c++字符串,删除字符'b'并将字符'a'替换为两个'd'的构建函数
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【中文标题】c++字符串,删除字符\'b\'并将字符\'a\'替换为两个\'d\'的构建函数【英文标题】:c++ string, build function that removes character 'b' and replaces character 'a' by two 'd'c++字符串,删除字符'b'并将字符'a'替换为两个'd'的构建函数 【发布时间】:2016-11-25 22:02:26 【问题描述】:在 Hackerrank 平台上进行的一项测试中,我被要求构建一个函数,该函数在删除所有“b”并将所有“a”替换为两个“d”后返回一个字符串。例如:i/p: abacdb o/p ddddcd 在搜索了各种文献后,我能够想出使用这个程序:(请注意我不允许更改函数类型)
#include <iostream>
using namespace std;
char* ReplaceandRemove(char* s)
int write_idx=0;
int a_count=0;
for(const char &C : s)
if(C!='b')
s[write_idx++]=C;
if(C=='a')
++a_count;
s.resize(write_idx+a_count);
int curr_idx=write_idx - 1;
write_idx = s.size()-1;
while(curr_idx>=0)
if(curr_idx=='a')
s[write_idx--]='d';
s[write_idx--]='d';
else
s[write_idx--]=s[curr_idx];
--curr_idx;
return s;
int main()
char s[6]='a', 'b', 'a', 'c', 'd', 'b';
ReplaceandRemove(s);
cout<<s;
return 0;
程序给出了很多超出我理解的错误:
In function 'char* ReplaceandRemove(char*)':
6:25: error: no matching function for call to 'begin(char*&)'
s)
6:25: note: candidates are:
42:0,
52,
40,
41,
42,
38,
39,
1:
89:5: note: template constexpr const _Tp* std::begin(std::initializer_list<_Tp>)
89:5: note: template argument deduction/substitution failed:
6:25: note: mismatched types 'std::initializer_list<_Tp>' and 'char*'
s)
51:0,
40,
41,
42,
38,
39,
1:
87:5: note: template _Tp* std::begin(_Tp (&)[_Nm])
87:5: note: template argument deduction/substitution failed:
6:25: note: mismatched types '_Tp [_Nm]' and 'char*'
s)
51:0,
40,
41,
42,
38,
39,
1:
58:5: note: template decltype (__cont.begin()) std::begin(const _Container&)
58:5: note: template argument deduction/substitution failed:
In substitution of 'template decltype (__cont.begin()) std::begin(const _Container&) [with _Container = char*]':
6:25: required from here
58:5: error: request for member 'begin' in '__cont', which is of non-class type 'char* const'
48:5: note: template decltype (__cont.begin()) std::begin(_Container&)
48:5: note: template argument deduction/substitution failed:
In substitution of 'template decltype (__cont.begin()) std::begin(_Container&) [with _Container = char*]':
6:25: required from here
48:5: error: request for member 'begin' in '__cont', which is of non-class type 'char*'
6:25: error: no matching function for call to 'end(char*&)'
s)
6:25: note: candidates are:
42:0,
52,
40,
41,
42,
38,
39,
1:
99:5: note: template constexpr const _Tp* std::end(std::initializer_list<_Tp>)
99:5: note: template argument deduction/substitution failed:
6:25: note: mismatched types 'std::initializer_list<_Tp>' and 'char*'
s)
51:0,
40,
41,
42,
38,
39,
1:
97:5: note: template _Tp* std::end(_Tp (&)[_Nm])
97:5: note: template argument deduction/substitution failed:
6:25: note: mismatched types '_Tp [_Nm]' and 'char*'
s)
51:0,
40,
41,
42,
38,
39,
1:
78:5: note: template decltype (__cont.end()) std::end(const _Container&)
78:5: note: template argument deduction/substitution failed:
In substitution of 'template decltype (__cont.end()) std::end(const _Container&) [with _Container = char*]':
6:25: required from here
78:5: error: request for member 'end' in '__cont', which is of non-class type 'char* const'
68:5: note: template decltype (__cont.end()) std::end(_Container&)
68:5: note: template argument deduction/substitution failed:
In substitution of 'template decltype (__cont.end()) std::end(_Container&) [with _Container = char*]':
6:25: required from here
68:5: error: request for member 'end' in '__cont', which is of non-class type 'char*'
15:7: error: request for member 'resize' in 's', which is of non-class type 'char*'
17:19: error: request for member 'size' in 's', which is of non-class type 'char*'
请帮我找出我做错了什么
【问题讨论】:
【参考方案1】:for(const char &C : s)
s
是一个char *
,一个纯字符指针。范围迭代仅适用于std::begin()
和std::end()
支持的那些类型。普通指针不是其中之一。
s.resize(write_idx+a_count);
s
是一个char *
,一个普通的字符指针。它不是一个实现名为resize()
的方法的类。
write_idx = s.size()-1;
s
是一个char *
,一个普通的字符指针。它不是实现称为size()
的方法的类。
所示代码的总体问题是它假定s
是某种类,如std::string
,它实现了各种方法。不是,是普通的char *
。
这就是编译错误的原因。
【讨论】:
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