如何从 php 中的 URL 检索网站标题？

Posted 2023-03-14

【中文标题】如何从 php 中的 URL 检索网站标题？

【英文标题】：How to retrieve site title from URL in php?

【发布时间】：2021-08-31 06:47:01

【问题描述】：

<form method="POST" action=" route('storeCompany') ">
   <label> __('Website URL') </label>
   <input type="text" name="url" value=" old('url') " class="form-control" required="required">
   <label> __('Site Title') </label>
   <input type="text" name="name" value=" old('name') " class="form-control" required="required">
   <input type="submit" name="sbNewReviewItem" class="btn btn-block btn-primary" value=" __('Submit') ">
</form>

这是我的表单，我希望根据网站 URL 自动完成网站标题字段（它也必须是可编辑的）。

示例：我输入https://***.com/ 作为网站标题，然后网站标题必须在网站标题字段中显示Stack Overflow - Where Developers Learn, Share, & Build Careers（网站标题）。如果您知道执行此操作的方法，请告诉我。谢谢！

【问题讨论】：

希望下面的答案对你有用。

【参考方案1】：

DEMO 对于这个函数，你可以使用 url 获取标题名称。

对于这个功能，您可以使用 url 获取标题名称

---

<?php
    function page_title($url) 
        $fp = file_get_contents($url);
        if (!$fp) 
            return null;

        $res = preg_match("/<title>(.*)<\/title>/siU", $fp, $title_matches);
        if (!$res) 
            return null; 

        // Clean up title: remove EOL's and excessive whitespace.
        $title = preg_replace('/\s+/', ' ', $title_matches[1]);
        $title = trim($title);
        return $title;
    
    print page_title("https://***.com");
?>

输出：Stack Overflow - 开发人员学习、分享和建立职业生涯的地方

LARAVEL 代码

HTML 代码

---

<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.2/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.16.0/umd/popper.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.2/js/bootstrap.min.js"></script>
<link rel="stylesheet" type="text/css" href="https://cdnjs.cloudflare.com/ajax/libs/toastr.js/latest/css/toastr.min.css">
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/toastr.js/latest/js/toastr.min.js"></script>

<form method="POST" action=" route('storeCompany') "  id="websiteForm">
      csrf_field() 
    <label> __('Website URL') </label>
    <input type="text" name="url" value=" old('url') " class="form-control url"  required="required">
    <label> __('Site Title') </label>
    <input type="text" name="title" value=" old('name') " class="form-control title"/>
    <input type="submit" name="sbNewReviewItem" class="btn btn-block btn-primary clssubmit" value=" __('Submit') ">
</form>

路线代码

---

Route::post('changestatus', ['as' => 'changestatus', 'uses' => 'YourControllerName@changestatus']);
Route::post('checktitle', ['as' => 'checktitle', 'uses' => 'YourControllerName@checktitle']);

控制器代码

---

public function checktitle(Request $request)

    try 
        $data = self::page_title($request->val);   
        $arr = array("status" => 200, "msg" => 'success',"result" => $data);
     catch (\Illuminate\Database\QueryException $ex) 
        $msg = 'Something went wrong.';
        if (isset($ex->errorInfo[2])) 
            $msg = $ex->errorInfo[2];
        
        $arr = array("status" => 400, "msg" => $msg, "result" => array());
     catch (Exception $ex) 
        $msg = 'Something went wrong.';
        if (isset($ex->errorInfo[2])) 
            $msg = $ex->errorInfo[2];
        
        $arr = array("status" => 400, "msg" => $msg, "result" => array());
    
    return \Response::json($arr);


private function page_title($url) 
    $fp = file_get_contents($url);
    if (!$fp) 
        return null;
    $res = preg_match("/<title>(.*)<\/title>/siU", $fp, $title_matches);
    if (!$res) 
        return null; 
    // Clean up title: remove EOL's and excessive whitespace.
    $title = preg_replace('/\s+/', ' ', $title_matches[1]);
    $title = trim($title);
    return $title;

Ajax 代码

---

$('body').on('keyup', '.url', function (e) 
   var val= $( ".url" ).val( );
   e.preventDefault();
   $.ajax(
       url: " route('checktitle')",  // write your route path
       headers: 
       'X-CSRF-TOKEN': ' csrf_token() '
        ,
       data: val : val,
       type: 'POST',
       beforeSend: function () 
             $('.clssubmit').prop("disabled", true);
       ,
       success: function (data) 
           if (data.status == 400) 
             $('.submitspinner').html('');
             toastr.error(data.msg)
           
           if (data.status == 200) 
             $('.clssubmit').prop("disabled", false);
             $( ".title" ).val(data.result);
             toastr.success(data.msg)
           
       ,
   );
);

【讨论】：

希望这个答案对你有用！！ @Codenooober

【参考方案2】：

您可以使用Javascript通过document.title获取<title>标签的内容。然后，您可以将其推送到对应的<label> 标签。

【参考方案3】：

你会在这里得到答案 [https://www.php.net/manual/en/function.get-meta-tags.php][1]

`$tags = get_meta_tags('https://***.com/');

print_r($tags);`

【参考方案4】：

刀片模板

<!DOCTYPE html>
<html lang="en">
<head>
    <title>Bootstrap Example</title>
    <meta charset="utf-8">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.2/css/bootstrap.min.css">
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
    <script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.16.0/umd/popper.min.js"></script>
    <script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.2/js/bootstrap.min.js"></script>
</head>
<body>

    <form method="POST" action=" route('storeCompany') "  id="websiteForm">
        @csrf
        <label> __('Website URL') </label>
        <input type="text" name="url" value=" old('url') " class="form-control" required="required">
        <label> __('Site Title') </label>
        <input type="text" name="title" value=" old('name') " class="form-control name"/>
        <input type="submit" name="sbNewReviewItem" class="btn btn-block btn-primary" value=" __('Submit') ">
    </form>


        <script src="https://cdnjs.cloudflare.com/ajax/libs/axios/0.21.1/axios.min.js" integrity="sha512-bZS47S7sPOxkjU/4Bt0zrhEtWx0y0CRkhEp8IckzK+ltifIIE9EMIMTuT/mEzoIMewUINruDBIR/jJnbguonqQ==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>

        <script>
            $("#websiteForm").submit(function(e) 

                e.preventDefault();
                var bodyFormData = new FormData(this);
                var url=$(this).attr('action');
                axios.post(url,bodyFormData).then(function (response) 
                    console.log(response.data);
                    $('input[name="title"]').val(response.data.title)


                    return false;
                ).catch(function (error) 



                );


            );
        </script>
</body>
</html>

在 Laravel 方面

 if(request()->isMethod('POST'))

        $html = file_get_contents(request()->url);

       

        $xml = new DOMDocument();
        libxml_use_internal_errors(true);
        $xml->validateOnParse = true;
        $xml->loadHTML(mb_convert_encoding($html, 'HTML-ENTITIES', 'UTF-8'));


        return  [
            'title'=>$xml->getElementsByTagName('title')->item('0')->nodeValue,

        ];