如何检查 3 个列表之间的内容？

Posted 2023-04-12

【中文标题】如何检查 3 个列表之间的内容？

【英文标题】：How can I check things between 3 lists?

【发布时间】：2021-02-24 14:55:17

【问题描述】：

我需要一些关于我的游戏代码的帮助。这是一个关于制作菜肴和送货的游戏。您需要捕获一些在地下生成的成分，当您捕获它们时，它们会进入您的库存。

有 3 种类型的食谱，有 1、2 和 3 种成分。此外，不需要在您的库存中按顺序排列成分即可完成配方，它应该只是验证您是否拥有正确的物品。如果您有 3 种成分，则应在具有 3 种成分的食谱列表中验证是否有这些元素。

成分有名称和ID。

public abstract class IIngredient : IItem 
    public string ingredientName;
    public int ingredientId;

菜谱是一个IIngredient列表，菜谱有一个名字：

public abstract class IRecipe 
    public List<IIngredient> ingredients;
    public string recipe_name;

还有库存

public abstract class IInventory

    public List<IIngredient> ingredient_inventory; 
    public abstract void AddIngredient(IIngredient ingredient);

玩家库存：

public class PlayerInventory : IInventory


    public PlayerInventory()
    
        this.ingredient_inventory = new List<IIngredient>();
    

    public override void AddIngredient(IIngredient ingredient)
    
        ingredient_inventory.Add(ingredient);
    

当我交付物品时，我想检查我的库存中有多少物品，以了解我应该比较哪些食谱，然后尝试将我的物品与所有成分相同的食谱进行匹配.如果有任何食谱匹配，我想知道它是谁。

我正在使用此代码，但它不起作用：

player_inventory_ingredients_id = new List<int>();
player_inventory_ingredients_name = new List<string>();

   public override void CheckRecipe(PlayerInventory playerInventory) 
    

        foreach (IIngredient item_ingredient in playerInventory.ingredient_inventory)
        
            player_inventory_ingredients_name.Add(item_ingredient.ingredientName);
            Debug.Log("You have " + item_ingredient.ingredientName); 
        

        List<IRecipe> recipes_item_amount = recipes.FindAll
                      (i => i.ingredients.Count == playerInventory.ingredient_inventory.Count);



        foreach (IRecipe recipe_name in recipes_item_amount)
        
            Debug.Log("Possible recipes are " + recipe_name.recipe_name);

            List<string> recipe_temp = new List<string>();
            IEnumerable<string> test_the_names = player_inventory_ingredients_name.Except(recipe_temp);

            foreach (IIngredient ingredients in recipe_name.ingredients)
            
                Debug.Log(recipe_name + " ingredient is: " + ingredients);

                recipe_temp.Add(ingredients.ingredientName);
            
            

最后一个代码块，我尝试验证并检查是否有 itens，但没有显示任何结果。我什至不知道我写的代码是否有意义嘿嘿

【问题讨论】：

最后一个代码块，我尝试验证并检查是否有 itens，但没有显示任何结果。我什至不知道我写的代码是否有意义嘿嘿

那么你需要三个嵌套的for循环1）用户2）配方名称3）成分

@GertArnold 成功了！谢谢！

@jdweng 你介意写吗？

球员名单在哪里。我看不出你是从哪里得到玩家名字的？

【参考方案1】：

也许是这样的？

for (int i = 0; i < recipes_item_amount.Count; i++)

    int item_ok=0;

    for (int f = 0; f < recipes_item_amount[i].ingredients.Count; f++)
    
        if (item_ok == recipes_item_amount[i].ingredients.Count)
        
            Debug.Log(recipes_item_amount[i].recipe_name);
        

        for (int v = 0; v < playerInventory.ingredient_inventory.Count; v++)
        
            if (playerInventory.ingredient_inventory[v].ingredientName == recipes_item_amount[i].ingredients[f].ingredientName)
            
                Debug.Log("This item matchs");
                item_ok++;
                break;
            
            else 
            
                Debug.Log("This item doesn't match");
            
        
    

但我没有得到配方名称，调试只是显示：

Debug.log

【讨论】：

是的。但是您只需要找到一个匹配项。所以在你进入最后一个 for 循环之前，你有一个变量：Boolean found = false。然后，当您获得匹配项时，您设置 true 并退出最后一个 for 循环。仅当 found == false 时才会出现“不匹配”。

发布另一个答案>>>>

【参考方案2】：

这有意义吗？它没有显示正确的答案:(

bool found = false;

for (int i = 0; i < recipes_item_amount.Count; i++)
           

    if (!found)
    
        Debug.Log(recipes_item_amount[i].recipe_name);
    

    for (int f = 0; f < recipes_item_amount[i].ingredients.Count; f++)
              
        for (int v = 0; v < playerInventory.ingredient_inventory.Count; v++)
        
            if (playerInventory.ingredient_inventory[v].ingredientName == recipes_item_amount[i].ingredients[f].ingredientName)
            
                Debug.Log("This item matchs : " + recipes_item_amount[i].ingredients[f].ingredientName);
                found = true;
                break;
            
            else 
            
                Debug.Log("This item doesn't match: " + recipes_item_amount[i].ingredients[f].ingredientName);
            
        
    

---

我移动了代码。

for (int i = 0; i < recipes_item_amount.Count; i++)


    for (int f = 0; f < recipes_item_amount[i].ingredients.Count; f++)
    
        bool found = false;
        for (int v = 0; v < playerInventory.ingredient_inventory.Count; v++)
        
            if (playerInventory.ingredient_inventory[v].ingredientName == recipes_item_amount[i].ingredients[f].ingredientName)
            
                Debug.Log("This item matchs : " + recipes_item_amount[i].ingredients[f].ingredientName);
                found = true;
                break;
            
            else
            
                Debug.Log("This item doesn't match: " + recipes_item_amount[i].ingredients[f].ingredientName);
            
        
        if (!found)
        
            Debug.Log(recipes_item_amount[i].recipe_name);
        
    

【讨论】：

非常感谢！！！当我在食谱中有一个项目时它可以工作，但是有 2 或 3 个项目的食谱它不起作用

可能是你缺少成分！

【参考方案3】：

我终于成功了，非常感谢@jdweng 的帮助！

for (int i = 0; i < recipes_item_amount.Count; i++)

    int have_item = 0;

    for (int f = 0; f < recipes_item_amount[i].ingredients.Count; f++)
    
        for (int v = 0; v < playerInventory.ingredient_inventory.Count; v++)
        
            if (playerInventory.ingredient_inventory[v].ingredientName == recipes_item_amount[i].ingredients[f].ingredientName)
            
                Debug.Log("This item matchs : " + recipes_item_amount[i].ingredients[f].ingredientName);
                have_item++;
                Debug.Log(have_item);
                break;
            
            else
            
                Debug.Log("This item doesn't match: " + recipes_item_amount[i].ingredients[f].ingredientName);
            
        
        if (have_item == playerInventory.ingredient_inventory.Count)
        
            Debug.Log(recipes_item_amount[i].recipe_name);
        
    

【参考方案4】：

这个怎么样：

        var ingredientIds = playerInventory.ingredient_inventory.Select(i => i.ingredientId).ToList();

        var recipiesMatchingAllTheIngredients = recipes.Where(r => r.ingredients.Count == ingredientIds.Count &&
            r.ingredients.All(i => ingredientIds.Contains(i.ingredientId)))
            .ToList();

Linq 很棒 :)