将同一列的今天和从今天开始的总数结合起来会产生一个 sql 查询

Posted 2023-03-24

【中文标题】将同一列的今天和从今天开始的总数结合起来会产生一个 sql 查询

【英文标题】：combine today and total previous from today of that same column results in one sql query

【发布时间】：2012-10-12 06:17:26

【问题描述】：

declare @temp table (ddate datetime)

insert @temp
select DATEDIFF(d,0,CONVERT(smalldatetime,'09/30/2012')  -Number)
from master..spt_values
where type='p' and number < DatePart(d,'09/30/2012')
order by 1

DECLARE @DeptCode int =1 

--显示特定日期数据

select   ComplaintMedia_Abbri,
ddate,COUNT(ComplaintMedia)  as c
from    Complaint 
INNER JOIN @temp 
ON convert(datetime,convert(varchar(10),ComplaintDate,101),101)=convert(datetime,convert(varchar(10),ddate,101),101)        
WHERE isnull(Receivedby_Dept,Relatesto_Dept)=1     
group by ComplaintMedia_Abbri,ddate
order by ddate,ComplaintMedia_Abbri

-- 显示截至日期的特定日期数据运行总计

select   ComplaintMedia_Abbri,ddate,
    COUNT(ComplaintMedia_Abbri)  as c
    from    Complaint 

    INNER JOIN @temp 
    ON convert(datetime,convert(varchar(10),ComplaintDate,101),101)<=convert(datetime,convert(varchar(10),ddate,101),101)       

    WHERE isnull(Receivedby_Dept,Relatesto_Dept)=1     
    group by ComplaintMedia_Abbri,ddate

我想在一个 sql 查询结果中显示截至日期和今天（那天）记录的运行总计..​​...

在加入时有两个不同的条件。

预期的结果应该是这样的

编辑： 我可以通过使用这些查询并加入它们来实现此结果，但我想在一个查询而不是两个查询中完成此任务

我目前的方式可以在这里查看。抱歉这么长的问题，但我认为实际上有必要理解问题..

declare @temp table (ddate datetime)

insert @temp
select DATEDIFF(d,0,CONVERT(smalldatetime,'09/30/2012')  -Number)
from master..spt_values
where type='p' and number < DatePart(d,'09/30/2012')
order by 1

--select * from @temp

SELECT * FROM 

        (select ddate,ISNULL(L,0) AS Letter,
          ISNULL(P,0) AS Phone,
          ISNULL(E,0) AS Email,
          ISNULL(W,0) AS WEB 
          FROM 
          (
            select   ComplaintMedia_Abbri,
          ddate,COUNT(ComplaintMedia)  as c
            from    Complaint 
            INNER JOIN @temp 
            ON convert(datetime,convert(varchar(10),ComplaintDate,101),101)=convert(datetime,convert(varchar(10),ddate,101),101)        
            WHERE isnull(Receivedby_Dept,Relatesto_Dept)=1     
            group by ComplaintMedia_Abbri,ddate
    ) p 

    pivot (SUM(c) FOR ComplaintMedia_Abbri IN (E,W,L,P)) AS pvt 

    ) AS [A]

    INNER JOIN 

    (
    select ddate,ISNULL(L,0) AS LetterTot,
      ISNULL(P,0) AS PhoneTot,
      ISNULL(E,0) AS EmailTot,
      ISNULL(W,0) AS WEBTot
      FROM 
      (

    select   ComplaintMedia_Abbri,ddate,
    COUNT(ComplaintMedia_Abbri)  as c
    from    Complaint 

    INNER JOIN @temp 
    ON convert(datetime,convert(varchar(10),ComplaintDate,101),101)<=convert(datetime,convert(varchar(10),ddate,101),101)       

    WHERE isnull(Receivedby_Dept,Relatesto_Dept)=1     
    group by ComplaintMedia_Abbri,ddate
    ) p 

   pivot (SUM(c) FOR ComplaintMedia_Abbri IN (E,W,L,P)) AS pvt



    ) AS [B]

   ON A.ddate=B.ddate

   order by A.ddate

【问题讨论】：

您的数据是什么样的，预期的结果是什么？

预期列是第二部分和第三部分查询结果...

