线程5:同时访问0x10b883638,但修改需要独占访问

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【中文标题】线程5:同时访问0x10b883638,但修改需要独占访问【英文标题】:Thread 5: Simultaneous accesses to 0x10b883638, but modification requires exclusive access 【发布时间】:2019-10-28 09:13:48 【问题描述】:

我已经询问了this question regarding some Apple 代码并使其工作。

我有looked here,但那里的答案并不能解决我的问题 虽然我解决了这个问题,但我没有在显示的行上收到以下错误。

    private var playerItemContext = 0

override func observeValue(forKeyPath keyPath: String?, of object: Any?, change: [NSKeyValueChangeKey : Any]?, context: UnsafeMutableRawPointer?) 
    // Only handle observations for the playerItemContext
    print("jdslfhjkfdhaldfahjkflhajfldashkjfdshkjlas")
    guard context == &playerItemContext else 
        super.observeValue(forKeyPath: keyPath, of: object,change: change, context: context)
        return
    
    ...

为什么会这样,我该如何解决?

【问题讨论】:

Simultaneous accesses to 0x1c0a7f0f8, but modification requires exclusive access error on Xcode 9 beta 4的可能重复 我看过那个问题,答案很旧,不能解决我的问题@Xcoder 你在那个问题上试过这个特定的答案吗? ***.com/a/47438532/243192 是的,它对我没有任何改变。 @wvteijlingen 【参考方案1】:

试试这个代码:

    override func observeValue(forKeyPath keyPath: String?, of object: Any?, change: [NSKeyValueChangeKey : Any]?, context: UnsafeMutableRawPointer?) 

    // Only handle observations for the playerItemContext
    guard context == &P2SheetViewController.playerStatusContext else 
        super.observeValue(forKeyPath: keyPath, of: object, change: change, context: context)
        return
    

    if keyPath == #keyPath(AVPlayer.status) 
        let status: AVPlayer.Status
        if let statusNumber = change?[.newKey] as? NSNumber 
            status = AVPlayer.Status(rawValue: statusNumber.intValue)!
         else 
            status = .unknown
        

        //Switch over status value
        switch status 
        case .readyToPlay:

            break
        // Player item is ready to play
        case .failed:
            print(".UKNOWN")

            break
        // Player item failed. See error.
        case .unknown:
            print(".UKNOWN")

            break
        // Player item is not yet ready.
        @unknown default: //new jul 17
            print(".UKNOWN")

            break
        

    

希望对你有帮助

【讨论】:

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