JPA多对多关系：无法插入生成的表

Posted 2023-04-12

【中文标题】JPA多对多关系：无法插入生成的表

【英文标题】：JPA many to many relation: unable to insert into generated table

【发布时间】：2020-11-17 16:07:38

【问题描述】：

我有 2 个实体“Entre”和“Emplacement”：

@Entity
@Table(name = "ENTREE")
public class Entree 

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ID_ENTREE", updatable = false, nullable = false)
private long idEntree;

@Column(name = "NUM_DECLARATION", insertable=true, updatable=true, nullable=true)
private String numDeclaration;


@Column(name = "DATE_ENTREE", insertable=true, updatable=true, nullable=true)
private String dateEntree;

@Column(name = "TYPE_ENTREE",  insertable=true, updatable=true, nullable=true)
private String typeEntree;

@Column(name = "NOM_ARTICLE",  insertable=true, updatable=true, nullable=true)
private String nomArticle;

@Column(name = "TYPE_ARTICLE",  insertable=true, updatable=true, nullable=true)
private String typeArticle;

@Column(name = "QUANTITE_ENTREE",  insertable=true, updatable=true, nullable=true)
private int quantiteEntree;

@ManyToOne
@JoinColumn(name="idDossier", nullable=false)
private Dossier dossier;

 @ManyToMany( fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
 @JoinTable(name = "entree_emplacement",
 joinColumns = 
         @JoinColumn(name = "id_entree", referencedColumnName = "id_entree",
                 nullable = false, updatable = false),
 inverseJoinColumns = 
         @JoinColumn(name = "id_emplacement", referencedColumnName = "id_emplacement",
                 nullable = false, updatable = false))
 private Set<Emplacement> emplacement = new HashSet<>();

public Entree() 
    super();


public Entree( String numDeclaration, String dateEntree, String typeEntree, String nomArticle, String typeArticle, int quantiteEntree,  boolean isDone) 
    super();
    this.numDeclaration = numDeclaration;
    this.dateEntree = dateEntree;
    this.typeEntree = typeEntree;
    this.nomArticle = nomArticle;
    this.typeArticle = typeArticle;
    this.quantiteEntree = quantiteEntree;   
    


public long getIdEntree() 
    return idEntree;


public void setIdEntree(long idEntree) 
    this.idEntree = idEntree;



public String getNumDeclaration() 
    return numDeclaration;


public void setNumDeclaration(String numDeclaration) 
    this.numDeclaration = numDeclaration;



public String getDateEntree() 
    return dateEntree;


public void setDateEntree(String dateEntree) 
    this.dateEntree = dateEntree;


public String getTypeEntree() 
    return typeEntree;


public void setTypeEntree(String typeEntree) 
    this.typeEntree = typeEntree;


public String getNomArticle() 
    return nomArticle;


public void setNomArticle(String nomArticle) 
    this.nomArticle = nomArticle;


public String getTypeArticle() 
    return typeArticle;


public void setTypeArticle(String typeArticle) 
    this.typeArticle = typeArticle;


public int getQuantiteEntree() 
    return quantiteEntree;


public void setQuantiteEntree(int quantiteEntree) 
    this.quantiteEntree = quantiteEntree;



public Dossier getDossier() 
    return dossier;

public void setDossier(Dossier dossier) 
    this.dossier = dossier;


 public Set<Emplacement> getEmplacements() 
        return emplacement;
    
 
 public void addEmplacement(Emplacement emplacement) 
        this.emplacement.add(emplacement);
        emplacement.getEntrees().add(this);
    
 
    public void removeEmplacement(Emplacement emplacement) 
        this.emplacement.remove(emplacement);
        emplacement.getEntrees().remove(this);
    

这里是第二个实体：

@Entity
@Table(name = "EMPLACEMENT")
public class Emplacement 

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ID_EMPLACEMENT", updatable = false, nullable = false)
private long idEmplacement;

@Column(name = "NUM_EMPLACEMENT",  insertable=true, updatable=true, nullable=false)
private String numEmplacement;

@ManyToMany(mappedBy = "emplacement", fetch = FetchType.LAZY, cascade = CascadeType.ALL)
private Set<Entree> entree = new HashSet<>();
    

public Emplacement() 




public Emplacement( String numEmplacement) 
    this.numEmplacement = numEmplacement;       

 
public long getIdEmplacement() 
    return idEmplacement;


public void setIdEmplacement(long idEmplacement) 
    this.idEmplacement = idEmplacement;


public String getNumEmplacement() 
    return numEmplacement;


public void setNumEmplacement(String numEmplacement) 
    this.numEmplacement = numEmplacement;



public Set<Entree> getEntrees() 
    return entree;

这是我的插入代码：

@PostMapping("/ajouterEntree")
public ResponseEntity<String> addEntree(@Valid Entree entree, BindingResult result,ModelMap modelMap, @RequestParam(name = "numDossier") String numDossier, @RequestParam(name = "emplacement") String liste_emplacements) 

Emplacement e = new Emplacement(liste_emplacements);
                
                
                entree.getEmplacements().add(e);
                
                entreeService.saveEntree(entree);
                
                return new ResponseEntity<String>("ok" + result, HttpStatus.OK);
            
      

我可以将数据插入到 Entree 和 Emplacement 表中，但是生成的第三个名为 entree-emplacement 的表是空的。

那么如何在@ManyToMany 关系中将数据插入到生成的表中？ 谢谢

【参考方案1】：

好的，解决了。这是我的代码：

if(!liste_emplacements.equals(""))
            
                List<String> list = new ArrayList<String>(Arrays.asList(liste_emplacements.split(",")));
                Emplacement[] emp = new Emplacement[list.size()];
                for (int i=0; i<list.size() ;i++)
                 
                     emp[i] = new Emplacement(Long.parseLong(list.get(i)));
                     entree.getEmplacements().add(emp[i]);
                     emp[i].getEntrees().add(entree);

                 
            
            
            entreeService.saveEntree(entree);
            return new ResponseEntity<String>("ok" + result, HttpStatus.OK);