如何在 WorkManager for Android 中创建一个带有参数的 Worker?
Posted
技术标签:
【中文标题】如何在 WorkManager for Android 中创建一个带有参数的 Worker?【英文标题】:How to create a Worker with parameters for in WorkManager for Android? 【发布时间】:2019-03-09 09:21:53 【问题描述】:android 架构有一个新组件WorkManager。
来自example,
class CompressWorker(context : Context, params : WorkerParameters)
: Worker(context, params)
override fun doWork(): Result
// Do the work here--in this case, compress the stored images.
// In this example no parameters are passed; the task is
// assumed to be "compress the whole library."
myCompress()
// Indicate success or failure with your return value:
return Result.SUCCESS
// (Returning RETRY tells WorkManager to try this task again
// later; FAILURE says not to try again.)
val compressionWork = OneTimeWorkRequestBuilder<CompressWorker>().build()
如何创建一个Worker
接受构造函数或doWork
中的参数?
【问题讨论】:
【参考方案1】:在 Java 中:
传递参数如下:
Constraints.Builder builder = new Constraints.Builder()
.setRequiredNetworkType(NetworkType.CONNECTED);
// Passing params
Data.Builder data = new Data.Builder();
data.putString("SyncMaster", syncModuleName);
OneTimeWorkRequest syncWorkRequest =
new OneTimeWorkRequest.Builder(SyncWorker.class)
.addTag("Sync")
.setInputData(data.build())
.setConstraints(builder.build())
.build();
WorkManager.getInstance().enqueue(syncWorkRequest);
你可以这样:
public class SyncWorker extends Worker
private static final String TAG = "MyWorker";
public SyncWorker(@NonNull Context context, @NonNull WorkerParameters workerParams)
super(context, workerParams);
mContext = context;
@NonNull
@Override
public Result doWork()
Log.d(TAG, "doWork for Sync");
String syncTable = getInputData().getString("SyncMaster");
return Result.success();
希望它会明显有所帮助。
【讨论】:
【参考方案2】:你可以像Bundle一样使用setInputData
方法发送数据。
/*** Logic to set Data while creating worker **/
val compressionWork = OneTimeWorkRequest.Builder(CompressWorker::class.java)
val data = Data.Builder()
//Add parameter in Data class. just like bundle. You can also add Boolean and Number in parameter.
data.putString("file_path", "put_file_path_here")
//Set Input Data
compressionWork.setInputData(data.build())
//enque worker
WorkManager.getInstance().enqueue(compressionWork.build())
/*** Logic to get Data ***/
class CompressWorker(context : Context, params : WorkerParameters)
: Worker(context, params)
override fun doWork(): Result
//get Input Data back using "inputData" variable
val filePath = inputData.getString("file_path")
// Do the work here--in this case, compress the stored images.
// In this example no parameters are passed; the task is
// assumed to be "compress the whole library."
myCompress()
// Indicate success or failure with your return value:
return Result.SUCCESS
// (Returning RETRY tells WorkManager to try this task again
// later; FAILURE says not to try again.)
欲了解更多信息,请访问link。
【讨论】:
如何访问Worker中的数据? params.getInputData().getString("file_path") 有没有办法发送非原始值作为参数? 要回答@Óscar 点,这里讨论如何将可序列化的 POJO 传递给 Worker ***.com/questions/51018299/… @Óscar 尝试使用workDataOf
时要谨慎。尽管有其方法签名,但您不能传递除基元以外的任何内容,因为生成的 Data
对象只能包含基元或基元数组。如果您尝试传递其他任何内容,您将收到 IllegalArgumentException
。以上是关于如何在 WorkManager for Android 中创建一个带有参数的 Worker?的主要内容,如果未能解决你的问题,请参考以下文章
WorkManager 如何安排对 REST API 的 GET 请求?
如何使用Workmanager / PeriodicWorkRequest保持时间间隔之间的数据
如何在 Android Jetpack Workmanager 中输入和输出 AN Object 数据?
从 FirebaseJobDispatcher 迁移到 AndroidX Workmanager 时:如何在 startWork 中返回 ListenableFuture? [复制]