mdx 从周期中选择数据

Posted 2023-03-25

【中文标题】mdx 从周期中选择数据

【英文标题】：mdx select data from period

【发布时间】：2016-05-26 12:47:17

【问题描述】：

对于基于 OLAP 的报告，我需要提取当年期间和上一年同期的数据。

如果今天是 2016-05-26， 然后我需要这些日期：2016-01-01 - 2016-05-26 和 2015-01-01 - 2015-05-26

 SELECT NON EMPTY 
     [Measures].[Sell In Return]  ON COLUMNS, 

NON EMPTY  (

[Date].[Date].[Date].ALLMEMBERS * 
[Product].[Prod Name].[Prod Name].ALLMEMBERS * 
[Product].[Product].[Product].ALLMEMBERS * 
[Date].[Month Calendar].[Month Calendar].ALLMEMBERS

)  

DIMENSION PROPERTIES MEMBER_CAPTION, MEMBER_UNIQUE_NAME 
ON ROWS 

FROM 
[Table]

【问题讨论】：

您的多维数据集的日期维度中是否有未来的日期，或者是今天多维数据集中的最后一个日期？ （我们的立方体没有未来的日子，所以我知道Tail([Date].[Month Calendar].[Date]) 是今天）

你有这样[Date].[Month Calendar].[Calendar Day]的关卡吗？

是的，我有未来几天的预测

我有层次结构 date.month.week.day

【参考方案1】：

这是在多维数据集中查找 Today 的开始。我已将“度量”移至切片器并将“今天”移至列：

WITH 
  MEMBER [Measures].[Key for Today] AS 
    Format
    (
      Now()
     ,'yyyyMMdd'
    ) 
  MEMBER [Measures].[Today string] AS 
      '[Date].[Month Calendar].[Calendar Day].&[' + [Measures].[Key for Today]
    + ']' 
  SET [Today] AS 
    StrToMember
    (
      [Measures].[Today string]
     ,constrained
    ) 
  SET [TodayLstYr] AS 
    ParallelPeriod
    (
      [Date].[Date - Calendar Month].[Calendar Year]
     ,1
     ,[Today]
    ) 
  SET [ThisYear] AS 
    
        Ancestor
        (
          [Today]
         ,[Date].[Month Calendar].[Calendar Day]
        ).Item(0)
      : 
        [Today]
     
  MEMBER [Date].[Date - Calendar Month].[All].[ThisYear] AS 
    Aggregate([ThisYear]) 
  SET [LastYear] AS 
    
        Ancestor
        (
          [TodayLstYr]
         ,[Date].[Month Calendar].[Calendar Day]
        ).Item(0)
      : 
        [TodayLstYr]
     
  MEMBER [Date].[Date - Calendar Month].[All].[LastYear] AS 
    Aggregate([LastYear]) 
SELECT 
  NON EMPTY 
    
      [Today]
     ,[Date].[Date - Calendar Month].[All].[ThisYear]
     ,[Date].[Date - Calendar Month].[All].[LastYear]
     ON COLUMNS
 ,NON EMPTY 
      [Product].[Prod Name].[Prod Name].ALLMEMBERS
    * 
      [Product].[Product].[Product].ALLMEMBERS ON ROWS
FROM [Table]
WHERE 
  [Measures].[Sell In Return];

【参考方案2】：

这里还有另一种方法：

with set Today as  //today's date
filter([Date].[Month Calendar].[Date].members,
     Format([Date].[Month Calendar].currentmember.member_name, "Short Date") = 
format(now(), "Short Date"))

set MonthBegToToday as  //range of dates from current month's beginning till today
today.item(0).firstsibling : today.item(0)

set LastYearMonthBegToToday as  //range of dates from current month's beginning till today (using parallelperiod function to get the "same date last year")
PARALLELPERIOD([Date].[Month Calendar].[Year], 1, 
today.item(0).firstsibling)
:
PARALLELPERIOD([Date].[Month Calendar].[Year], 1, 
today.item(0))

member Measures.SalesMonthBegToToday as   //total sales by using SUM()
sum(MonthBegToToday, [Measures].[Sell In Return])

member Measures.SalesLastYearMonthBegToToday as 
sum(LastYearMonthBegToToday, [Measures].[Sell In Return])

【参考方案3】：

感谢您的帮助

我用成员定义了 2 个周期并将范围添加到列上

WITH 

  MEMBER [Measures].[Key for Today] AS Format   (Now() ,'yyyyMMdd'  ) 
  member [measures].[CurrentYear] as Format   (Now() ,'yyyy') 
  MEMBER [Measures].[TodayPrevYear] AS Format   (DateAdd("YYYY",-1,Now()) ,'yyyyMMdd') 
 Member [measures].[PrevYear] as Format ( dateadd("YYYY",-1,Now()) ,'yyyy') 

SELECT 
  NON EMPTY 
    
        StrToMember ( '[Date].[Date Key].[Date Key].&[' +[measures].[PrevYear]+'0101'+  ']',constrained )
    :StrToMember ( '[Date].[Date Key].[Date Key].&[' + [Measures].[TodayPrevYear]  + ']',constrained )
    ,
    StrToMember ( '[Date].[Date Key].[Date Key].&[' +[measures].[CurrentYear]+'0101'+  ']',constrained )
    :StrToMember ( '[Date].[Date Key].[Date Key].&[' + [Measures].[Key for Today]  + ']',constrained )


     ON COLUMNS
 ,NON EMPTY 

      [Product].[Product].[Product].ALLMEMBERS 
      * [Product].[SKUs].[SKU].ALLMEMBERS 

      ON ROWS
FROM [Table]
WHERE 
  [Measures].[Sell In Return];

【讨论】：

感谢 Sourav 和我的帮助，您可以“提升”我们的答案