device_id')
            ->select('devices.id as device_id', 'devices.name', 'devices.status', 'components.state', 'components.type', 'devices.lat', 'devices.lng')
            ->where('device_user.user_id', $request->user_id)
            ->where('components.type', $type)
            ->get();
$array = [];
foreach ($get1 as $key => $value) 
array_push($array, ["properties" => $value, "geometry" => $value->lat]);
            
return $array;

【参考方案1】：

我试了很多次，终于搞定了。

$get = DB::table('device_user')
            ->join('devices', 'devices.id', '=', 'device_user.device_id')
            ->join('components', 'devices.id', '=', 'components.device_id')
            ->select('devices.id as device_id', 'devices.name', 'devices.status', 'components.state', 'components.type', 'devices.lat', 'devices.lng')
            ->where('device_user.user_id', $request->user_id)
            ->where('components.type', $type)
            ->get();
        $finalarray =[];
        foreach ($get as $key => $value) 
            array_push($finalarray, ["properties" => ['device_id' => $value->device_id, 'name' => $value->name, 'status' => $value->status, 'state' => $value->state, 'type' => $value->type, ], "geometry" => ["coordinates" => ['lat' => $value->lat, 'lng' => $value->lng]]]);
        

【参考方案2】：

试试这个

$get1 = DB::table('device_user')
            ->join('devices', 'devices.id', '=', 'device_user.device_id')
            ->join('components', 'devices.id', '=', 'components.device_id')
            ->select('devices.id as device_id', 'devices.name', 'devices.status', 'components.state', 'components.type', 'devices.lat', 'devices.lng')
            ->where('device_user.user_id', $request->user_id)
            ->where('components.type', $type)
            ->get();

$main_array = [];
foreach ($get1 as $key => $value) 

    $main_array[$key]['properties'] = array('device_id' => $value->device_id, 'device_name' =>  $value->device_name, 'state' => $value->state, 'status' => $value->status);
    $main_array[$key]['geometry'] = array('lat' => $value->lat, 'lng' =>  $value->lng);


return $main_array;