如何使用枢轴连接两个表并在一个表中组合两个字段
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【中文标题】如何使用枢轴连接两个表并在一个表中组合两个字段【英文标题】：How to Join two table using pivot with combining two field in 1 table 【发布时间】：2016-04-27 18:55:48 【问题描述】：我有两个这种格式的表
工作技能
ID_Skill Min_Job Idea_Job Max_Job
=====================================
1 0 0 1
2 0 1 1
7 1 1 1
8 1 1 1
工作_教育
Degree_Job Field_Job Min_Job Idea_Job Max_Job
===================================================
7 37 0 0 1
7 106 0 1 1
13 37 1 1 1
13 106 1 1 1
我想这样显示
Criteria 1 2 7 8 [ 7 37 ] [ 7 106 ] [13 37] [13 106]
=============================================================
Min 0 0 1 1 1 1 0 0
Ideal 0 1 1 1 0 1 1 1
Max 1 1 1 1 1 1 1 1
我如何在 pivot 中实现这一点。如果您有其他方法，请提出建议。
【问题讨论】：
你使用什么数据库？ SQL Server 2014 @SureshKoya 【参考方案1】：declare @job_skill table (id_skill int,min_job int ,ideal_job int ,max_job int)
insert into @job_skill
VAlues
( 1 , 0 , 0 , 1),
( 2 , 0 , 1 , 1),
( 7 , 1 , 1 , 1),
( 8 , 1 , 1 , 1)
declare @Job_Education table (Degree_Job int, Field_Job int, Min_Job int, Ideal_Job int, Max_Job int)
insert into @job_education
values
( 7 , 37 , 0 , 0 , 1),
( 7 , 106 , 0 , 1 , 1),
( 13 , 37 , 1 , 1 , 1),
( 13 , 106 , 1 , 1 , 1)
/*
I want to display like this
Criteria 1 2 7 8 [ 7 37 ] [ 7 106 ] [13 37] [13 106]
=============================================================
Min 0 0 1 1 1 1 0 0
Ideal 0 1 1 1 0 1 1 1
Max 1 1 1 1 1 1 1 1
*/
select *
from
(
select 1 as seq,'Min' as Criteria,cast(id_skill as char(10)) as COL, min_job jobval
from @job_skill
union
select 2,'Ideal',cast(id_skill as char(10)) as criteria,ideal_job
from @job_skill
union
select 3,'Max',cast(id_skill as char(10)) as criteria, Max_job
from @job_skill
union
select 1, 'Min','(' + rtrim(cast(degree_job as char(4))) + ' ' + rtrim(cast(field_job as char(4))) +')' , min_job
from @job_education
union
select 2, 'Ideal','(' + rtrim(cast(degree_job as char(4))) + ' ' + rtrim(cast(field_job as char(4))) +')' , ideal_job
from @job_education
union
select 3, 'Max','(' + rtrim(cast(degree_job as char(4))) + ' ' + rtrim(cast(field_job as char(4))) +')' , Max_job
from @job_education
) s
pivot (max(jobval) for col in([1],[2],[7],[8],[(7 37)],[(7 106)],[(13 37)],[(13 106)])) pvt
order by seq
【讨论】：
【参考方案2】：这就是答案。我有我想要的结果。查询是动态的。
Declare @Skill NVARCHAR(MAX),
@Degree_Field NVARCHAR(MAX),
@Experience NVARCHAR(MAX),
@query NVARCHAR(MAX)
select @Skill =
STUFF((
select SEQ
From
(
SELECT SEQ = (',' + QUOTENAME(Skill_Name) )
From
(
select Skill_Meta.Skill_Name,Min_Job, Ideal_Job, Max_Job
FROM Job_Skill
Inner Join Skill_Meta On Skill_Meta.ID_SKL = Job_Skill.ID_SKL_Job
)SKL
UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U
) SKL
GROUP By SEQ
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select @Degree_Field =
STUFF((
select SEQ
From
(
SELECT SEQ = (',' + QUOTENAME(cast(CONCAT(Degree_Job,' ', Field_Job) as varchar(10))) )
FROM Job_Education
UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U
) SKL
GROUP By SEQ
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select @Experience =
STUFF((
select SEQ
From
(
SELECT SEQ = (',' + QUOTENAME(cast(Experience_Job as varchar(10))) )
FROM Job_Experience
UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U
) SKL
GROUP By SEQ
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query =
';With
P1_Src As
(
SELECT ID_Job,Skill_Name, Val, Col
FROM Job_Skill
Inner Join Skill_Meta On Skill_Meta.ID_SKL = Job_Skill.ID_SKL_JOB
UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U
),
P1 AS
(
SELECT ID_Job,Col,'+@Skill+'
FROM P1_Src
PIVOT (MAX(Val) FOR Skill_Name IN ('+@Skill+')) AS Pa
),
P2_Src As
(
SELECT ID_Job,CONCAT(Degree_Job,'' '', Field_Job) as DegreeField, Val, Col
FROM Job_Education
UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U
),
P2 AS
(
SELECT ID_Job,Col,'+@Degree_Field+'
FROM P2_Src
PIVOT (MAX(Val) FOR DegreeField IN ('+@Degree_Field+')) AS Pb
),
P3_Src As
(
SELECT ID_Job,Experience_Job, Val, Col
FROM Job_Experience
UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U
),
P3 AS
(
SELECT ID_Job,Col,'+@Experience+'
FROM P3_Src
PIVOT (MAX(Val) FOR Experience_Job IN ('+@Experience+')) AS Pc
)
select P1.ID_Job,P1.Col,P1.'+@Skill+',P2.'+@Degree_Field+',P3.'+@Experience+'
From P1
Inner Join P2 On P1.ID_Job = P2.ID_Job and P1.Col = P2.Col
Inner Join P3 On P1.ID_Job = P3.ID_Job and P1.Col = P3.Col'
exec sp_executesql @query
【讨论】：
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