PHP - 解析 Facebook 帖子 JSON

Posted 2023-03-16

【中文标题】PHP - 解析 Facebook 帖子 JSON

【英文标题】：PHP - Parse Facebook Post JSON

【发布时间】：2015-06-17 05:01:44

【问题描述】：

我真的很难从 Facebook 的 Graph API 解析 JSON 数据。我正在使用file_get_contents 和json_decode 来解码对象

$json = file_get_contents($facebook_url);
$obj = json_decode($json, true);

这里是一些示例 JSON：

"data": [
  
     "place": 
        "id": "134972803193847",
        "name": "University of Southern California",
        "location": 
           "city": "Los Angeles",
           "country": "United States",
           "latitude": 34.021142052439,
           "longitude": -118.28519155575,
           "state": "CA",
           "street": "3551 Trousdale Pkwy",
           "zip": "90089"
        
     ,
     "picture": "https://fbcdn-vthumb-a.akamaihd.net/hvthumb-ak-xtf1/v/t15.0-10/xxxxxxxx",
     "id": "xxxxxxxxxx",
     "created_time": "2015-06-12T02:26:04+0000"
  ,
  
     "place": 
        "id": "74286767824",
        "name": "Los Angeles International Airport (LAX)",
        "location": 
           "city": "Los Angeles",
           "country": "United States",
           "latitude": 33.943998965589,
           "longitude": -118.402533192,
           "state": "CA",
           "street": "1 World Way",
           "zip": "90045"
        
     ,
     "picture": "https://scontent.xx.fbcdn.net/hphotos-xat1/v/t1.0-9/xxxxxxx",
     "id": "xxxxxxxx12321",
     "created_time": "2015-06-06T22:57:49+0000"
  ,
],
"paging": 
  "previous": "https://graph.facebook.com/v2.3/wfefwfwefwe",
  "next": "https://graph.facebook.com/v2.3/fweewfwef"

我尝试了各种解决方案，但echo 一直在打印“Array”

我正在尝试为每个帖子获取一些字段，例如 id、姓名、城市、国家/地区、纬度、经度、州、created_time、图片。

我试过这个，它只是打印了很多次“Array”。我知道这是一个简单的 JSON 解析/php 问题。

foreach($obj['data'] as $chunk) 
  foreach($chunk['place'] as $place)       
    $fbid   = $place['id'];
    $name = $place['name'];
    $location = $place['location'];
    $city = $location['city'];
    $country = $location['country'];
    $latitude = $location['latitude'];
    $longitude = $location['longitude'];
    $state = $location['state'];
    $tuple = array($fbid, $name, $city, $country, $latitude, $longitude, $state);
    echo $tuple . "\n";
  

【参考方案1】：

Live Demo

你的输出是一个对象。所以你不能通过[ 访问对象。

试试这个：

foreach($obj->data as $chunk) 

    $fbid   = $chunk->place->id;
    $name = $chunk->place->name;
    $location = $chunk->place->location;
    $city = $location->city;
    $country = $location->country;
    $latitude = $location->latitude;
    $longitude = $location->longitude;
    $state = $location->state;
    $tuple = array($fbid, $name, $city, $country, $latitude, $longitude, $state);
    print_r( $tuple);

输出：

Array
(
    [0] => 134972803193847
    [1] => University of Southern California
    [2] => Los Angeles
    [3] => United States
    [4] => 34.021142052439
    [5] => -118.28519155575
    [6] => CA
)
Array
(
    [0] => 74286767824
    [1] => Los Angeles International Airport (LAX)
    [2] => Los Angeles
    [3] => United States
    [4] => 33.943998965589
    [5] => -118.402533192
    [6] => CA
)

当你需要打印一个数组时，你不能使用echo。您应该使用print_r 或var_dump。

【讨论】：

这段代码给了我一个警告，说我将不正确的对象传递给 foreach 循环：/

【参考方案2】：

echo 打印 Array() 因为您将数组转换为字符串。

要以人类可读的格式打印数组，请使用print_r($obj);，然后打印第一个位置的 id，例如，使用 echo $obj['data'][0]['place']['id']; 或遍历所有位置并打印每个 id 使用

foreach ($obj['data'] as $a) 
    echo $a['place']['id'];

您可以在 PHP 手册页上找到有关 print_r 的更多信息。 http://php.net/manual/en/function.print-r.php