索引匹配最大/最小分数 (Java)

Posted 2023-03-17

【中文标题】索引匹配最大/最小分数 (Java)

【英文标题】：Index match max/min scores (Java)

【发布时间】：2021-09-14 00:52:12

【问题描述】：

我正在完成一项编码作业，并且即将完成保存我的最终打印语句，该语句需要匹配名称和最大和最小分数。

我已经能够使用两个 if 语句在两个句子中获得适当的值，但是对于如何使我的索引正确以将名称与最大和最小分数对齐，我有点困惑。

除了数组和索引之外，我无法使用类或其他/不同的方法。

    //Create method StudentMax
private static int StudentMax(int[] Scores) 
    int ScoreMax = Scores[0];
    for (int i = 0; i < Scores.length; i++)
        if (Scores[i] > ScoreMax)
            ScoreMax = Scores[i];
        
    
    return ScoreMax;


//Create method StudentMin
private static int StudentMin(int[] Scores) 
    int ScoreMin = Scores[0];
    for (int i = 0; i < Scores.length; i++)
        if (Scores[i] < ScoreMin) 
            ScoreMin = Scores[i];
        
    
    return ScoreMin;


public static void main(String[] args) 

    //Call Scanner
    Scanner scan = new Scanner(System.in);

    //User Welcome
    System.out.println("Welcome to the student score sorter.");
    System.out.println("\nThis program will accept a number of student names and score values, then find the highest and lowest score.");
    System.out.println("\nThen will return the names and max/min scores.");


    //User Prompt Enter number of students
    System.out.println("\nHow many students would you like to enter: ");
    int StudentCount = scan.nextInt();

    //Create arrays: Scores, StudentFirst, StudentLast
    int [] Scores = new int[StudentCount];
    String [] StudentFirst = new String [StudentCount];
    String [] StudentLast = new String [StudentCount];


    for (int i = 0; i < Scores.length; i++) 
        System.out.println("\nStudent " + (i+1)+":");
        System.out.println("\nEnter Student's name:");
        StudentFirst[i] = scan.next();
        StudentLast[i] = scan.next();
        System.out.println("\nEnter Student's score (0-100):");
        Scores[i] = scan.nextInt();
    
    

    int max = StudentMax(Scores);
    int min = StudentMin(Scores);
    


    for (int i = 0; i < Scores.length; i++) 
        System.out.println("\n"+StudentFirst[i] + " " + StudentLast[i] +":      " + Scores[i]); 
    
    
    
    for (int i = 0; i < Scores.length; i++)  
        if (Scores [i] == max) 
            System.out.println("\n"+ StudentFirst[i] +" "+ StudentLast[i] + " has the highest score => " +max+ " and " + StudentFirst[i]+" " + StudentLast[i]+ " has the lowest => " +min);         
        
    
    
    
    
    //This is the sentence format that I need to make work, but I am struggling to understand how to align the index for names and scores. 
    //System.out.println("\n"+StudentFirst[i] +" "+ StudentLast[i]+ " has the highest score => " +max+ " and " +StudentFirst[i] +" "+ StudentLast [i]+ " has the lowest score => " +min);
    
    
     
    
    


    //Scan Close
    scan.close();
    //Close Program

【参考方案1】：

传回索引而不是值

private static int StudentMin(int[] Scores) 
    int ScoreMin = Scores[0];
    int index = 0;
    for (int i = 0; i < Scores.length; i++)
        if (Scores[i] < ScoreMin) 
            ScoreMin = Scores[i];
            index = i;
        
    
    return index;

以后就可以使用了

int index = StudentMax(Scores);

System.out.println("\n"+ StudentFirst[index] +" "+ StudentLast[index] + " has the highest score => " +Scored[index]);  

注意请注意Java命名约定

【讨论】：

我确实尝试过这个并且遇到了相同的问题，即 Min 索引的名称重复。我认为这适用于单个语句，但我需要在同一个句子中包含最大/最小值。

做int maxIndex = StudentMax(Scores); 然后int minIndex = StudentMin(Scores);

我觉得有点笨，但确实有效。非常感谢您的帮助和指导。在试图理解这一点的理论时，该方法是推动数组前进以便能够做到这一点，还是只是读取数组中的值并将其拉出？

如果您对这个答案感到满意，请不要忘记投票和/或接受它。

当然可以。非常感谢。这是我第一次访问该网站。