从 laravel 中的过程获取结果 - 从响应中删除方括号

Posted 2023-03-14

【中文标题】从 laravel 中的过程获取结果 - 从响应中删除方括号

【英文标题】：Getting the result from procedure in laravel - removing the square brackets from the response

【发布时间】：2015-03-25 05:36:12

【问题描述】：

这是我的程序

$result = DB::select('call FastBooking(?,?)',array(Input::get('Lat'),Input::get('Long')));
return $result;

当我执行并尝试返回 $result 时，我得到了它

["AutoId":4,"DriverId":4,"distance":103.81984745881,"AutoId":3,"DriverId":3,"distance":373.5531833859,"AutoId":1,"DriverId":1,"distance":7528.7211073364,"AutoId":2,"DriverId":2,"distance":7560.0258965718]

当我尝试print_r($result); 时，我得到以下结果

Array ( [0] => stdClass Object ( [AutoId] => 4 [DriverId] => 4 [distance] => 103.81984745881 ) [1] => stdClass Object ( [AutoId] => 3 [DriverId] => 3 [distance] => 373.5531833859 ) [2] => stdClass Object ( [AutoId] => 1 [DriverId] => 1 [distance] => 7528.7211073364 ) [3] => stdClass Object ( [AutoId] => 2 [DriverId] => 2 [distance] => 7560.0258965718 ) ) Tarrif is 1 Day is 4 Time is 4Current Date is 2015-02-26 - Count : 0

我只想得到

"AutoId":4,"DriverId":4,"distance":103.81984745881,"AutoId":3,"DriverId":3,"distance":373.5531833859,"AutoId":1,"DriverId":1,"distance":7528.7211073364,"AutoId":2,"DriverId":2,"distance":7560.0258965718

这意味着我不想把方括号放在外面，

我怎么会变成这样？

（不关心解码，我只想把[]这里的方括号去掉）

【问题讨论】：

你有一个对象数组。外面的括号是解码所必需的。

不，我不直接解码这个，我有另一组对象，我将插入其中，所以我只需要删除 [] 在这种情况下

【参考方案1】：

我看不出有人想要一串损坏的 json 的任何理由，但你可以尝试做这样的事情......

str_replace (array('[', ']'), '' , $data);

我不确定您将这些数据用于什么目的，但我强烈建议您保留有效的 json。

【讨论】：

得到相同的结果 :( :["AutoId":4,"DriverId":4,"distance":103.81984745881,"AutoId":3,"DriverId":3,"distance":373.5531833859,"AutoId":1,"DriverId":1,"distance":7528.7211073364,"AutoId":2,"DriverId":2,"distance":7560.0258965718]