通过 httpget 发送 cookie 值但没有得到所需的响应
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【中文标题】通过 httpget 发送 cookie 值但没有得到所需的响应【英文标题】:Sending cookie value via httpget but not getting the desired response 【发布时间】:2013-06-01 15:12:35 【问题描述】:我正在调用我的登录网络服务,如下所示
String url = "http://mydomaim.com/login.php";
UserFunctions userFunction = new UserFunctions();
JSONObject json = userFunction.loginUser(userEmail, password, url);
它工作正常,并如下所示向我发送回复
"userName":"a",
"login_success":1,
"user_id":"3",
"session_id":"1067749aae85b0e6c5c5e697b61cd89d",
"email":"a"
我解析了这个响应,并成功获取了会话 ID,并将其存储在一个静态变量中(在 MainActivity.java 中)现在我必须将此会话 ID 作为 cookie 值发送到我的其他 Web 服务。
我已经这样做了
public JSONObject getJSONQuestion(String url, List<NameValuePair> params)
// Making HTTP request
try
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
CookieStore cookieStore = new BasicCookieStore();
Cookie cookie = new BasicClientCookie("PHPSESSID",
MainActivity.SESSION_ID);
// MainActivity.SESSION_ID has my session id
cookieStore.addCookie(cookie);
HttpContext localContext = new BasicHttpContext();
localContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore);
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet,
localContext);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
catch (UnsupportedEncodingException e)
e.printStackTrace();
catch (ClientProtocolException e)
e.printStackTrace();
catch (IOException e)
e.printStackTrace();
try
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null)
sb.append(line + "\n");
is.close();
json = sb.toString();
Log.e("JSON", json);
catch (Exception e)
Log.e("Buffer Error", "Error converting result " + e.toString());
// try parse the string to a JSON object
try
jObj = new JSONObject(json);
catch (JSONException e)
Log.e("JSON Parser", "Error parsing data " + e.toString());
// return JSON String
return jObj;
但我没有得到想要的响应。请查看我的 cookie 代码。我哪里做错了?
编辑
我明白了,
"logout_success":1,"logout_reason":"no_activity_since_15_min"
但我必须得到这个,
"random_questions":[
"questionid":"31",
"question":"I hate V-",
"answer1":"some answer 1",
"answer2":"another answer 2",
"answer3":"yet another answer 3",
"answer4":"a great answer 4",
"correct":"3"
,
… (more follow) …
]
编辑 2
这是我的会话和 cookie 的 php 代码
<?php
$min = 15 * 60;
//$min = 60;
if (time() - $_SESSION['LAST_ACTIVITY'] > $min)
session_destroy();
setcookie("PHPSESSID", "", time() - 3600, "/"); // delete session cookie
echo json_encode(array('logout_success' => 1, 'logout_reason' => 'no_activity_since_15_min'));
die;
else
$_SESSION['LAST_ACTIVITY'] = time();
mysqli_query($link, "UPDATE logged_in_users SET last_activity = " . $_SESSION['LAST_ACTIVITY'] . " WHERE session_id = '" . session_id() . "' ");
【问题讨论】:
您收到的响应或错误是什么?您可以编辑您的问题并将其包括在内吗? @QuentinSwain 是的,只是一分钟 @QuentinSwain 看看我的编辑。我没有收到任何错误。 如果您将正确的会话值传输到服务器并且您收到响应。看起来服务器变得混乱了。我猜您的会话配置为根据您在响应中收到的消息在 15 分钟后超时。可能是服务器将您的会话提前超时? 我看不到 web 服务中的代码是什么样的。只是离开我可以从帖子中看到的信息。如果您没有收到 HTTP 错误响应并且从服务器获得某种形式的有效响应,则可能存在逻辑或配置问题。希望您能找到解决方案。 【参考方案1】:使用那个:来自How to save session_id as cookie value and send it to server in android
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
List<Cookie> cookies = httpClient.getCookieStore().getCookies();
for (Cookie cookie : cookies)
System.out.println("Cookie: " + cookie.toString());
if (cookie.getName().contains("PHPSESSID"))
guid = cookie.getValue();
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
【讨论】:
感谢您的回答。你是我的救命稻草 D:以上是关于通过 httpget 发送 cookie 值但没有得到所需的响应的主要内容,如果未能解决你的问题,请参考以下文章
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