尝试在 Android Studio 上实现 RapidApi

Posted 2023-03-31

【中文标题】尝试在 Android Studio 上实现 RapidApi

【英文标题】：Trying to implement RapidApi on Android Studio

【发布时间】：2020-01-14 18:00:12

【问题描述】：

我正在尝试在 android Studio 上实现双字词典 API。 我得到的错误信息是：

I/OkHttpClient: Callback failure for call to https://twinword-twinword-bundle-v1.p.rapidapi.com/...
    java.io.IOException: Unexpected code Responseprotocol=http/1.1, code=403, message=Forbidden, url=https://twinword-twinword-bundle-v1.p.rapidapi.com/word_example/?entry=mask
        at com.example.anew.SentenceFramer$1.onResponse(SentenceFramer.java:58)
        at com.squareup.okhttp.Call$AsyncCall.execute(Call.java:177)
        at com.squareup.okhttp.internal.NamedRunnable.run(NamedRunnable.java:33)
        at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1133)
        at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:607)
        at java.lang.Thread.run(Thread.java:760)

我认为该消息是被禁止的，因为它无法访问 rapidAPI，我认为问题是我无法弄清楚项目密钥是什么，因为我在 RapidAPI 网站的任何地方都找不到它。还是问题实际上出在我的代码上？

RapidApiConnect connect = new RapidApiConnect("I put my project name here", "I dont know where to find project key");
String object_1;

String host = "twinword-twinword-bundle-v1.p.rapidapi.com";
String API_KEY = "this is the api key";

@Override
protected void onCreate(Bundle savedInstanceState) 
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_sentence_framer);

    object_1 = getIntent().getStringExtra("First Object");
    Log.d("EDMTERROR", object_1);
    OkHttpClient client = new OkHttpClient();

    Request request = new Request.Builder()
            .url("https://twinword-twinword-bundle-v1.p.rapidapi.com/word_example/?entry=mask")
            .get()
            .addHeader("x-rapidapi-host", host)
            .addHeader("x-rapidapi-key", API_KEY)
            .build();

    client.newCall(request).enqueue(new Callback() 
        @Override
        public void onFailure(Request request, IOException e) 
            Log.d("EDMTERROR", "onfailure");
            e.printStackTrace();
        

        @Override
        public void onResponse(Response response) throws IOException 
            Log.d("EDMTERROR", "masalah");

            try (ResponseBody responseBody = response.body()) 
                if (!response.isSuccessful()) 
                    Log.d("EDMTERROR", "unexpected code");
                    throw new IOException("Unexpected code " + response);
                

                Headers responseHeaders = response.headers();
                Log.d("EDMTERROR", "headers");
                for (int i = 0, size = responseHeaders.size(); i < size; i++) 

                    System.out.println(responseHeaders.name(i) + ": " + responseHeaders.value(i));
                

                System.out.println(responseBody.string());
            

这是我第一次这样做，所以我对如何解决这个问题一无所知。我试图访问的网站是https://rapidapi.com/twinword/api/word-dictionary?endpoint=53aa5089e4b0a798dbd1a61d。

请帮忙，我的最后一年项目需要这个...

【参考方案1】：

您似乎还没有在 rapidapi.com (https://rapidapi.com/twinword/api/word-dictionary/pricing) 上订阅 API

另外，我找不到您尝试使用的端点 (/word_example)，看起来正确的端点是 /example。

您可以随时通过 [e-mail] 与他们联系

【讨论】：

看来RapidAPI自己的API有问题，所以我必须创建自己的类来复制API。无论如何，非常感谢您的回复