如何获得当前职位的城市名称?

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【中文标题】如何获得当前职位的城市名称?【英文标题】:how I can get the city name of my current position? 【发布时间】:2013-08-15 19:23:59 【问题描述】:

我正在使用 android studio,在一个弹出对话框中我希望用户可以获取他们的位置,但我所知道的只是获取我的纬度和经度。

这是代码

import android.app.Activity;
import android.content.Context;
import android.location.Criteria;
import android.location.Location;
import android.location.LocationListener;
import android.location.LocationManager;
import android.os.Bundle;
import android.widget.TextView;
import android.widget.Toast;

public class MainActivity extends Activity implements LocationListener 
    private TextView latituteField;
    private TextView longitudeField;
    private LocationManager locationManager;
    private String provider;


    @Override
    public void onCreate(Bundle savedInstanceState) 
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        latituteField = (TextView) findViewById(R.id.TextView02);
        longitudeField = (TextView) findViewById(R.id.TextView04);


        locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);

        Criteria criteria = new Criteria();
        provider = locationManager.getBestProvider(criteria, false);
        Location location = locationManager.getLastKnownLocation(provider);


        if (location != null) 
            System.out.println("Provider " + provider + " has been selected.");
            onLocationChanged(location);
         else 
            latituteField.setText("Location not available");
            longitudeField.setText("Location not available");
        
    


    @Override
    protected void onResume() 
        super.onResume();
        locationManager.requestLocationUpdates(provider, 400, 1, this);
    


    @Override
    protected void onPause() 
        super.onPause();
        locationManager.removeUpdates(this);
    

    @Override
    public void onLocationChanged(Location location) 
        int lat = (int) (location.getLatitude());
        int lng = (int) (location.getLongitude());
        latituteField.setText(String.valueOf(lat));
        longitudeField.setText(String.valueOf(lng));
    

    @Override
    public void onStatusChanged(String provider, int status, Bundle extras) 


    

    @Override
    public void onProviderEnabled(String provider) 
        Toast.makeText(this, "Enabled new provider " + provider,
                Toast.LENGTH_SHORT).show();

    

    @Override
    public void onProviderDisabled(String provider) 
        Toast.makeText(this, "Disabled provider " + provider,
                Toast.LENGTH_SHORT).show();
    
 

在 MainActivity。你能帮帮我吗?

我已经在清单中添加了这个

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_MOCK_LOCATION"/>

但它仍然显示“位置不可用”。


【问题讨论】:

你的名字是指地址? 是的,我指的是城市:例如。佛罗伦萨 【参考方案1】:

您需要 GeoCoder 类从给定的经纬度获取 Address。尝试以下方法:

Geocoder geoCoder = new Geocoder(this, Locale.getDefault()); //it is Geocoder
StringBuilder builder = new StringBuilder();
try 
    List<Address> address = geoCoder.getFromLocation(latitude, longitude, 1);
    int maxLines = address.get(0).getMaxAddressLineIndex();
    for (int i=0; i<maxLines; i++) 
    String addressStr = address.get(0).getAddressLine(i);
    builder.append(addressStr);
    builder.append(" ");
    

String fnialAddress = builder.toString(); //This is the complete address.
 catch (IOException e) 
  catch (NullPointerException e) 

下面的代码应该适合您:(检查有关您的代码的内联 cmets)

import java.io.IOException;
import java.util.List;
import java.util.Locale;

import android.app.Activity;
import android.content.Context;
import android.location.Address;
import android.location.Criteria;
import android.location.Geocoder;
import android.location.Location;
import android.location.LocationListener;
import android.location.LocationManager;
import android.os.Bundle;
import android.widget.TextView;
import android.widget.Toast;

public class MainActivity extends Activity implements LocationListener 
private TextView latituteField;
private TextView longitudeField;
private TextView addressField; //Add a new TextView to your activity_main to display the address
private LocationManager locationManager;
private String provider;


