猫鼬查询中的嵌套选择

Posted 2023-03-22

【中文标题】猫鼬查询中的嵌套选择

【英文标题】：Nested select in Mongoose Query

【发布时间】：2020-08-11 13:22:01

【问题描述】：

我正在尝试将 SQL 转换为 Mongoose 查询，但我发现它很混乱。这是我的架构。基本上我想从今天开始获取过去 7 天的数据

var mongoose = require('mongoose');  
var RequestSchema = new mongoose.Schema(  
  pickup_person_name:String,
  dest_person_name:String,
  pickup_person_phone:String,
  dest_person_phone:String,
  tranx_status:String,
  order_status:String,
  pickup_longitude:String,
  pickup_latitude:String,
  pickup_location_name:String,
  pickup_date:Date,
  dest_longitude:String,
  dest_latitude:String,
  dest_location_name:String,
  price:String,
  item_to_deliver:String,
  rider_id:String,
  rider_name:String,
  order_number:String,
  payment_mode:String
, autoCreate: true);
mongoose.model('Request', RequestSchema);

这是我要转换为 Mongoose 的查询。

SELECT pickup_date, count(*) FROM (SELECT pickup_date as event_date FROM requests where DATE(pickup_date) >= (CURRENT_DATE -  '7 DAYS')   ) GROUP BY pickup_date ORDER BY pickup_date

I expect to have a list like 
[  event_date:27/08/2020,count:8, event_date:26/08/2020,count:9, event_date:25/08/2020,count:9]

【问题讨论】：

你能从你的数据库中发布数据吗？

我希望从数据库 [ event_date:27/08/2020,count:8, event_date:26/08/2020,count:9, event_date: 25/08/2020,count:9]

【参考方案1】：

你想使用这样的东西：

db.collection.aggregate([
  
    $match: 
      $expr: 
        $gte: [
          "$pickup_date",
          
            "$subtract": [
              "$$NOW",
              604800000
            ]
          
        ]
      
    
  ,
  
    $group: 
      _id: 
        year: 
          $year: "$pickup_date"
        ,
        month: 
          $month: "$pickup_date"
        ,
        day: 
          "$dayOfMonth": "$pickup_date"
        
      ,
      count: 
        $sum: 1
      
    
  ,
  
    $project: 
      count: 1,
      _id: 0,
      event_date: 
        "$concat": [
          
            "$toString": "$_id.day"
          ,
          "/",
          
            "$toString": "$_id.month"
          ,
          "/",
          
            "$toString": "$_id.year"
          
        ]
      
    
  
])

MongoPlayground

【讨论】：

我的 order_status 为 Done,New。对于那些日期。我想将它们添加到数组中，以便我们得到 [ event_date:27/08/2020,count:8,new:2,done:1, event_date:26/08/2020,count:9,,new :1,done:1, event_date:25/08/2020,count:9,,new:2,done:1] 我将如何将其添加到聚合中。您的查询有效

像这样：mongoplayground.net/p/b791bTa0nXG