如何实现两个 C 程序使用的全局 POSIX 信号量?
Posted
技术标签:
【中文标题】如何实现两个 C 程序使用的全局 POSIX 信号量?【英文标题】:How to implement global POSIX semaphore to be used by two C programs? 【发布时间】:2021-09-25 03:26:17 【问题描述】:我有两个 C 文件:a.c
(master) 和 b.c
(follower)。
我想使用信号量在 master 和 follower 之间创建同步。
根据我了解到的情况,我需要一个全局 POSIX 信号量才能完成这项工作。
如何仅使用 a.c
(master) 中的信号量在 b.c
(follower) 文件中实现这一点?
为a.c
文件(主)实现的信号量:
#include <semaphore.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <pthread.h>
#include <string.h>
sem_t x,y;
pthread_t tid;
pthread_t writerthreads[100],readerthreads[100];
int readercount = 0, writercount = 0;
void* reader(void* param)
if (writercount > 0)
sem_wait(&x);
readercount++;
if (readercount == 1)
sem_wait(&y);
sem_post(&x);
printf("%d reader is inside\n",readercount);
//read all the files in the directory
sleep(3);
sem_wait(&x);
readercount--;
if (readercount == 0)
sem_post(&y);
sem_post(&x);
printf("%d Reader is leaving\n",readercount+1);
else
printf("Nothing to view\n");
return NULL;
void* writer(void* param)
printf("Master is trying to upload\n");
sem_wait(&y);
printf("Master is uploading\n");
//create file in a directory
sem_post(&y);
writercount++;
printf("Master is leaving\n");
return NULL;
int main()
int a,i = 0,b;
sem_init(&x,0,1);
sem_init(&y,0,1);
while (1)
printf("Enter 1 to View / 2 to Upload / 3 to Exit:");
scanf("%d",&b);
if (b == 1)
pthread_create(&readerthreads[i],NULL,reader,NULL);
else if (b == 2)
pthread_create(&writerthreads[i],NULL,writer,NULL);
else
exit(0);
pthread_join(writerthreads[i],NULL);
pthread_join(readerthreads[i],NULL);
i++;
return 0;
b.c
文件中的信号量(关注者):
#include <semaphore.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <pthread.h>
#include <string.h>
sem_t x,y;
pthread_t tid;
pthread_t readerthreads[100];
int readercount = 0, writercount = 0;
void* reader(void* param)
if (writercount > 0)
sem_wait(&x);
readercount++;
if (readercount == 1)
sem_wait(&y);
sem_post(&x);
printf("%d Follower is inside\n",readercount);
//read all the files in the directory
sleep(3);
sem_wait(&x);
readercount--;
if (readercount == 0)
sem_post(&y);
sem_post(&x);
printf("%d Follower is leaving\n",readercount+1);
else
printf("Nothing to view\n");
return NULL;
int main()
int a,i = 0,b;
sem_init(&x,0,1);
sem_init(&y,0,1);
while (1)
printf("Enter 1 to View / 3 to Exit:");
scanf("%d",&b);
if (b == 1)
pthread_create(&readerthreads[i],NULL,reader,NULL);
else
exit(0);
pthread_join(readerthreads[i],NULL);
i++;
【问题讨论】:
这能回答你的问题吗? System-wide global variable / semaphore / mutex in C++/Linux? 具体而言,请参阅 man7.org/linux/man-pages/man3/sem_open.3.html,其中提到您必须使用sem_open()
来创建或打开命名信号量,并且您为信号量提供的名称必须以/
。还要确保名称是唯一的,因为系统上的其他进程也使用全局信号量,并且您不希望您的名称与其他进程发生冲突。
@NikosC.,是的,它很有用,但我可以看到它的示例实现吗?
