正则表达式用逗号和等号解析字符串

Posted 2023-04-13

【中文标题】正则表达式用逗号和等号解析字符串

【英文标题】：REGEX parsing string by comma and equals sign

【发布时间】：2021-09-17 19:47:55

【问题描述】：

假设我有一个带上下文的字符串变量

 Column00 = 10.02.2020, Column01 = 287, Column02 = 0, Column03 = 200000, Column04 = Оплата (287 от 10.02.2020), Column10 = 10.02.2020, Column11 = 287, Column12 = 200000, Column13 = 0, Column14 = 287~287 

我对获取这样的字符串数组非常感兴趣

"10.02.2020", "287", "0", "200000", "Оплата (287 от 10.02.2020)", "10.02.2020", "287", "200000", "0", "287~287"

是否可以通过 REGEX 实现？非常感谢您的帮助。

UPD 有时这部分Column04 = Оплата (287 от 10.02.2020) 可以是Column04 = Оплата (287 от 10.02.2020 或Column04 = Оплата 287 от 10.02.2020)。

【问题讨论】：

为什么选择正则表达式？使用String.Split method 或Regex.Split method

我忘了说有时候这部分Column04 = Оплата (287 от 10.02.2020)可以是Column04 = Оплата (287 от 10.02.2020或者Column04 = Оплата 287 от 10.02.2020)

【参考方案1】：

使用String.Split方法：

string inp = @" Column00 = 10.02.2020, Column01 = 287, Column02 = 0, Column03 = 200000, Column04 = Оплата (287 от 10.02.2020), Column10 = 10.02.2020, Column11 = 287, Column12 = 200000, Column13 = 0, Column14 = 287~287 ";
var result = string.Concat("", string.Join(", ", inp.Split(new string[]" ", "", " ", "", ", ", " = ", StringSplitOptions.RemoveEmptyEntries).Where(x => !x.StartsWith("Column"))), "");

使用Regex.Split方法：

var result1 = String.Join("", Regex.Split(inp, @"Column\d1,.=."));