将多个手势识别器分配给 AnyObject 时出错

Posted 2023-02-15

【中文标题】将多个手势识别器分配给 AnyObject 时出错

【英文标题】：Error while Assigning Multiple Gesture Recognizers to AnyObject

【发布时间】：2016-08-02 04:29:52

【问题描述】：

大家好，我目前在这个错误上迷路了，这是我第一次使用 ios 和 Swift，虽然我已经能够使用 1 个手势识别器来查看视图，但我需要为任何对象设置多个手势识别器（component.control 有AnyObject 类型），当我运行它并按下按钮（作为 AnyObject 类型传递）时，我在 appDelegate.swift 文件中得到了这个错误

line 1: class AppDelegate: UIResponder, UIApplicationDelegate  //Thread 1: EXC_BAD_ACCESS (code=1,address=0x1)

我们将不胜感激！谢谢！

这就是我所拥有的 覆盖 func viewDidLoad() super.viewDidLoad()

    //gestures  
    let gesture_tap = UITapGestureRecognizer(target: self, action: #selector(ComponentDetailViewController.ctrl_tapped(_:event:)));
    let gesture_pinch = UIPinchGestureRecognizer(target: self, action: #selector(ComponentDetailViewController.ctrl_pinched(_:event:)));
    let gesture_swipe = UISwipeGestureRecognizer(target:self, action: #selector(ComponentDetailViewController.ctrl_swiped(_:event:)));
    let gesture_longPress = UILongPressGestureRecognizer(target: self, action: #selector(ComponentDetailViewController.ctrl_longPressed(_:event:)));
    let gesture_rotate = UIRotationGestureRecognizer(target:self,action: #selector(ComponentDetailViewController.ctrl_rotated(_:event:)));
    let gesture_pan = UIPanGestureRecognizer(target:self, action: #selector(ComponentDetailViewController.ctrl_panned(_:event:)));

    let ctrl = component?.control;

    ctrl!.addGestureRecognizer(gesture_tap);
    ctrl!.addGestureRecognizer(gesture_pinch);
    ctrl!.addGestureRecognizer(gesture_swipe);
    ctrl!.addGestureRecognizer(gesture_longPress);
    ctrl!.addGestureRecognizer(gesture_rotate);
    ctrl!.addGestureRecognizer(gesture_pan);

    gesture_tap.delegate = self;
    gesture_pinch.delegate = self;
    gesture_swipe.delegate = self;
    gesture_longPress.delegate = self;
    gesture_rotate.delegate = self;
    gesture_pan.delegate = self;


    component?.control = ctrl as? UIView;

    //component?.control!.userInteractionEnabled = true;
    //component?.control!.addGestureRecognizer(tap);
    viewDisplayComponent.addSubview((component?.control)! as! UIView);




//Gesture methods
func ctrl_tapped(ctrl: AnyObject, event:UIEvent)
    setMessage("TO_tapped");

func ctrl_pinched(ctrl: AnyObject, event:UIEvent)
    setMessage("TO_pinchedWithArgs")

func ctrl_swiped(ctrl: AnyObject, event:UIEvent)
    setMessage("TO_swipedWithArgs");

func ctrl_longPressed(ctrl: AnyObject, event:UIEvent)
    setMessage("TO_longPressedWithArgs");

func ctrl_rotated(ctrl: AnyObject, event:UIEvent)
    //logTextView.text += "Rotated";

func ctrl_panned(ctrl: AnyObject, event:UIEvent)
    setMessage("TO_pannedWithArgs");

【参考方案1】：

根据docs：

调用的动作方法必须符合以下之一 签名：

(void)handleGesture; (void)handleGesture:(UIGestureRecognizer *)gestureRecognizer; 快速翻译： handleGesture(gestureRecognizer: UIGestureRecognizer)

然而，您所有的操作方法都有带有两个参数的签名。我不确定你是如何让一个手势识别器工作的。

我在 appDelegate.swift 文件中得到了这个错误：

第 1 行：类 AppDelegate：UIResponder、UIApplicationDelegate //线程1：EXC_BAD_ACCESS (code=1,address=0x1)

Xcode 调试区域的输出顶部，即 print() 语句的输出位置如何？