【参考方案1】:
有两个不同的进程,你必须使用命名信号量,如下所述:
Share POSIX semaphore among multiple processes
所以你的代码可以像这样编辑
a.c
#include <semaphore.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <pthread.h>
#include <string.h>
#include <fcntl.h>
sem_t *x,*y;
pthread_t tid;
pthread_t writerthreads[100],readerthreads[100];
int readercount = 0, writercount = 0;
void* reader(void* param)
if (writercount > 0)
sem_wait(x);
readercount++;
if (readercount == 1)
sem_wait(y);
sem_post(x);
printf("%d reader is inside\n",readercount);
//read all the files in the directory
sleep(3);
sem_wait(x);
readercount--;
if (readercount == 0)
sem_post(y);
sem_post(x);
printf("%d Reader is leaving\n",readercount+1);
else
printf("Nothing to view\n");
return NULL;
void* writer(void* param)
printf("Master is trying to upload\n");
sem_wait(y);
printf("Master is uploading\n");
//create file in a directory
sem_post(y);
writercount++;
printf("Master is leaving\n");
return NULL;
int main()
int a,i = 0,b;
x = sem_open("/semaphore_x", O_CREAT | O_EXCL, S_IRWXU | S_IRWXG | S_IRWXO, 1);
y = sem_open("/semaphore_y", O_CREAT | O_EXCL, S_IRWXU | S_IRWXG | S_IRWXO, 1);
if( x == NULL || y == NULL)
printf("Unable to open named semaphores\n");
exit(-1);
while (1)
printf("Enter 1 to View / 2 to Upload / 3 to Exit:");
scanf("%d",&b);
if (b == 1)
pthread_create(&readerthreads[i],NULL,reader,NULL);
else if (b == 2)
pthread_create(&writerthreads[i],NULL,writer,NULL);
else
sem_close(x);
sem_close(y);
sem_unlink("/semaphore_x");
sem_unlink("/semaphore_y");
exit(0);
pthread_join(writerthreads[i],NULL);
pthread_join(readerthreads[i],NULL);
i++;
return 0;
和b.c
#include <semaphore.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <pthread.h>
#include <string.h>
#include <fcntl.h>
sem_t *x,*y;
pthread_t tid;
pthread_t readerthreads[100];
int readercount = 0, writercount = 0;
void* reader(void* param)
if (writercount > 0)
sem_wait(x);
readercount++;
if (readercount == 1)
sem_wait(y);
sem_post(x);
printf("%d Follower is inside\n",readercount);
//read all the files in the directory
sleep(3);
sem_wait(x);
readercount--;
if (readercount == 0)
sem_post(y);
sem_post(x);
printf("%d Follower is leaving\n",readercount+1);
else
printf("Nothing to view\n");
return NULL;
int main()
int a,i = 0,b;
x = sem_open("/semaphore_x", O_RDWR);
y = sem_open("/semaphore_y", O_RDWR);
if( x == NULL || y == NULL)
printf("Unable to open named semaphores\n");
exit(-1);
while (1)
printf("Enter 1 to View / 3 to Exit:");
scanf("%d",&b);
if (b == 1)
pthread_create(&readerthreads[i],NULL,reader,NULL);
else
sem_close(x);
sem_close(y);
exit(0);
pthread_join(readerthreads[i],NULL);
i++;
【讨论】:
我阅读了所有文档,您是否可以在我的一个文件中向我展示如何实现,因为我以前从未这样做过,而且由于我是初学者,这让我感到困惑。我想知道初始化信号量名称后如何使用。 @CheckerPecker 我编辑了答案,包括修改您的源代码。请检查b.c
中writercount
的使用,因为没有更新它的值。
非常感谢我收到这些错误:a.c:(.text+0x1a5): undefined reference to sem_open' /usr/bin/ld: a.c:(.text+0x1cc): undefined reference to
sem_open' /usr/bin/ld: a.c:(.text+0x2ad):未定义引用 sem_close' /usr/bin/ld: a.c:(.text+0x2bc): undefined reference to
sem_close' /usr/bin/ld: a.c:(.text+0x2c8): 未定义引用 sem_unlink' /usr/bin/ld: a.c:(.text+0x2d4): undefined reference to
sem_unlink' collect2: error: ld 返回 1 个退出状态
我怎样才能避免它们?
你链接线程库了吗?例如:gcc a.c -lpthread -o a.exe
以上是关于如何实现两个 C 程序使用的全局 POSIX 信号量?的主要内容,如果未能解决你的问题,请参考以下文章