ListView 显示来自 Firebase 问题的所有数据

Posted 2023-05-07

【中文标题】ListView 显示来自 Firebase 问题的所有数据

【英文标题】：ListView Displays all of the data from Firebase issue

【发布时间】：2021-02-27 17:22:07

【问题描述】：

我已经创建了一个旋转器，包含一个扇区列表，并且选择一个应该显示属于该特定扇区的项目，我认为我的查询有一个问题，从Firebase实时数据库获取数据返回列表中的所有项目

关于创建代码

 FirebaseApp.initializeApp(this);
    listView = findViewById(R.id.listView);

    spnSector = findViewById(R.id.spnSector);

    ArrayAdapter<CharSequence> adapter1 = ArrayAdapter.createFromResource(this,
            R.array.sector_array, android.R.layout.simple_spinner_item);

    adapter1.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);

    spnSector.setAdapter(adapter1);

    spnSector.setOnItemSelectedListener(this);

位置类

public class Location 

public String sector;
public String area;

public double longitude;
public double latitude;

public String getSector() 
    return sector;


public String getArea() 
    return area;


public double getLongitude() 
    return longitude;


public double getLatitude() 
    return latitude;


public Location()




public Location(String sector , String area, double longitude, double latitude)

    this. sector = sector;
    this. area = area;
    this.longitude = longitude;
    this.latitude = latitude;


@Override
public String toString() 
    return "\n Sector='" + sector + '\'' +
            ",Area Name='" + area + '\'' +
            ",Longitude='" + longitude + '\'' +
            ",Latitude=" + latitude + "\n";

案例分类

    public class Case 

    private String caseName;
    private String date;
    private String caseStatus;
    private Location location;

    public String getDate() 
        return date;
    

    public String getCaseName() 
        return caseName;
    

    public String getCaseStatus() 
        return caseStatus;
    

    public Location getLocation() 
        return location;
    

    public Case() 
    


    public Case(String caseName,String date, String caseStatus , Location location) 
        this.caseName = caseName;
        this.date = date;
        this.caseStatus = caseStatus;
        this.location = location;
    

    @Override
    public String toString() 
        return "\nCase Date=" + date + "\n" +
                "Area=" + location.area + "\n" +
                "Latitude=" + location.latitude + "\n" +
                "Longitude=" + location.longitude + "\n"+
                "Sector=" + location.sector + "\n" +
                "Status=" + caseStatus + "\n" +
                "Case name=" + caseName + "\n" ;


    

搜索查询方式

 public void doSearch3(View view) 

    String sector = spnSector.getSelectedItem().toString();

    final ArrayList<Case> cases = new ArrayList<>();


    final ArrayAdapter adapter = new ArrayAdapter<> (SearchCase.this, android.R.layout.simple_list_item_1, cases);

    databaseReference = FirebaseDatabase.getInstance().getReference();

    Query query = databaseReference.child("/Cases");
    query.orderByChild("/location/sector").equalTo(sector);
    query.addValueEventListener(new ValueEventListener() 
        @Override
        public void onDataChange(@NonNull DataSnapshot dataSnapshot) 
            for(DataSnapshot ds : dataSnapshot.getChildren())

                Case case1 = ds.getValue(Case.class);
                cases.add(case1);

            
            listView.setAdapter(adapter);
        

        @Override
        public void onCancelled(@NonNull DatabaseError databaseError) 

        
    );

我可以用 firestore 来做，但我必须实时做，我认为查询是错误的

【参考方案1】：

orderByChild 和equalTo 等查询构建方法返回一个新的Query 对象，因此您必须更新query 变量以引用该新对象。

Query query = databaseReference.child("/Cases");
query = query.orderByChild("/location/sector").equalTo(sector);
query.addValueEventListener(new ValueEventListener() 

【讨论】：

感谢指出，原来是这个问题

【参考方案2】：

改变这个：

databaseReference = FirebaseDatabase.getInstance().getReference();

    Query query = databaseReference.child("/Cases");
    query.orderByChild("/location/sector").equalTo(sector);
    query.addValueEventListener(new ValueEventListener() 
        @Override
        public void onDataChange(@NonNull DataSnapshot dataSnapshot) 
            for(DataSnapshot ds : dataSnapshot.getChildren())

                Case case1 = ds.getValue(Case.class);
                cases.add(case1);

            
            listView.setAdapter(adapter);
        

        @Override
        public void onCancelled(@NonNull DatabaseError databaseError) 

        
    );

到这里：

databaseReference = FirebaseDatabase.getInstance().getReference();

    Query query = databaseReference.child("/Cases");
    query.addValueEventListener(new ValueEventListener() 
        @Override
        public void onDataChange(@NonNull DataSnapshot dataSnapshot) 
            for(DataSnapshot ds : dataSnapshot.getChildren())
             if (ds.child("location").child("sector").getValue(String.class).equals(sector))
                Case case1 = ds.getValue(Case.class);
                cases.add(case1);
   

                

            
            listView.setAdapter(adapter);
        

        @Override
        public void onCancelled(@NonNull DatabaseError databaseError) 

        
    );