带有案例类的抽象类的scala circe编码器/解码器
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【中文标题】带有案例类的抽象类的scala circe编码器/解码器【英文标题】:scala circe encoders/decoders for an abstract class with case classes 【发布时间】:2018-10-22 17:51:34 【问题描述】:我想将 FieldMapping 类的集合保存为 json 字符串 -
abstract class Field
def clazz: Class[_]
def name: String
case class StringField(name: String) extends Field
override def clazz: Class[_] = classOf[String]
case class DateField(name: String) extends Field
override def clazz: Class[_] = classOf[Date]
... 等 - 完整代码在这里: https://github.com/alexeyOnGitHub/scala-typesafe/blob/master/src/main/scala/com/example/model/Field.scala
Circe 代码:
import com.example.model.DateField, Field, FieldMapping, StringField
import io.circe.generic.semiauto.deriveDecoder, deriveEncoder
import io.circe.Decoder, Encoder
object CirceBoilerplateForConfigs
implicit val fieldDecoder: Decoder[StringField] = deriveDecoder[StringField]
implicit val fieldEncoder: Encoder[StringField] = deriveEncoder[StringField]
implicit val dateDecoder: Decoder[DateField] = deriveDecoder[DateField]
implicit val dateEncoder: Encoder[DateField] = deriveEncoder[DateField]
implicit val fooDecoder: Decoder[FieldMapping] = deriveDecoder[FieldMapping]
implicit val fooEncoder: Encoder[FieldMapping] = deriveEncoder[FieldMapping]
错误:(14, 65) 找不到类型的惰性隐式值 io.circe.generic.decoding.DerivedDecoder[com.example.model.FieldMapping] 隐式 val fooDecoder: Decoder[FieldMapping] = derivedDecoder[FieldMapping] 错误:(14, 65)
deriveDecoder 方法的参数不足:(隐式解码: shapeless.Lazy[io.circe.generic.decoding.DerivedDecoder[com.example.model.FieldMapping]])io.circe.Decoder[com.example.model.FieldMapping]。 未指定值参数解码。隐式 val fooDecoder: 解码器[FieldMapping] = 派生解码器[FieldMapping] 错误:(15, 65)
找不到类型的惰性隐式值 io.circe.generic.encoding.DerivedObjectEncoder[com.example.model.FieldMapping] 隐式 val fooEncoder: Encoder[FieldMapping] = derivedEncoder[FieldMapping] 错误:(15, 65)
没有足够的论据 方法派生编码器:(隐式编码: shapeless.Lazy[io.circe.generic.encoding.DerivedObjectEncoder[com.example.model.FieldMapping]])io.circe.ObjectEncoder[com.example.model.FieldMapping]。 未指定的值参数编码。隐式 val fooEncoder: 编码器[FieldMapping] = 派生编码器[FieldMapping]
【问题讨论】:
在您的要点中,您没有提供GUser
的代码。
FieldMapping
也没有定义。
如果我注释掉 case class GUserField
、def user
、import com.example.model...
、implicit val fooDecoder
、implicit val fooEncoder
一切都会编译。
这里是其余代码 - github.com/alexeyOnGitHub/scala-typesafe/tree/master/src/main/… 我需要 FieldMapping 集合的编码器/解码器,因为这是我想要转换为 json 字符串的内容
How to create a Minimal, Complete, and Verifiable example
【参考方案1】:
Field
应该是一个密封特征(具有抽象类或非密封特征这不起作用)。
以下代码编译:
import java.util.Date
sealed trait Field
def clazz: Class[_]
def name: String
case class StringField(name: String) extends Field
override def clazz: Class[_] = classOf[String]
case class DateField(name: String) extends Field
override def clazz: Class[_] = classOf[Date]
case class FieldMapping(fieldInConnector1: Option[Field],
fieldInConnector2: Option[Field],
selected: Boolean,
defaultValue: String)
import io.circe.generic.semiauto.deriveDecoder, deriveEncoder
import io.circe.Decoder, Encoder
object CirceBoilerplateForConfigs
implicit val stringDecoder: Decoder[StringField] = deriveDecoder[StringField]
implicit val stringEncoder: Encoder[StringField] = deriveEncoder[StringField]
implicit val dateDecoder: Decoder[DateField] = deriveDecoder[DateField]
implicit val dateEncoder: Encoder[DateField] = deriveEncoder[DateField]
implicit val fieldDecoder: Decoder[Field] = deriveDecoder[Field]
implicit val fieldEncoder: Encoder[Field] = deriveEncoder[Field]
implicit val fooDecoder: Decoder[FieldMapping] = deriveDecoder[FieldMapping]
implicit val fooEncoder: Encoder[FieldMapping] = deriveEncoder[FieldMapping]
【讨论】:
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