@Override
public void onCreate(Bundle savedInstanceState) 
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    latituteField = (TextView) findViewById(R.id.TextView02);
    longitudeField = (TextView) findViewById(R.id.TextView04);
    addressField = (TextView) findViewById(R.id.TextView05); //Make sure you add this to activity_main


    locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);

    Criteria criteria = new Criteria();
    provider = locationManager.getBestProvider(criteria, false);
    Location location = locationManager.getLastKnownLocation(provider);


    if (location != null) 
        System.out.println("Provider " + provider + " has been selected.");
        onLocationChanged(location);
     else 
        latituteField.setText("Location not available");
        longitudeField.setText("Location not available");
    



@Override
protected void onResume() 
    super.onResume();
    locationManager.requestLocationUpdates(provider, 400, 1, this);



@Override
protected void onPause() 
    super.onPause();
    locationManager.removeUpdates(this);


@Override
public void onLocationChanged(Location location) 
    //You had this as int. It is advised to have Lat/Loing as double.
    double lat = location.getLatitude();
    double lng = location.getLongitude();

    Geocoder geoCoder = new Geocoder(this, Locale.getDefault());
    StringBuilder builder = new StringBuilder();
    try 
        List<Address> address = geoCoder.getFromLocation(lat, lng, 1);
        int maxLines = address.get(0).getMaxAddressLineIndex();
        for (int i=0; i<maxLines; i++) 
            String addressStr = address.get(0).getAddressLine(i);
            builder.append(addressStr);
            builder.append(" ");
        

        String fnialAddress = builder.toString(); //This is the complete address.

        latituteField.setText(String.valueOf(lat));
        longitudeField.setText(String.valueOf(lng));
        addressField.setText(fnialAddress); //This will display the final address.

     catch (IOException e) 
        // Handle IOException
     catch (NullPointerException e) 
        // Handle NullPointerException
    


@Override
public void onStatusChanged(String provider, int status, Bundle extras) 




@Override
public void onProviderEnabled(String provider) 
    Toast.makeText(this, "Enabled new provider " + provider,
            Toast.LENGTH_SHORT).show();



@Override
public void onProviderDisabled(String provider) 
    Toast.makeText(this, "Disabled provider " + provider,
            Toast.LENGTH_SHORT).show();


【讨论】:

我不知道为什么,但它不起作用!当我在手机上启动该应用程序时,它显示“不幸的是,我的应用程序已停止”。它对你有用吗? Nono 我解决了它并且它工作但在 TextView02、TextView04 和 TextView05 中显示“位置不可用” 你是在设备还是模拟器上使用它? 我在手机上试试 System.err: java.io.IOException: 服务不可用【参考方案2】:

您需要在 AsyncTask 中(或在与 UI 线程不同的 ThreadGroup 中的线程中)执行 Geocoder!

public void getCityName(final Location location, final OnGeocoderFinishedListener listener) 
   new AsyncTask<Void, Integer, List<Address>>() 
      @Override
      protected List<Address> doInBackground(Void... arg0) 
         Geocoder coder = new Geocoder(getContext(), Locale.ENGLISH);
         List<Address> results = null;
         try 
            results = coder.getFromLocation(location.getLatitude(), location.getLongitude(), 1);
          catch (IOException e) 
            // nothing
         
         return results;
      
        
      @Override
      protected void onPostExecute(List<Address> results) 
         if (results != null && listener != null) 
            listener.onFinished(results);
         
      
   .execute();

有了这个抽象的监听器

public abstract class OnGeocoderFinishedListener 
   public abstract void onFinished(List<Address> results);

现在像这样调用方法:

getCityName(location, new OnGeocoderFinishedListener() 
   @Override
   public void onFinished(List<Address> results) 
      // do something with the result
   
);

希望这会对你们中的一些人有所帮助!

【讨论】:

【参考方案3】:

您可以使用 google api 获取当前位置地址。看看我在这篇文章中的回答去获取你的城市吧。

How to get city name from latitude and longitude coordinates in Google Maps?

【讨论】:

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