我在 while 循环中有一个 if 函数，但它要么忽略它，要么不中断

Posted 2023-03-15

【中文标题】我在 while 循环中有一个 if 函数，但它要么忽略它，要么不中断

【英文标题】：I have an if function in a while loop, but it either ignores it or doesn't break

【发布时间】：2019-05-14 04:21:21

【问题描述】：

while True:
    print("We have entered in the open sea, but the current is pushing us. 
            We can veer left and"
              +"\nmiss the storm, or go straight through it. Type [left] or 
              [straight] exactly as it is in the box.")
    turnChoice = input()

    if turnChoice == "left":
        food = food - 2
        time.sleep(2)
        print("You missed the storm, but you lost a little food. Your 
            current 
          food level is 5. If you let it go to zero, "
          +"\nyour health will decrease.")
        break
    if turnChoice == "straight":
        time.sleep(2)
        random.randint(1,5)
        break
    if random == 1:
        food = food - 2
        print("You tried to go through the storm, but the ship was damaged. 
            You lost some food.")
        break
    if random == 2:
        print("The ship made it through the storm without taking damage 
                somehow. 
            You did not loose any supplies or health.")
        break
    if random == 3:
        print("The ship made it through. It made a lot of noise, but no 
            supplies were lost.")
        break
    if random == 4:
        health = health - 20
        print("The ship made it through, but there was damage. While you 
            were inside the ship, a stack of barrels fell on you."
            +"\n You took some damage, receiving a concussion and fracturing 
            your arm. But you will live.")
        break
    if random == 5:
        water = water - 2
        print("You made it through the storm, but some water barrels were 
            lost to the storm. ")
        time.sleep(2)
        print("Here is your water status, don't let it get to zero: ")
        print(water)
        break

    if turnChoice not in("left", "straight"):
        print("Invalid input, please try again.")

对不起，如果它的格式不好，我是 *** 的新手。我正在为我的英语项目编写一个文字游戏。我试图在“while”循环中运行这些不同的“if”函数，但它要么忽略它们，要么只是循环整个函数。如果您选择“直接”，那么它应该拉一个随机数生成器并选择一个随机场景。如果你选择“左”，它只会减少你的食物。 “left”功能有效，但“straight”无效。另外，我试图让它在它通过“左”功能或“直”功能后打破，但由于“如果”功能，我不知道如何去做。这是在Pycharm上编程的，我相信是python 3.7.0。

【问题讨论】：

就我而言，它适用于 left 和 straight。当你选择直接时，它会选择什么？

我将尝试通过提问来提供帮助。 break 是做什么的？

【参考方案1】：

两件事：

Break 用于退出 while 循环。对于 python，if 语句将根据缩进退出。因此，要直奔并继续您的场景，您只需在直奔后移除休息时间。

random.randint 为您提供介于 1 和 5 之间的随机整数，但不会将其保存在您用于检查场景的变量中。所以你需要随机存储它。 “随机”。部分只是从您导入的随机模块中获取此功能。

当他们输入 straight 并正确分配 random 时，这将退出 if 语句而不是 while 循环。这两个更改为我修复了它。

if turnChoice == "straight":
    time.sleep(2)
    random = random.randint(1,5)
if random == 1: #rest of code

【参考方案2】：

您的 random.randint(1,5) 行没有分配给变量，因此没有任何 if 语句被触发。尝试做类似的事情

rnd = random.randint(1,5)

if rnd == 1:
    # stuff here
if rnd == 2:
    # stuff here