@t-clausen.dk 嘿问题更新了当前查询和当前结果，但它们来自两个不同的查询，我想将这两个合并为一个以提高此存储过程的速度。

我认为 MS Sql 服务器中没有默认功能来获取运行（累积）总数。我曾经***.com/questions/11664142/… 发布过同样的问题。在 PL/Sql 中这很容易。我猜你正在寻找同样的东西。

它已添加到 SQL Server 2012，但不是 2008。SUM(Letter) OVER (ORDER BY ddate RANGE UNBOUNDED PRECEDING) LetterTotal - 请参阅 sqlfiddle.com/#!6/1e69d/2

【参考方案1】：

我已经修改了评论中给出的 SQL Fiddle，如果你已经有了每日总数，它将给你想要的输出：

http://www.sqlfiddle.com/#!6/09168/2

DECLARE @startDate datetime
DECLARE @endDate datetime

SELECT @startDate = '2012-10-08'
SELECT @endDate = '2012-10-12'

SELECT
    DT1.ddate,
    DT1.phone,
    DT1.letter,
    DT1.email,
    DT1.web,
    SUM(DT2.phone) phoneTotal,
    SUM(DT2.letter) letterTotal,
    SUM(DT2.email) emailTotal,
    SUM(DT2.web) webTotal 
  FROM
    DailyTotals DT1
    LEFT JOIN DailyTotals DT2 ON DT1.ddate >= DT2.ddate AND DT2.ddate >= @startDate
  WHERE
    DT1.ddate <= @endDate
  GROUP BY
  DT1.ddate,
  DT1.phone,
  DT1.letter,
  DT1.email,
  DT1.web

如果您想使其成为一个语句，您需要将 DailyTotals 替换为您的子查询，该子查询为您提供每日总计。不过，我建议创建一个名为 DailyTotals 的视图并使用它。

编辑：

您可以使用 CTE 而不是临时表来生成日期范围。我已经修改了你说的完整查询，你说它可以加入 CTE 而不是 @temp。我没有办法测试它。如果这不起作用，请使用您的架构创建一个 SLQ Fiddle，我会再试一次。

WITH Dates AS
(
    SELECT CONVERT(date, MIN(ComplaintTime)) AS ddate,
    MAX(ComplaintTime) as EndDate
    FROM
      Complaints
    UNION ALL
    SELECT DATEADD(DAY, 1, ddate), EndDate
    FROM Dates
    WHERE DATEADD(DAY, 1, ddate) <= EndDate
    )

SELECT * FROM 

        (select ddate,ISNULL(L,0) AS Letter,
          ISNULL(P,0) AS Phone,
          ISNULL(E,0) AS Email,
          ISNULL(W,0) AS WEB 
          FROM 
          (
            select   ComplaintMedia_Abbri,
          ddate,COUNT(ComplaintMedia)  as c
            from    Complaint 
            INNER JOIN Dates
            ON convert(date,ComplaintDate)=ddate OPTION (MAXRECURSION 500)
            WHERE isnull(Receivedby_Dept,Relatesto_Dept)=1     
            group by ComplaintMedia_Abbri,ddate
    ) p 

    pivot (SUM(c) FOR ComplaintMedia_Abbri IN (E,W,L,P)) AS pvt 

    ) AS [A]

    INNER JOIN 

    (
    select ddate,ISNULL(L,0) AS LetterTot,
      ISNULL(P,0) AS PhoneTot,
      ISNULL(E,0) AS EmailTot,
      ISNULL(W,0) AS WEBTot
      FROM 
      (

    select   ComplaintMedia_Abbri,ddate,
    COUNT(ComplaintMedia_Abbri)  as c
    from    Complaint 

    INNER JOIN Dates OPTION (MAXRECURSION 0)
    ON CONVERT(date,ComplaintDate) <= ddate OPTION (MAXRECURSION 0)

    WHERE isnull(Receivedby_Dept,Relatesto_Dept)=1     
    group by ComplaintMedia_Abbri,ddate
    ) p 

   pivot (SUM(c) FOR ComplaintMedia_Abbri IN (E,W,L,P)) AS pvt



    ) AS [B]

   ON A.ddate=B.ddate

   order by A.ddate

【讨论】：

嘿，你做得很好，但你的解决方案的问题是它只给我运行总计，我不是在寻找运行总计，我正在寻找该列之前的日值和总和那一天……

语句终止。在语句完成之前，最大递归 100 已用完。 :(

@rahularyansharma 再次编辑。每次加入日期后，请参阅 OPTION (MAXRECURSION 0)。默认情况下，SQL Server 将 CTE 的最大递归级别设置为 100 以防止无限循环。如果您将其设置为 0，那么在您确定您的 CTE 正确之前，对循环数没有限制，这是非常危险的。我已将 1 设置为 500，将 1 设置为无限。我建议您将其设置为等于投诉表中最大日期和最小日期之间的天数。一旦你满意它可以正常工作，你可以将它们都设置为 0

如果您没有意识到 CTE 的每次递归都会将第二天添加到结果中，直到达到最大日期。因此，您的投诉表中最旧和最新记录之间的间隔超过 100 天。