将 GROUPED BY SUM 查询与其他查询链接（使用 JOIN 或子查询）

Posted 2023-05-09

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【中文标题】将 GROUPED BY SUM 查询与其他查询链接（使用 JOIN 或子查询）【英文标题】：Link GROUPED BY SUM query with other query (with either JOIN or subquery) 【发布时间】：2020-01-08 09:21:33 【问题描述】：

我有以下表格：

Payments
payment_id   amount   tax_bill_nr   fk_person_id   payment_type   ...

Person
person_id   name   address   ...

Remission
remission_id   tax_bill_nr   fk_person_id   taxing_year   ...

Remission_State
fk_remission_id   created_on   ...

我已经对 Remissions 进行了大量查询，它连接了来自其他表的所有类型的数据。实际上它有 300 多行（是的，数据库模型很烂……），但所有其他数据与我当前的问题无关。查询目前是这样的：

SELECT *
FROM (SELECT remission_id,
             tax_bill_nr,
             ...,
             row_number() OVER (PARITION BY rr.remission_id ORDER BY rs.created_on) rn
      FROM Remission r
      LEFT JOIN Remission_State rs ON rs.fk_remission_id = r.remission_id
      LEFT JOIN ...
      ORDER BY taxing_year, remission_id
) WHERE rn = 1;

我创建了一个单独的查询，它获取按tax_bill_nr 分组的付款总和。这个分离的查询也会得到tax_bill_number 和Person 数据：

SELECT DISTINCT temp.tax_bill_nr,
                pers.person_id,
                temp.amount_sum AS total_amount
FROM (SELECT p.tax_bill_number, sum(p.amount) AS amount_sum
      FROM Payments p
      WHERE p.payment_type = 6 -- Remission_Payment
      GROUP BY p.tax_bill_nr) temp
LEFT JOIN Payments p2 ON temp.tax_bill_nr = p2.tax_bill_number
LEFT JOIN Person pers ON pers.person_id = p2.fk_person_id;

我基本上想结合这两个查询。或者更准确地说，将total_amount 添加到第一个查询的输出中，通过tax_bill_nr 链接Remission 和Payments-sum。

由于SUM 和GROUP BY 的构造，我不知道该怎么做。我尝试过使用子查询，但随后出现缺少右括号、太多值等错误，以及其他神秘的语法错误（这意味着有问题，但 Oracle不知道具体是什么）..

上述查询是 Oracle SQL（如果相关，Oracle 数据库服务器使用版本 12）。

【问题讨论】：

【参考方案1】：

您可以简单地使用 CTE（公用表表达式）来获得更简洁的代码，如下所示：

-- CTE
WITH AMOUNTS (tax_bill_number, amount_sum)
AS
(SELECT p.tax_bill_number, sum(p.amount) AS amount_sum
      FROM Payments p
      WHERE p.payment_type = 6 -- Remission_Payment
      GROUP BY p.tax_bill_nr)
--
SELECT *
FROM (SELECT remission_id,
             tax_bill_nr,
             ...,
             A.amount_sum, -- THIS IS YOUR REQUIRED DATA
             row_number() OVER (PARITION BY rr.remission_id ORDER BY rs.created_on) rn
      FROM Remission r
      LEFT JOIN Remission_State rs ON rs.fk_remission_id = r.remission_id
      LEFT JOIN ...
      -- ADDED FOLLOWING JOIN 
      LEFT JOIN AMOUNTS A ON (A.tax_bill_number = tax_bill_nr)
      ORDER BY taxing_year, remission_id
) WHERE rn = 1;

干杯！！

【讨论】：

【参考方案2】：

由于您有 2 组数据作为结果，因此根据其中存在的公共列将它们相互连接。例如