Oracle SQL：根据变量值将一行划分到其他表中的另一行而不遣返

Posted 2023-03-27

【中文标题】Oracle SQL：根据变量值将一行划分到其他表中的另一行而不遣返

【英文标题】：Oracle SQL: Divided one row to other row in other table without repatriation depending in variable value

【发布时间】：2019-03-06 05:16:40

【问题描述】：

我有拖车桌：

客户：

name
-----
TOMMY 
LOUIE 
HUGO 
OLLIE 
DAVID 
LEWIS 
JACKSON 

员工：

name     | stage
---------+---------
OLIVER   |  1
NOAH     |  1
ALFIE    |  1
OSCAR    |  2
NOAH     |  2
OLIVER   |  2
LEO      |  2

在员工中，我有两个阶段。在每个阶段，它可以有相同的员工还是不同的员工，我想将客户划分或分配给员工有两个条件：

第一阶段的客户必须在第二阶段有不同的员工 每个员工在每个阶段必须有相同数量的客户，每个客户在每个阶段必须有 1 名员工，不能重复。

我已经使用游标完成了将结果插入不同表中的过程，但问题是它给出了错误的结果，即在阶段 1 中将客户重复给阶段 2 中的同一员工（例如 NOAH 采用相同的客户）

CREATE  PROCEDURE AUDIT_Customer   AS

CURSOR Customer_STAGE1 IS SELECT * FROM (
                select
                      s.name  Customer_name
                      ,t.name Employees_name 
                from (select name, row_number() over(order by name) as rn from Employees  WHERE stage = 1 ) t
                join (select name, row_number() over(order by name) as rn from Customer  ) s
                on mod(s.rn - 1, (select count(*) from Employees WHERE stage = 1)) = t.rn -1); 


CURSOR Customer_STAGE2 IS SELECT * FROM (
                select
                      s.name  Customer_name
                      ,t.name Employees_name 
                from (select name, row_number() over(order by name) as rn from Employees  WHERE stage = 2 ) t
                join (select name, row_number() over(order by name) as rn from Customer   ) s
                on mod(s.rn - 1, (select count(*) from Employees WHERE stage = 2)) = t.rn -1);                 


Begin 
      For y in  Customer_STAGE1 Loop

             Insert  into Customer_Employee(Customer_name,Employees_name,RECIVE_DATE,stage)
             Values  (Y.Customer_name ,Y.Employees_name,sysdate,1) ;

      End Loop ;

       For y in  Customer_STAGE2 Loop

             Insert  into Customer_Employee(Customer_name,Employees_name,RECIVE_DATE,stage)
             Values  (Y.Customer_name ,Y.Employees_name,sysdate,2) ;

      End Loop ;


   COMMIT;               
End AUDIT_Customer;

结果：

    Customer| Employees| stage
    --------+--------- +---------
    TOMMY   | OLIVER   |  1
    LOUIE   | OLIVER   |  1
    HUGO    | NOAH     |  1
    OLLIE   | NOAH     |  1
    DAVID   | ALFIE    |  1
    LEWIS   | ALFIE    |  1
    JACKSON | ALFIE    |  1
    TOMMY   | OSCAR    |  2
    LOUIE   | OSCAR    |  2
    HUGO    | NOAH     |  2
    OLLIE   | NOAH     |  2
    DAVID   | OLIVER   |  2
    LEWIS   | OLIVER   |  2
    JACKSON | LEO      |  2

我该如何解决？

【问题讨论】：

您使用的是 mysql 还是 Oracle？

使用Oracle sql

【参考方案1】：

过滤程序的第二部分 这可能会有所帮助：

(select name, row_number() over(order by name) as rn from Employees  WHERE stage = 2 and Employee.Name not in (select Employee.Name from Employee WHERE stage = 1))

【讨论】：

它不起作用..它忽略了员工在第 1 阶段和第 2 阶段的情况（例如 NOAH）。