我如何将其设为 UDF

Posted 2023-04-13

【中文标题】我如何将其设为 UDF

【英文标题】：How would I make this a UDF

【发布时间】：2014-08-26 15:06:14

【问题描述】：

问题：如何从以下工作代码制作 UDF。

declare @currentweek as date
declare @1stweek as date
declare @2ndweek as date
declare @3rdweek as date
declare @4thweek as date
declare @5thweek as date

set @currentweek= dateadd(dd,0,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @1stweek= dateadd(dd,7,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @2ndweek= dateadd(dd,14,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @3rdweek= dateadd(dd,21,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @4thweek= dateadd(dd,28,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @5thweek= dateadd(dd,35,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))

select


case 
    when ([1] >= @currentweek and [1]<@1stweek)and ([2] >= @currentweek and [2]<@1stweek) and ([3] >= @currentweek and [3]<@1stweek)then 'RAP'
    when ([2] >= @currentweek and [2]<@1stweek)and ([3] >= @currentweek and [3]<@1stweek) then 'RA'
    when ([1] >= @currentweek and [1]<@1stweek)and ([3] >= @currentweek and [3]<@1stweek) then 'AP'
    when [3] >= @currentweek and [3]<@1stweek then 'A'
    when ([1] >= @currentweek and [1]<@1stweek)and ([2] >= @currentweek and [2]<@1stweek) then 'RP'
    when [2] >= @currentweek and [2]<@1stweek then 'R' 
    when [1] >= @currentweek and [1]<@1stweek then 'P' 

    else null 
end as [current week]
,case 
    when ([1] >= @1stweek and [1]<@2ndweek)and ([2] >= @1stweek and [2]<@2ndweek) and ([3] >= @1stweek and [3]<@2ndweek)then 'RAP'
    when ([2] >= @1stweek and [2]<@2ndweek)and ([3] >= @1stweek and [3]<@2ndweek) then 'RA'
    when ([1] >= @1stweek and [1]<@2ndweek)and ([3] >= @1stweek and [3]<@2ndweek) then 'AP'
    when [3] >= @1stweek and [3]<@2ndweek then 'A'
    when (([1] >= @1stweek and [1]<@2ndweek)and ([2] >= @1stweek and [2]<@2ndweek)) then 'RP'
    when [2] >=@1stweek and [2] < @2ndweek then 'R'
    when [1] >=@1stweek and [1] < @2ndweek then 'P'
    else null
end as [Next week Week]

我曾尝试研究CREATE Function 命令：

我想出了

CREATE FUNCTION testudf()
returns table
as
begin

    Inserted the code

End
Go

然而这并没有奏效。有什么想法吗？

编辑：在退货旁边添加了单词表。

消息 102，级别 15，状态 31，过程 RollingDateRAP，第 81 行 'BEGIN' 附近的语法不正确。

【问题讨论】：

没用 - 怎么样？你收到错误了吗？如果是这样，请发布完整且准确的错误消息！如果没有 - 它以什么方式不起作用？

看起来您只是在“returns”之后缺少“TABLE”这个词

Msg 444，级别 16，状态 2，过程 RollingDateRAP，第 20 行，函数中包含的 Select 语句无法将数据返回到客户端。消息 455，级别 16，状态 2，过程 RollingDateRAP，第 20 行函数中包含的最后一条语句必须是返回语句。

@tab：看起来这样将错误减少到只有一个 Msg 102、Level 15、State 31、Procedure testudf、Line 81 'BEGIN'附近的语法错误。

是 [1]、[2] 等.. 占位符吗？如果假设它们代表数字，那么您应该将数值与日期进行比较。

【参考方案1】：

啊，试试这个：

CREATE FUNCTION testudf()
returns @tblOut  TABLE (
[current week] varchar(31)
,[Next week Week] varchar(31)
)
as
begin



   declare @currentweek as date
declare @1stweek as date
declare @2ndweek as date
declare @3rdweek as date
declare @4thweek as date
declare @5thweek as date

set @currentweek= dateadd(dd,0,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @1stweek= dateadd(dd,7,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @2ndweek= dateadd(dd,14,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @3rdweek= dateadd(dd,21,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @4thweek= dateadd(dd,28,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))
set @5thweek= dateadd(dd,35,(dateadd(DD,1-datepart(DW,GETDATE()),getdate())))

INSERT INTO @tblOut
select


case 
    when ([1] >= @currentweek and [1]<@1stweek)and ([2] >= @currentweek and [2]<@1stweek) and ([3] >= @currentweek and [3]<@1stweek)then 'RAP'
    when ([2] >= @currentweek and [2]<@1stweek)and ([3] >= @currentweek and [3]<@1stweek) then 'RA'
    when ([1] >= @currentweek and [1]<@1stweek)and ([3] >= @currentweek and [3]<@1stweek) then 'AP'
    when [3] >= @currentweek and [3]<@1stweek then 'A'
    when ([1] >= @currentweek and [1]<@1stweek)and ([2] >= @currentweek and [2]<@1stweek) then 'RP'
    when [2] >= @currentweek and [2]<@1stweek then 'R' 
    when [1] >= @currentweek and [1]<@1stweek then 'P' 

    else null 
end as [current week]
,case 
    when ([1] >= @1stweek and [1]<@2ndweek)and ([2] >= @1stweek and [2]<@2ndweek) and ([3] >= @1stweek and [3]<@2ndweek)then 'RAP'
    when ([2] >= @1stweek and [2]<@2ndweek)and ([3] >= @1stweek and [3]<@2ndweek) then 'RA'
    when ([1] >= @1stweek and [1]<@2ndweek)and ([3] >= @1stweek and [3]<@2ndweek) then 'AP'
    when [3] >= @1stweek and [3]<@2ndweek then 'A'
    when (([1] >= @1stweek and [1]<@2ndweek)and ([2] >= @1stweek and [2]<@2ndweek)) then 'RP'
    when [2] >=@1stweek and [2] < @2ndweek then 'R'
    when [1] >=@1stweek and [1] < @2ndweek then 'P'
    else null
end as [Next week Week];

RETURN;

End
Go

【讨论】：

感谢大家的帮助！我很感激