使用带网关保护的 JSON Web 服务时 IOS 无响应

Posted 2023-03-16

【中文标题】使用带网关保护的 JSON Web 服务时 IOS 无响应

【英文标题】：No Response in IOS while using JSON Webservice with Gateway protection

【发布时间】：2014-03-14 06:03:59

【问题描述】：

下面的代码是简单的登录应用程序。我使用 Post 请求传递用户名和密码来获取详细信息。但我得到了来自网络服务的 @"" 响应。

email= emailTextField.text;
password=passwordTextfield.text;

NSString *post = [[NSString alloc] initWithFormat:@"UserName=%@&Password=%@",email,password];

NSData *postData = [post dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES];

NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];

NSURL *url = [NSURL URLWithString:@"http:Gateway/api/json"];
NSMutableURLRequest *theRequest = [NSMutableURLRequest requestWithURL:url];
[theRequest setHTTPMethod:@"POST"];
[theRequest setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[theRequest setValue:postLength forHTTPHeaderField:@"Content-Length"];
[theRequest setHTTPBody:postData];
[theRequest setHTTPBody:postData];

NSURLResponse *response;// = [[NSURLResponse alloc] init];

NSError *error;// = [[NSError alloc] init;

NSData *urlData = [NSURLConnection sendSynchronousRequest:theRequest returningResponse:&response error:&error];

NSString *str=[[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];

NSLog(@"Login response: is %@",str);

【问题讨论】：

查看NSURLConnectionDelegate 提供身份验证的方法。

我应该调用哪种方法来传递用户名和密码凭据？

NSLog(@"errot: %@",error);

这是错误 o get 操作无法完成。 (NSURLErrorDomain error -1012.)" UserInfo=0xa219390 NSErrorFailingURLKey=http://1, NSErrorFailingURLStringKey=http:///api/json/reply/Customer/?, NSUnderlyingError=0x8f3e3c0 "操作无法完成。 (kCFErrorDomainCFNetwork 错误 -1012.)"

【参考方案1】：

要向服务器提供身份验证凭据，请使用 NSURLConnection 委托

- (void)connection:(NSURLConnection *)connection didReceiveAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge 

    if ([challenge previousFailureCount] == 0) 

        NSURLCredential *credential;
        credential = [NSURLCredential credentialWithUser:userName password:password persistence:NSURLCredentialPersistenceNone];
        [[challenge sender] useCredential:credential forAuthenticationChallenge:challenge];
     else 
        [[challenge sender] cancelAuthenticationChallenge:challenge];