IOS：UIPanGesture 不适用于 ios 4.3

Posted 2023-03-16

【中文标题】IOS：UIPanGesture 不适用于 ios 4.3

【英文标题】：IOS: UIPanGesture don't work on ios 4.3

【发布时间】：2012-03-27 14:39:37

【问题描述】：

我的应用中有这个角色：

- (void) touch:(UIPanGestureRecognizer*)gesture
if (gesture.state == UIGestureRecognizerStateBegan) 
       
        if (gesture.numberOfTouches == 1) 
        
            // some code
        
        else if (gesture.numberOfTouches == 2) //some code
        else return;

else if (gesture.state == UIGestureRecognizerStateChanged)

    if (gesture.numberOfTouches == 1)

        // some code            
     
    else if (gesture.numberOfTouches == 2) // some code 

    else return;


else if (gesture.state == UIGestureRecognizerStateEnded     ||
         gesture.state == UIGestureRecognizerStateCancelled ||
         gesture.state == UIGestureRecognizerStateFailed)
   
    // some code

它在 ios 5 中可以正常工作，但在 ios 4.3 中却不行...为什么？？？

【问题讨论】：

你为哪个控件添加了这个手势？你能在你创建这个手势的地方发布代码吗？

【参考方案1】：

这是为视图添加平移手势的代码。就像您在代码中为哪个控件添加了识别器一样？

- (void)viewDidload:(BOOL)animated
    UIRotationGestureRecognizer *panRecognizer = [[UIPanGestureRecognizer alloc]initWithTarget:self action:@selector(touch:];
    [self.view addGestureRecognizer:panRecognizer];
[super viewDidLoad:animated];


- (void) touch:(UIPanGestureRecognizer*)gesture
if (gesture.state == UIGestureRecognizerStateBegan) 
       
        if (gesture.numberOfTouches == 1) 
        
            // some code
        
        else if (gesture.numberOfTouches == 2) //some code
        else return;

else if (gesture.state == UIGestureRecognizerStateChanged)

    if (gesture.numberOfTouches == 1)

        // some code            
     
    else if (gesture.numberOfTouches == 2) // some code 

    else return;


else if (gesture.state == UIGestureRecognizerStateEnded     ||
         gesture.state == UIGestureRecognizerStateCancelled ||
         gesture.state == UIGestureRecognizerStateFailed)
   
    // some code