Tonic.PHP 关于具有“/resource”和“/resource/id”URL 的

Posted 2023-03-31

【中文标题】Tonic.PHP 关于具有“/resource”和“/resource/id”URL 的

【英文标题】：Tonic.PHP on having "/resource" and "/resource/id" URL's

【发布时间】：2014-03-24 02:23:42

【问题描述】：

我正在尝试获取 URL“/videoGame”来运行“listAllVideoGames”方法和“/videoGame/#”（其中# 是一个数字）来运行“getVideoGame”方法。使用“@priority”注释更改优先级我可以同时调用两个 URL，但找不到执行我描述的方法。

/**
 * @uri /videoGame
 * @uri /videoGame/:id
 */
class VideoGame extends Resource

    protected function getDao()
        return new VideoGameDao();
    

    /**
     * @uri /videoGame
     * @json
     * @provides application/json
     * @method GET
     */
    public function listAllVideoGames()
        return new Response(Response::OK,$this->dao->getAllVideoGames());
    

    /**
     * @uri /videoGame/:id
     * @json
     * @provides application/json
     * @method GET
     */
    public function getVideoGame($id)
        $vg = $this->dao->getVideoGame($id);
        if ($vg)
            return new Response(Response::OK,$vg);
        else
            throw new NotFoundException();
        
    

【参考方案1】：

我发现这样做的唯一方法是为 GET 调用创建一种调度程序，如下所示：

/**
 * @uri /videoGame
 * @uri /videoGame/:id
 */
class VideoGame extends Resource

    protected function getDao()
        return new VideoGameDao();
    

    /**
     * @uri /videoGame/:id
     * @provides application/json
     * @method GET
     */
    public function getVideoGames($id = 0)
        if (is_numeric($id) && $id > 0)
            return $this->getVideoGame($id);
        else
            return $this->getAllVideoGames();
        
    

    private function getVideoGame($id)
        $vg = $this->dao->getVideoGame($id);
        if ($vg)
            return new Response(Response::OK,$vg);
        else
            throw new NotFoundException();
        
    

    public function getAllVideoGames()
        return new Response(Response::OK,$this->dao->getAllVideoGames());