如何将所有数据存储在单个数组中，以便我可以轻松地将其作为请求发布？
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【中文标题】如何将所有数据存储在单个数组中，以便我可以轻松地将其作为请求发布？【英文标题】：How to store all data in single array so that I can easily post it as request? 【发布时间】：2015-05-19 16:07:16 【问题描述】：我正在尝试创建嵌套的 jsonArray，以便将其发布到服务器。
我想将这种类型的 json 发布到服务器：
"topnode":
"node1":
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"node2":
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"node3":
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"node4":
"node4_1": [
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"id": "2",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"id": "3",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
],
"Node4_2": [
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"id": "2",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
],
"Node4_3": [
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"id": "2",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
]
,
"Node5":
"A": [
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"id": "2",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"id": "3",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
],
"B": [
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"id": "2",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
],
"C": [
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"id": "2",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
],
"D": [
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
,
"id": "1",
"SecurityQuestion": "1",
"SecuirtyAnswer": "11",
"CreatedDate": "2015-03-16 11:30:59",
"ModifiedDate": "2015-03-16 11:30:59",
"AuthDate": "2015-03-16 11:30:59"
]
我不知道如何做到这一点。这是我正在尝试的：
JSONArray obj_tArray = new JSONArray();
additionalArrayData = new JSONArray();
for (salary tSalary : tsalary_arrayOfList)
additionalData.put("employer", tSalary .getemployer());
additionalData.put("name", tSalary .getname());
additionalData.put("income_head_salary", tSalary .getincome_head_salary());
additionalData.put("total", tSalary .gettotal());
additionalData.put("year", tSalary .getYear());
additionalData.put("panCardNumber", tSalary .getUserPanCard());
additionalData.put("income_head_salary", tSalary .getincome_head_salary());
obj_tArray.put(additionalData);
additionalArrayData.put("t_salary");
additionalArrayData.put(1, obj_TArray);
【问题讨论】：
到目前为止你在哪里？ 我正在尝试这样@eduyayo ***.com/questions/6218143/… 我可以创建请求，但不知道如何将所有这些节点放在一个数组中。 :(@eduyayo 【参考方案1】：这样的事情应该可以工作：
JSONObject innerObject = new JSONObject();
JSONObject middleObject = new JSONObject();
JSONObject outerObject = new JSONObject();
innerObject.put("id", "1");
innerObject.put("SecurityQuestion", "TestQuestion");
middleObject.put("node1", innerObject);
outerObject.put("topnode", middleObject);
这就是您获得嵌套 JSONObject 的方式。您现在需要添加用于迭代不同对象的逻辑。
【讨论】：
感谢您为我提供路径@Deutro以上是关于如何将所有数据存储在单个数组中，以便我可以轻松地将其作为请求发布？的主要内容，如果未能解决你的问题，请参考以下文章
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