创建一个文件夹，然后根据需要保存尽可能多的 .txt 文档

Posted 2023-05-07

【中文标题】创建一个文件夹，然后根据需要保存尽可能多的 .txt 文档

【英文标题】：Create a Folder then Save as many .txt Documents as I want

【发布时间】：2021-04-02 21:08:06

【问题描述】：

    import os
    path = os.getcwd()
    print(path)
    y = False
    while y == False:
        dirName = input("Folder name: ")
        try:
            # Create target Directory
            os.mkdir(dirName)
            print("Directory '" , dirName ,  "' Created ")
            y = True
        except FileExistsError:
            print("Directory " , dirName ,  " already exists")
            
    folderDir = os.path.join(path, dirName)
    
    y = int(input("Number of profs: "))
    for a in range(y):
        with open("number.txt","r") as z:
            num = z.read()
            num = int(num)
            newNum = (int(num)+1)
            numProf = ("profile"+str(newNum))
            with open("number.txt","w") as file:
                file.write(str(newNum))
                file.close()
                with open(folderDir+numProf+".txt","x") as f:
                    print(numProf)

###THIS DELETES THE FILES
    ##RESET FILE NUMBER
    reset = input(str("Delete all files (Y/N)?"))
    if reset == "y" or reset == "Y":
        delete = True
    
    if reset == "n" or reset == "N":
        delete = False
    
    if delete == True:
        with open("number.txt","w") as file:
            file.write("0")
            file.close()
        notRemoved = 0
        removed = 0
        for x in range(0,101):
            try:
                os.remove("profile"+str(x)+".txt")
                removed += 1
            except:
                notRemoved +=1
        print("Deleted "+str(removed)) 

这是代码^ Number 用于跟踪有多少文件。 不知道如何打开 number 来检查目录中有多少更改并保存在与 number.txt 相同的文件中，同时仍然创建一个新的空文件夹。

【问题讨论】：

与您的问题无关，但也许很高兴知道：您最好写 if reset == "y" or reset == "Y": 而不是 if reset.lower() == "y": 但在您当前的情况下，如果您输入与“Y”、“y”、“N”、“n”（试试看）为避免这种情况，您可以立即写：delete = reset.lower() == "y" 这意味着，delete == True 如果重置为“y”（或“Y” ) 否则为假。为了执行检查，只需编写：if delete:（delete == True 也可以，但在 python 世界中不常用/不经常使用）

also: reset = input(str("Delete all files (Y/N)?")) 也与 reset = input("Delete all files (Y/N)?") 相同。通常最好的做法是让文件尽可能短地打开并尽快关闭它们。这意味着，对于with open("number.txt","r") as z:，您应该只保留下一行 (num = z.read()) 的缩进，并且您可以将其后的所有其他行取消缩进 4（直到 ###THIS DELE... 注释）with open("number.txt","w") as file: 相同，只需保留该行在它缩进之后，去掉flle.close()和其他人的身份。

您也不需要在另一个 with 语句中使用 file.close()。离开with 声明后，文件将自动关闭。使用 python 编码快乐！

【参考方案1】：

folderDir = os.path.join(path, dirName,numProf)
with open(folderDir+".txt","x") as f:
    print(folderDir+numProf)

更改了该代码并且它起作用了