Google+ 登录无法正常工作

Posted 2023-04-14

【中文标题】Google+ 登录无法正常工作

【英文标题】：Google+ sign in not working correctly

【发布时间】：2015-03-18 10:57:01

【问题描述】：

我一直在关注this guide 登录 google+ 并从 android 开发者页面上玩 google 游戏。但是，当我的应用程序启动时，我需要按两次 google+ 按钮才能完全登录。第一次按它时会询问我要使用哪个帐户（我的设备上有两个 google 帐户），第二次按当我按下它时，它会在我的屏幕顶部显示“欢迎”弹出窗口（带有 google play 播放器级别）。另外，当我按下注销按钮时，应用程序会再次显示登录按钮，但是当我按下登录按钮时，它不会再次登录。

TL;DR：必须按两次登录按钮才能登录，注销后登录按钮将不再起作用。

我的主要活动：

public class MainActivity extends Activity implements
        View.OnClickListener,
        GoogleApiClient.ConnectionCallbacks,
        GoogleApiClient.OnConnectionFailedListener 

    public SharedPreferences prefs;

    private static int RC_SIGN_IN = 9001;

    private GoogleApiClient mGoogleApiClient;

    private boolean mResolvingConnectionFailure = false;
    private boolean mAutoStartSignInFlow = true;
    private boolean mSignInClicked = false;

    boolean mExplicitSignOut =true; // set to true since we don't want an automatic login untill the user has done a manual login
    boolean mInSignInFlow = false; // set to true when you're in the middle of the
    // sign in flow, to know you should not attempt
    // to connect in onStart()

    // Every "clickable" item in this application (buttons, etc)
    final static int[] CLICKABLES = 
       R.id.sign_in_button,
       R.id.sign_out_button
    ;

    private boolean isSignedIn() 
        return (mGoogleApiClient != null && mGoogleApiClient.isConnected());
    

    @Override
    protected void onCreate(Bundle savedInstanceState) 
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        // set the onClickListener to every "clickable" view
        for (int id: CLICKABLES) 
            findViewById(id).setOnClickListener(this);
        

        mGoogleApiClient = new GoogleApiClient.Builder(this)
                .addConnectionCallbacks(this)
                .addOnConnectionFailedListener(this)
                .addApi(Plus.API).addScope(Plus.SCOPE_PLUS_LOGIN)
                .addApi(Games.API).addScope(Games.SCOPE_GAMES)
                        // add other APIs and scopes here as needed
                .build();

    

    @Override
    public void onConnected(Bundle bundle) 
        // Connected; change GUI accordingly

        // show sign-out button, hide the sign-in button
        findViewById(R.id.sign_in_button).setVisibility(View.GONE);
        findViewById(R.id.sign_out_button).setVisibility(View.VISIBLE);
    

    @Override
    public void onConnectionSuspended(int i) 
        mGoogleApiClient.connect();
    

    @Override
    public void onConnectionFailed(ConnectionResult connectionResult) 
        if (mResolvingConnectionFailure) 
            // Already resolving
            return;
        

        // If the sign in button was clicked or if auto sign-in is enabled,
        // launch the sign-in flow
        if (mSignInClicked || mAutoStartSignInFlow) 
            mAutoStartSignInFlow = false;
            mSignInClicked = false;
            mResolvingConnectionFailure = true;

            // Attempt to resolve the connection failure using BaseGameUtils.
            // The R.string.signin_other_error value should reference a generic
            // error string in your strings.xml file, such as "There was
            // an issue with sign in, please try again later."
            if (!BaseGameUtils.resolveConnectionFailure(this,
                    mGoogleApiClient, connectionResult,
                    RC_SIGN_IN, getString(R.string.signin_other_error))) 
                mResolvingConnectionFailure = false;
            
        
        findViewById(R.id.sign_in_button).setVisibility(View.VISIBLE);
        findViewById(R.id.sign_out_button).setVisibility(View.GONE);
    

    @Override
    protected void onStart() 
        super.onStart();
        if (!mInSignInFlow && !mExplicitSignOut) 
            // auto sign in
            mGoogleApiClient.connect();
        
    

    @Override
    public void onClick(View view) 
        if (view.getId() == R.id.sign_in_button) 
            // start the asynchronous sign in flow
            mExplicitSignOut = false;
            mSignInClicked = true;
            mGoogleApiClient.connect();
        
        else if (view.getId() == R.id.sign_out_button) 
            // sign out.
            mSignInClicked = false;
            // user explicitly signed out, so turn off auto sign in
            mExplicitSignOut = true;
            if (isSignedIn()) 
                Games.signOut(mGoogleApiClient);
                mGoogleApiClient.disconnect();
            

            // show sign-in button, hide the sign-out button
            findViewById(R.id.sign_in_button).setVisibility(View.VISIBLE);
            findViewById(R.id.sign_out_button).setVisibility(View.GONE);
        
    

我的activity_main.xml：

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools" android:layout_
    android:layout_ android:paddingLeft="@dimen/activity_horizontal_margin"
    android:paddingRight="@dimen/activity_horizontal_margin"
    android:paddingTop="@dimen/activity_vertical_margin"
    android:paddingBottom="@dimen/activity_vertical_margin" tools:context=".MainActivity">
    <!-- sign-in button -->
    <com.google.android.gms.common.SignInButton
        android:id="@+id/sign_in_button"
        android:layout_
        android:layout_ />

    <!-- sign-out button -->
    <Button
        android:id="@+id/sign_out_button"
        android:layout_
        android:layout_
        android:text="Sign Out"
        android:visibility="gone" />
</RelativeLayout>

非常感谢任何帮助！

【问题讨论】：

你可以看到这个请androidhive.info/2014/02/…

我已经看过很多例子，包括来自 google 的例子。但是，我似乎无法弄清楚我的登录/注销代码与我看到的示例有何不同。另外，使用Log.d，我可以确定在适当的时刻达到了连接和断开功能。

我已经下载了链接中的源代码并编译了它，但是点击登录按钮后没有任何反应..

【参考方案1】：

您忘记实现onActivityResult 来捕获BaseGameUtils.resolveConnectionFailure 的结果。你会想要这样的东西：

        @Override
        public void onActivityResult(int request, int response, Intent data) 
            super.onActivityResult(request, response, data);
            if (request == RC_SIGN_IN) 
                mSignInClicked = false;
                mResolvingConnectionFailure = false;
                if (response == Activity.RESULT_OK) 
                    mGoogleApiClient.connect();
                 else 
                    BaseGameUtils.showActivityResultError(this, request, response, R.string.signin_other_error);
                
            
        

您可以看到，当返回RESULT_OK 时，我们正在调用mGoogleApiClient.connect()，这与您描述的手动第二次单击具有相同的效果。