SQL 错误：缺少关键字？

Posted 2023-05-09

【中文标题】SQL 错误：缺少关键字？

【英文标题】：SQL error: Missing keyword?

【发布时间】：2015-06-19 15:13:58

【问题描述】：

我在这里遇到了缺少关键字的错误。我最近添加了 WHERE 子句，这就是缺少关键字错误出现的时候。

 Select job_id,
        (Case :P1_DATE_CHOOSER 
             WHEN 'Daily' THEN trunc(start_time)
             WHEN 'Weekly' THEN trunc(start_time, 'WW')
             WHEN 'Monthly' THEN trunc(start_time, 'MM') 
        END) "START_DATE",  
        1440*(END_TIME - START_TIME) "RUN_TIME"
 from NI_INFA_ACTIVITY_LOG_V


WHERE 


 (Case :P1_JOB_SIZE_CHOOSER
 WHEN 'Small' THEN (1440*(END_TIME - START_TIME)) <= 5
 WHEN 'Medium' THEN  (1440*(END_TIME - START_TIME)) > 5 AND 
                (1440*(END_TIME - START_TIME)) <= 20
 WHEN 'Large' THEN (1440*(END_TIME - START_TIME)) > 20
 Else (1440*(END_TIME - START_TIME)) > 0 
 END)

任何帮助将不胜感激。

【问题讨论】：

你能描述一下你的桌子吗？

我认为 WHERE 子句中的 CASE 语句是不允许的。尝试使用 DECODE。

【参考方案1】：

这样做：

....
....
WHERE 
:P1_JOB_SIZE_CHOOSER = 'Small' AND (1440*(END_TIME - START_TIME)) <= 5
OR
:P1_JOB_SIZE_CHOOSER = 'Medium' AND (1440*(END_TIME - START_TIME)) > 5 AND 
                (1440*(END_TIME - START_TIME)) <= 20
OR
:P1_JOB_SIZE_CHOOSER = 'Large' AND ((1440*(END_TIME - START_TIME)) > 20
OR
:P1_JOB_SIZE_CHOOSER NOT IN('Small','Medium','Large') AND (1440*(END_TIME - START_TIME)) > 0 

【参考方案2】：

您必须稍微修改您的 CASE 以返回一个值：

WHERE 
  Case 
    WHEN :P1_JOB_SIZE_CHOOSER = 'Small'  AND (1440*(END_TIME - START_TIME)) <= 5 
      THEN 1
    WHEN :P1_JOB_SIZE_CHOOSER = 'Medium' AND (1440*(END_TIME - START_TIME)) > 5
                                         AND (1440*(END_TIME - START_TIME)) <= 20
      THEN 1
    WHEN :P1_JOB_SIZE_CHOOSER = 'Large' AND (1440*(END_TIME - START_TIME)) > 20
      THEN 1
    WHEN (1440*(END_TIME - START_TIME)) > 0
      THEN 1
  END = 1