JavaMail 问题或错误?
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【中文标题】JavaMail 问题或错误?【英文标题】:JavaMail Question or Bug? 【发布时间】:2010-10-10 14:17:47 【问题描述】:我有一个关于 Java Mail 以及它如何与流一起使用的问题。在 Java Mail 1.4.1 中有一个MimeMessage constructor that accepts a stream。我的理解是我可以将一个流传递给这个构造函数,它会为我将它解析成一个 MimeMessage。我写了 2 个测试来证明这一点。第一个测试发送一个只包含部分多部分 MIME 消息的流。第二个测试发送包含 2 个完整的多部分 MIME 消息的流。两者都不像我预期的那样工作。第一个不抛出异常,第二个以某种方式将整个流读入单个消息。这是 Java Mail 中的错误还是我使用了错误类型的流?还是我错过了更大的东西?
有点长,测试代码如下:
import java.io.BufferedInputStream;
import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Properties;
import javax.activation.DataHandler;
import javax.activation.DataSource;
import javax.mail.BodyPart;
import javax.mail.MessagingException;
import javax.mail.Multipart;
import javax.mail.Session;
import javax.mail.internet.MimeBodyPart;
import javax.mail.internet.MimeMessage;
import javax.mail.internet.MimeMultipart;
import javax.mail.util.ByteArrayDataSource;
import junit.framework.TestCase;
public class mimeTest extends TestCase
public void testPartialMulitpartMessage() throws MessagingException, IOException
Properties props = new Properties();
Session session = Session.getInstance(props, null);
String testMsg1 = "test";
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
// Step 1 - Create first MIME message
MimeMessage mesg = new MimeMessage(session);
Multipart mp = new MimeMultipart("mixed");
//create a child part
BodyPart bodyPart = new MimeBodyPart();
bodyPart.setContent(testMsg1, "application/x-special");
bodyPart.setHeader("Content-Length", String.valueOf(testMsg1.length()));
DataSource ds = new ByteArrayDataSource(testMsg1, "application/x-special");
bodyPart.setDataHandler(new DataHandler(ds));
bodyPart.setHeader("Content-Transfer-Encoding", "8bit");
// Add the child part to the multipart
mp.addBodyPart(bodyPart);
// Put the MultiPart into the Message
mesg.setContent(mp);
// Step 2 - write to a stream
mesg.writeTo(byteArrayOutputStream);
byte bytes[] = byteArrayOutputStream.toByteArray();
ByteArrayInputStream byteArrayInputStream = new ByteArrayInputStream(bytes, 0, 10);
BufferedInputStream bufferedInputStream = new BufferedInputStream(byteArrayInputStream);
boolean thrown = false;
try
//Why does this not throw a messageexception.
MimeMessage mesg2 = new MimeMessage(session, bufferedInputStream);
catch(MessagingException me)
thrown = true;
if(!thrown)
assertTrue("Expected exception not thrown.", false);
public void testMulitpleMulitpartMessages() throws MessagingException, IOException
Properties props = new Properties();
Session session = Session.getInstance(props, null);
String testMsg1 = "test";
String testMsg2 = "test1";
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
// Step 1 - Create first MIME message
MimeMessage mesg = new MimeMessage(session);
Multipart mp = new MimeMultipart("mixed");
//create a child part
BodyPart bodyPart = new MimeBodyPart();
bodyPart.setContent(testMsg1, "application/x-special");
bodyPart.setHeader("Content-Length", String.valueOf(testMsg1.length()));
DataSource ds = new ByteArrayDataSource(testMsg1, "application/x-special");
bodyPart.setDataHandler(new DataHandler(ds));
bodyPart.setHeader("Content-Transfer-Encoding", "8bit");
// Add the child part to the multipart
mp.addBodyPart(bodyPart);
// Put the MultiPart into the Message
mesg.setContent(mp);
// Step 2 - write to a stream
mesg.writeTo(byteArrayOutputStream);
// Step 3 - Create second MIME message
MimeMessage mesg2 = new MimeMessage(session);
mp = new MimeMultipart("mixed");
//create a child part
bodyPart = new MimeBodyPart();
bodyPart.setContent(testMsg2, "application/x-special");
bodyPart.setHeader("Content-Length", String.valueOf(testMsg2.length()));
ds = new ByteArrayDataSource(testMsg2, "application/x-special");
bodyPart.setDataHandler(new DataHandler(ds));
bodyPart.setHeader("Content-Transfer-Encoding", "8bit");
// Add the child part to the multipart
mp.addBodyPart(bodyPart);
// Put the MultiPart into the Message
mesg2.setContent(mp);
// Step 4 - write to the same stream
mesg2.writeTo(byteArrayOutputStream);
// Step 6 - read the two messages back
ByteArrayInputStream byteArrayInputStream = new ByteArrayInputStream(byteArrayOutputStream.toByteArray());
BufferedInputStream bufferedInputStream = new BufferedInputStream(byteArrayInputStream);
List<MimeMessage> listMessages = new ArrayList<MimeMessage>();
while (bufferedInputStream.available() > 0)
//http://java.sun.com/products/javamail/javadocs/javax/mail/internet/MimeMessage.html#MimeMessage(javax.mail.Session,%20java.io.InputStream)
//The InputStream will be left positioned at the end of the data for the message.
//WHY does this not work? It reads the whole stream.
mesg = new MimeMessage(session, bufferedInputStream);
//output the message
listMessages.add(mesg);
assertEquals(2, listMessages.size());
assertTrue(listMessages.get(0).equals(mesg));
assertTrue(listMessages.get(1).equals(mesg2));
【问题讨论】:
【参考方案1】:JavaMail 将读取整个流,可能会缓冲它。我同意@skaffman,但我的观点是,它只是在没有 cmets 的情况下进行了高度优化,这使得它很难使用。
MimeMessage.parse(InputStream) 方法就是您要处理的。它会读取整个流,而不关闭它,除非您使用的是 SharedInputStream。如您所见,它将使 InputStream 位于最后。
MimeMessage 对解释流中的数据没有多大作用,因此我认为你“错过了更大的东西”来使用你的话。你为什么期望它解释数据?您可以只发送用于创建流的多部分消息吗?
【讨论】:
【参考方案2】:JavaMail API 是一头猪,直接使用它是一项吃力不讨好的任务,主要是因为它的行为与您期望的不一样。
我建议在它周围使用 Spring 的 API 层,它的压力要小得多。它并没有完全隐藏 JavaMail,它只是让它更易于预测和测试友好。
【讨论】:
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